Question
Download Solution PDFA signal applied to a CRO has a rising time of 0.5 μs. Its bandwidth is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept of Bandwidth and Rise Time:
The bandwidth (BW) of a signal can be estimated using the rise time (tr) with the following relationship for a typical oscilloscope or CRO:
BW ≈ 0.35 / tr
Where,
- BW = Bandwidth in Hz
- tr = Rise time in seconds
Given Data:
- Rise Time (tr) = 0.5 μs = 0.5 × 10-6 s
Calculation:
Using the formula:
BW ≈ 0.35 / tr
BW ≈ 0.35 / (0.5 × 10-6)
BW ≈ 0.7 × 106 Hz
BW ≈ 0.7 MHz
Conclusion:
Hence, the bandwidth of the signal is approximately 0.7 MHz.
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.