Question
Download Solution PDFA shunt generator delivers a load current of 450 A at 250 V. Armature resistance is 0.01 Ω and shunt field resistance is 50 Ω. Calculate the emf generated.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFAccording to the question circuit diagram of DC shunt generator can be drawn asNow, shunt field current (Ish) is
\({I_{sh}} = \frac{V}{{{R_{sh}}}} = \frac{{250}}{{50}}\)
Ish = 5 A
Now Armature current is
Ia = IL + Ish = 450 + 5
Ia = 455 A
Now generated emf in dc shunt generator on be calculated as
E = V + Ia Ra
E = 250 + 455 (0.01) = 250 + 4.55
E = 254.55 V
Last updated on May 28, 2025
-> ISRO Technician recruitment notification 2025 has been released.
-> Candidates can apply for the ISRO recruitment 2025 for Technicians from June 2.
-> A total of 64 vacancies are announced for the recruitment of Technician.
-> The selection of the candidates is based on their performance in the Written Exam and Skill Test.
-> Candidates who want a successful selection must refer to the ISRO Technician Previous Year Papers to increase their chances of selection for the Technician post.