Question
Download Solution PDFA person boarded an express train on 30th August, 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13.30 hours and reached Trivandrum at 7.30 hours on 1st September, 2015. If the distance between Ahmedabad and Trivandrum is 2268 km, the average speed of the train between the two stations was:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Total distance covered = 2268 Km
Formula used :
Average speed = total distance / total time
Calculation :
| Day | Number hours of train travel |
| 30 Aug | 10.5 hrs |
| 31 Aug | 24 hrs |
| 1 Sep | 7.5 hrs |
Total number of hours train travel = 10.5 + 24 + 7.5 = 42 hrs
So average speed = Total Distance / total time
Average speed = 2268 / 42
Average speed = 54 km/hr
Average speed = 54 × 1000 / 3600 m/s
Average speed = 15 m/s
Important Points
Average speed = total distance covered / total time
to convert Km/hr into m/s multiply by 5/18.
Last updated on Jun 18, 2025
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