Question
Download Solution PDFA manufacturing process has a large amount of waste heat available at 200°C in a location where the local environmental temperature is 20°C. Determine the COP of a Carnot refrigerator operating between these temperatures.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
COP of a Carnot Refrigerator:
\({\bf{CO}}{{\bf{P}}_{\bf{R}}} = \frac{{{{\bf{T}}_{\bf{L}}}}}{{{{\bf{T}}_{\bf{H}}} - {{\bf{T}}_{\bf{L}}}}}= \frac{{Refrigerating\;Effect}}{{Work\;Input}}\)
where TL = Lower temperature, TH = Higher temperature.
Calculation:
Given:
TL = 20°C = 293 K, TH = 200°C = 473 K.
\({\bf{CO}}{{\bf{P}}_{\bf{R}}} = \frac{{{{\bf{T}}_{\bf{L}}}}}{{{{\bf{T}}_{\bf{H}}} - {{\bf{T}}_{\bf{L}}}}}\)
\({\bf{CO}}{{\bf{P}}_{\bf{R}}} = \frac{293}{473-293}=\frac{293}{180}=1.63\)
Last updated on May 12, 2025
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