A man starts from point 'O' travels 20 km towards East to reach point 'A', turns right and travels 10 km to reach point 'B', turns right and travels 9 km to reach point ‘C’, turns right and travels 5 km to reach point 'D', turns left and travels 12 km to reach point ‘E’ and then turns right and travels 6 km to reach point 'F'.

What is the shortest distance between point 'E' and point 'B'?

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RRB ALP CBT I 30 Aug 2018 Shift 3 Official Paper
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  1. \(\sqrt{145}\)
  2. \(\sqrt{466}\)
  3. \(\sqrt{450}\)
  4. 46

Answer (Detailed Solution Below)

Option 2 : \(\sqrt{466}\)
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According to the given conditions :

1) A man starts from point 'O' travels 20 km towards East to reach point 'A'

F1 Savita Railways 27-2-23 D36

2) Then turns right and travels 10 km to reach point 'B'


F1 Savita Railways 27-2-23 D37

3) Then turns right and travels 9 km to reach point ‘C’


F1 Savita Railways 27-2-23 D38

4) Then turns right and travels 5 km to reach point 'D'


F1 Savita Railways 27-2-23 D39

5) Then turns left and travels 12 km to reach point ‘E’


F1 Savita Railways 27-2-23 D40

6) then turns right and travels 6 km to reach point 'F'


F1 Savita Railways 27-2-23 D41
Thus, according to the final arrangement, shortest distance between point 'E' and point 'B'
is calculated by pythagoras theorem :-
F1 Savita Railways 27-2-23 D21

 

So, (EB)2 = (ED + DG)2 + (AB - DC)2

⇒ (EB)2 = (12 + 9)2 + (10 - 5)2

⇒ (EB)2 = (21)2 + (5)2

⇒ (EB)2 = 441 + 25

⇒ (EB)2 = 466

EB = \(\sqrt{466}\) km. 

Hence, "\(\sqrt{466}\)" is the correct answer
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