Question
Download Solution PDFA Kaplan turbine has an outside diameter of runner and hub diameter as 4 m and 2 m, respectively. If the velocity of flow at inlet is 8 m/s, then what will be the discharge passing through the turbine?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Kaplan Turbine:
- Kaplan turbine is an Axial Flow Reaction Turbine.
- It offers High Discharge and Low Head.
- In this turbine water flow parallel to the axis of rotation of the shaft.
Discharge (Q) for a Kaplan Turbine is given by
\(Q = \frac{\pi}{4}(D_0^2 - D_h^2)V_{f1} = \frac{\pi}{4}D_0^2(1 - \frac{D_h^2}{D_o^2})V_{f1} \)
where Do = Tip Diameter, Dh = Hub Diameter,Vf1 = Flow velocity
Flow Ratio: The ratio of Velocity of Flow at the inlet (Vf1) to the velocity given \(\sqrt{2gh}\) is known as flow ratio.
Flow Ratio, \(\psi = \frac{V_{f1}}{\sqrt{2gh}}\)
where h = Head on Turbine
Calculation:
Given:
Tip Diameter, Do = 4 m, Dh = Hub Diameter, = 2 m, Vf1 = Flow velocity = 8 m/s
Discharge, \(Q = \frac{\pi}{4}(D_0^2 - D_h^2)V_{f1}\)
\(Q = \frac{\pi}{4}(4^2 - 2^2)\times 8 =75.36 ~\rm{m^3/s}\)
Last updated on May 28, 2025
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