A cylindrical bucket of diameter 42 cm and height 10 cm was full of sand. When the sand in the bucket was poured on the ground, the sand got converted into a shape of a cone. If the height of the cone was 21 cm, what was the base area of the cone?

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Kerala PSC Common Preliminary Exam (GRADUATE LEVEL) PYP 38-24
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  1. 1980 cm2
  2. 2015 cm2
  3. 1780 cm2
  4. 2036 cm2

Answer (Detailed Solution Below)

Option 1 : 1980 cm2
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Ans: (A) 1980 cm2
 
Key Points : Volume of the cylinder:
Radius of the cylinder (r) = Diameter / 2 = 42 cm / 2 = 21 cm
Height of the cylinder (h) = 10 cm
Volume of cylinder = πr²h = π * (21)² * 10 = π * 441 * 10 = 4410π cm³
Important  Points :
Volume of the cone: The volume of the sand remains the same when poured from the cylinder to the cone.
Volume of cone = (1/3)πR²H, where R is the radius of the cone's base and H is the cone's height.
Height of the cone (H) = 21 cm
Equate the volumes and solve for the base area:
4410π = (1/3)πR² * 21
4410π = 7πR²
R² = 4410π / 7π
R² = 630 cm²
The base area of the cone is πR². We already found R² to be 630. Therefore, the base area is  630π. If we use π ≈ 22/7, the base area is (22/7) * 630 = 22 * 90 = 1980 cm².
Additional Information :
Volume of Cylinder: You correctly calculated the volume of the cylinder as πr²h = π * (21)² * 10 = 4410π cm³.
Volume of Cone: The volume of the cone is (1/3)πR²H, where R is the radius of the cone's base and H is the cone's height.
Equating Volumes: You correctly equated the volumes: 4410π = (1/3)πR² * 21.
Solving for R²: Your calculation of R² is also correct: R² = 630 cm².
Base Area of the Cone: The base area of the cone is indeed πR². Since you've already found R², the base area is simply 630π cm².

 

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