Corona MCQ Quiz in தமிழ் - Objective Question with Answer for Corona - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Mar 17, 2025

பெறு Corona பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Corona MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Corona MCQ Objective Questions

Top Corona MCQ Objective Questions

Corona Question 1:

The good effect of corona on overhead lines is to -

  1. increase the line carrying capacity due to conducting ionized air envelop around the conductor
  2. increase the power factor due to corona loss
  3. reduce the radio interference from the conductor
  4. reduce the steepness of surge fronts

Answer (Detailed Solution Below)

Option 4 : reduce the steepness of surge fronts

Corona Question 1 Detailed Solution

Good Effect of Corona on Overhead Lines:

Corona discharge occurs when the electric field intensity around the conductor exceeds the dielectric strength of the surrounding air, leading to ionization of the air and formation of a visible glow or corona. Although corona discharge is generally undesirable because it results in power loss, audible noise, and radio interference, it has a beneficial effect in certain situations.

The key beneficial effect of corona on overhead lines is:

  • Reduction of the Steepness of Surge Fronts: During a lightning strike or switching operation, high-voltage surges travel along the transmission lines. These surges can have steep wavefronts which pose a significant threat to insulation and equipment. The presence of corona discharge around the conductors can help to reduce the steepness of these surge fronts. The ionized air around the conductor acts as a cushion, dissipating energy and smoothing out the sharp edges of the surges. This results in less severe surges, which are less likely to cause damage to the insulation and other components of the power system.

Therefore, the correct answer is option 4.

Corona Question 2:

At 50 Hz operating frequency a HVAC transmission has a corona loss of 1.5 kW/ph/km. What is the corona loss of the same line operating at 60 Hz._______ (in kW/ph/kM)

Answer (Detailed Solution Below) 1.7

Corona Question 2 Detailed Solution

Corona loss, Ploss α (f + 25)

\(\begin{array}{l} \Rightarrow \frac{{1.5}}{{{{\left( {{P_{loss}}} \right)}_{{{60}_{Hz}}}}}} = \frac{{\left( {50 + 25} \right)}}{{\left( {60 + 25} \right)}}\\ \Rightarrow {\left( {{P_{loss}}} \right)_{{{60}_{Hz}}}} = \frac{{\left( {85} \right)\left( {1.5} \right)}}{{75}} = 1.7\ kW/ph/kM \end{array}\)

Corona Question 3:

A 3 phase line operating at 150 kV which has conductor of 1.5 cm diameter arranged in a 4 meter delta. Assume air density factor of 1.2 and the dielectric strength of air to be \(21\frac{{kV}}{{cm}}\). Calculate the corona loss ____ \(\left( {in\ \frac{{kW}}{{kM}}/Phase} \right)\).

Answer (Detailed Solution Below) 0

Corona Question 3 Detailed Solution

\(\begin{array}{l} V = 21m\delta r\ln \frac{d}{r}\\ = 21 \times 1.2 \times 1 \times 0.75\ \ln \left( {\frac{{400}}{{0.75}}} \right) \end{array}\)

= 118.68 kV

Line to line voltage is = 205.55 kV

Since the operating voltage is 150 kV, the corona loss will be absent.

⇒ Corona loss = 0.

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