Design of Canals MCQ Quiz in मराठी - Objective Question with Answer for Design of Canals - मोफत PDF डाउनलोड करा

Last updated on Mar 9, 2025

पाईये Design of Canals उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). हे मोफत डाउनलोड करा Design of Canals एमसीक्यू क्विझ पीडीएफ आणि बँकिंग, एसएससी, रेल्वे, यूपीएससी, स्टेट पीएससी यासारख्या तुमच्या आगामी परीक्षांची तयारी करा.

Latest Design of Canals MCQ Objective Questions

Top Design of Canals MCQ Objective Questions

Design of Canals Question 1:

The Garret diagram is applicable only for channel sections having side slopes of -

  1. 2 : 1
  2. \(\frac{1}{3}\) : 1
  3. \(\frac{1}{2}\) : 1
  4. 1 : 1

Answer (Detailed Solution Below)

Option 3 : \(\frac{1}{2}\) : 1

Design of Canals Question 1 Detailed Solution

Concepts:

Garret's diagram

  • It is graphical representation of design of canal dimensions based on Kennedy theory.
  • The diagram is discharge plotted on abscissa (X-axis), and slope of the channel on the left side of ordinate (Primary Y-axis) and depth of the channel and critical velocity on the right side of the ordinate. (Secondary Y-axis).
  • Garret's diagram is applicable only for side slope of the channel of 0.5: 1.
  • The diagrams are specified for manning's coefficient (N) of 0.0225. However, these charts can be extended to any value of N using a nomogram at the top of each diagram.

Design of Canals Question 2:

Consider statements regarding Lacey's theory:

1. He considered channel section semi-elliptical.

2. He considered channel cannot be in true regime.

3. Section is tighter and deeper.

Select true statements:

  1. 1 and 3
  2. 1 and 2
  3. Only 2
  4. All of these

Answer (Detailed Solution Below)

Option 2 : 1 and 2

Design of Canals Question 2 Detailed Solution

Explanation:

Lacey followed Lindley’s hypothesis, which states that “dimensions and slope of a channel to carry a given discharge and silt load in easily erodible soil are uniquely determined by nature”.

Option 1 & 2 are correct and option 3 is incorrect.

According to Lacey:

1) He considered the channel section semi-elliptical.

2) He considered the channel cannot be in the true regime. So, the channel only can be the initial and final regime.

3)  Section is wider and shallower.

4) Silt is kept in suspension by the vertical component of eddies generated at all points of forces normal to

the wetted perimeter. So the eddies are generated from the bottom as well as the side of the channel.

Regime Channel

5) A channel is said to in regime if there is neither silting nor scouring.

According to Lacey, there may be three regime conditions:

(i) True regime;

(ii) Initial regime; and

(iii) Final regime.

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Accordingly, he proposed the following four basic equations for designing of the alluvial channels:

1. Relationship between velocity (V) and Hydraulic Mean Depth (R)

\({V^2} = \frac{2}{5}fR\)

2. Relationship between Area (A) and Velocity of flow in channel (V)

\(A{f^2} = 140\;{V^5}\)

3. Grain size (d) of silt and silt factor (f)

\(f = 1.76\;\sqrt {d\left( {\;in\;mm} \right)} \)

4. Relationship between Regime Slope (S) and discharge (Q)

\(S = \frac{{{f^{5/3}}}}{{3340{Q^{1/6}}}}\)

Design of Canals Question 3:

An alluvial river has a dominant discharge of 1600 m3/sec and a bed slope of 1 in 5000. The approximate value of the meander belt for this river would be:

  1. 0.06 km
  2. 0.6 km
  3. 6 km
  4. 60 km

Answer (Detailed Solution Below)

Option 3 : 6 km

Design of Canals Question 3 Detailed Solution

Concept:

Meander Length (ML) - The tangential distance between the crests or trough of a mender in plan view.

Meander belt width (MB) - Distance between top and bottom portion of successive crests and trough of a member in plan view.

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The value of the meander belt (MB) for the river (in m) = 150 √Q 

Calculation:

Given

Q = 1600 m3/sec

MB = 150 √Q = 150 √1600

 = 150 × 40 = 6000 m = 6 km

Design of Canals Question 4:

Coefficient of Rugosity, as defined by Lacey, is dependent on

  1. Grade of the boundary material
  2. Density of the boundary material
  3. Grade and density of the boundary material
  4. Grade, density and hydraulic mean depth of the boundary material

Answer (Detailed Solution Below)

Option 3 : Grade and density of the boundary material

Design of Canals Question 4 Detailed Solution

Concept:

Lacey proposed that rugosity coefficient is dependent on grade and density of boundary material against the idea of Kutter and Manning, who defined rugosity coefficient to be dependent solely on surface roughness.

He also established relationship between rugosity coefficient (N) and silt factor (f) as below:

N α f1/4 and f = 1.76 \(\sqrt d\)

Where, d is the diameter average silt particle in ‘mm’.

However, Lacey considered the rugosity coefficient for ‘very good’ condition appropriate to the grain size and considered a value of 0.0225 for most of the conditions.

Design of Canals Question 5:

Which of these is correct about Lacey's theory?

  1. Wetted Perimeter is proportional to Q1/6
  2. Bed Slope is proportional to Q-1/6
  3. Hydraulic Radius is proportional to Q-1/2
  4. Velocity is proportional to Q1/2

Answer (Detailed Solution Below)

Option 2 : Bed Slope is proportional to Q-1/6

Design of Canals Question 5 Detailed Solution

Explanation:

From the below relations:

  1. Velocity is proportional to Q1/6
  2. Bed Slope is proportional to Q-1/6
  3. Wetted Perimeter is proportional to Q1/2


​So, the correct answer is option 2.

According to Lacey, the design formulas for canal design is as follows:

1) silt factor ⇒ \(\rm{f = 1.76\sqrt {{d_{mm}}}}\)

2) velocity of flow ⇒ \(V = {\left[ {\frac{{Q{f^2}}}{{140}}} \right]^{\frac{1}{6}}}\)

3) bed slope ⇒ \(S = \frac{{{f^{\frac{5}{3}}}}}{{3340 \times {Q^{\frac{1}{6}}}}}\)

4) wetted perimeter ⇒ \(P = 4.75\sqrt Q\)

5) hydraulic mean depth ⇒ \(R = \frac{{5{V^2}}}{{2f}}\)

6) Lacey's Normal Regimed depth ⇒ \(R_r' = 0.473{\left[ {\frac{{Q}}{{f}}} \right]^{\frac{1}{3}}}\)

7) Lacey's Normal depth ⇒ \(R_r' = 1.35{\left[ {\frac{{Q^2}}{{f}}} \right]^{\frac{1}{3}}}\)

Design of Canals Question 6:

The main function of a diversion head works of a canal from a river is-

  1. To raise water level
  2. To store water
  3. To control floods
  4. To remove silt

Answer (Detailed Solution Below)

Option 1 : To raise water level

Design of Canals Question 6 Detailed Solution

Diversion head works like Weir or barrage is constructed across a perennial river to raise water level and to divert the water to canal, is known as diversion head work Flow of water in the canal is controlled by canal head regulator. It controls the entry of silt into canals and provides some poundage by creating small pond. However, the most appropriate will be option ‘1’.

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Design of Canals Question 7:

A channel is designed by Lacey’s theory has a mean velocity of 2 m/sec. The silt factor is taken to be unity. The hydraulic mean radius will be?

  1. 5 m
  2. 2.5 m
  3. 2 m
  4. 10 m

Answer (Detailed Solution Below)

Option 4 : 10 m

Design of Canals Question 7 Detailed Solution

Concept:

Hydraulic mean radius as per Lacey’s theory is given by:

\(R = \frac{5}{2}\left( {\frac{{{V^2}}}{f}} \right)\)

Where,

V = mean velocity 

f = silt factor

Calculation:

Given,

V = 2 m/sec

f = 1

\(R = \frac{5}{2}\left( {\frac{{{V^2}}}{f}} \right)\)

\(R = \frac{5}{2}\left( {\frac{{{2^2}}}{1}} \right) = 10\;m\)

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According to Lacey, the design formulas for canal design are as follows:

1) silt factor ⇒ \(\rm{f = 1.76\sqrt {{d_{mm}}}}\)

2) velocity of flow ⇒ \(V = {\left[ {\frac{{Q{f^2}}}{{140}}} \right]^{\frac{1}{6}}}\)

3) hydraulic mean depth ⇒ \(R = \frac{{5{V^2}}}{{2f}}\)

4) wetted perimeter ⇒ \(P = 4.75\sqrt Q\)

5) bed slope ⇒ \(S = \frac{{{f^{\frac{5}{3}}}}}{{3340 \times {Q^{\frac{1}{6}}}}}\)

6) Lacey's regime scour depth ⇒ \(R_r' = 1.35{\left[ {\frac{{Q^2}}{{f}}} \right]^{\frac{1}{3}}}\)

Design of Canals Question 8:

Side slope canals are arranged _______ to contour

  1. at right angle
  2. at 45° angle
  3. at 65° angle
  4. Parallel

Answer (Detailed Solution Below)

Option 1 : at right angle

Design of Canals Question 8 Detailed Solution

Explanation:

1. Ridge Canal 

  • It is also called a watershed canal.
  • Aligned along the ridge or natural watershed line.
  • Can irrigate areas on both sides of the ridge.
  • Cross drainage work not requires.
  • They are economical.

2. Contour canal

  • Aligned nearly parallel to the contours of the country.
  • Can irrigate areas only on one side.
  • Cross drainage works are required.

3. Side Slope Canals

  •  Aligned roughly at right angles to the contour of the country.
  • It is neither on the watershed nor in the valley.
  • In can irrigate areas only on one side.
  • It is roughly parallel to the drainage of the country, so cross drainage works are not required.
  • It has a very steep bed slope.

Design of Canals Question 9:

A 20 m long horizontal concrete floor under a barrage on a permeable foundation retains a 5 m head of water and has a 5 m deep downstream end pile. The exit gradient is

  1. 1 in 4
  2. 1 in 5
  3. 1 in 6
  4. 1 in 8

Answer (Detailed Solution Below)

Option 2 : 1 in 5

Design of Canals Question 9 Detailed Solution

Concept:

Exit gradient, \({G_E} = \frac{H}{d} \times \frac{1}{{\pi \sqrt \lambda }}\)

Where,

H = Maximum seepage head

d = Vertical cut off depth at downstream end

\(\lambda = \frac{{1 + \sqrt {1 + {\alpha ^2}} }}{2}\;and\;\alpha = \frac{b}{d}\)

b = length at downstream end

Calculation:

\({\rm{\alpha }} = \frac{{20}}{5} = 4\)

\({\rm{\lambda }} = \frac{{1 + \sqrt {1 + {4^2}} }}{2} = 2.56\)

\({{\rm{G}}_{\rm{E}}} = \frac{5}{5} \times \frac{1}{{3.14 \times \sqrt {2.56} }} = \frac{1}{5}\)

Design of Canals Question 10:

Lacey’s scour depth for a stream carrying a discharge of 3 cumecs per meter width having a silt factor 1.2 is

  1. 1.32 m
  2. 2.64 m
  3. 3.96 m 
  4. 4.32 m

Answer (Detailed Solution Below)

Option 2 : 2.64 m

Design of Canals Question 10 Detailed Solution

Concept: 

Lacey's scour depth is given by:

\(R\; = \;1.35{\left( {\frac{{{q^2}}}{f}} \right)^{\frac{1}{3}}}\; \)

Where, q = Discharge per meter width, f = silt factor

Calculations:

Given, q = 3 cumec, f = 1.2

\(R\; = \;1.35{\left( {\frac{{{3^2}}}{1.2}} \right)^{\frac{1}{3}}}\;=\;2.64\;m\)

Important Points

Various formulas deduced by lacey is given below:

1) silt factor ⇒ \(\rm{f = 1.76\sqrt {{d_{mm}}}}\)

2) velocity of flow ⇒\(V = {\left[ {\frac{{Q{f^2}}}{{140}}} \right]^{\frac{1}{6}}}\)

3) hydraulic mean depth ⇒\(R = \frac{{5{V^2}}}{{2f}}\)

4) wetted perimeter ⇒ \(P = 4.75\sqrt Q\)

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