SI Formula Based MCQ Quiz in मल्याळम - Objective Question with Answer for SI Formula Based - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Given:

Principal (P₁) = ₹5,000

Rate (r₁) = 4% per annum

Principal (P₂) = ₹8,000

Rate (r₂) = 8% per annum

Time (t₂) = \(2 \frac{1}{2}\) years = 5/2 years

Formula used:

Simple Interest (SI) = \(\frac{P \times r \times t}{100}\)

Calculations:

Interest from ₹8,000 = \(\frac{8000 \times 8 \times \frac{5}{2}}{100}\)

⇒ \(\frac{8000 \times 8 \times 5}{2 \times 100} = 1600\)

So, interest = ₹1,600

Now, we need the interest from ₹5,000 to be ₹1,600.

Interest from ₹5,000 = \(\frac{5000 \times 4 \times t_1}{100}\)

⇒ \(\frac{5000 \times 4 \times t_1}{100} = 1600\)

⇒ \(\frac{20000 \times t_1}{100} = 1600\)

⇒ \(\frac{20000 \times t_1}{100} = 1600 \Rightarrow 200 \times t_1 = 1600\)

⇒ \(\Rightarrow t_1 = \frac{1600}{200} = 8\)

Answer:

Time (t₁) = 8 years

Given:

Principal amount (P) = ₹7,200

Amount (A) = ₹8,928

Rate of Interest (R) = 8% per annum

Formula Used:

Simple Interest (SI) = P × R × T / 100

Amount (A) = Principal (P) + Simple Interest (SI)

Calculation:

Simple Interest (SI) = Amount (A) - Principal (P)

⇒ SI = ₹8,928 - ₹7,200

⇒ SI = ₹1,728

Using the formula for Simple Interest:

SI = P × R × T / 100

⇒ 1,728 = 7,200 × 8 × T / 100

⇒ 1,728 = 576 × T

⇒ T = 1,728 / 576

⇒ T = 3 years

The correct answer is option 2.

Given:

Principal (P) = ₹ 9,500

Simple Interest (SI) = ₹ 1,520

Time (T) = 4 years

Formula Used:

Simple Interest (SI) = (P × R × T) / 100

where P → Principal, R → Rate of Interest, T → Time

Calculations:

According to Question:

1,520 = (9,500 × R × 4) / 100

1,520 = 38,000R / 100

1,520 = 380R

R = 1,520 / 380

R = 4%

∴ The rate of interest per annum is 4%.

Given:

Principal (P) = Rs. 6,000

Rate of interest (R) = 10% p.a.

Final amount (A) = Rs. 28,000

Formula Used:

Simple Interest (SI) = (P × R × T) / 100

Amount (A) = Principal + Interest

Calculation:

Since the interest is added to the principal after every 20 years, we need to find the time (T) in years where the amount becomes Rs. 28,000.

First 20 years:

SI₁ = (6000 × 10 × 20) / 100

⇒ SI₁ = 12000

New Principal after 20 years = P + SI₁

New Principal = 6000 + 12000 = 18000

SI₂ = 28000 - 18000 = 10000

SI₂ = (18000 × 10 × T)/100

⇒ 10000 = (18000 × 10 × T)/100

⇒ 10000/1800 = T

⇒ T = 5.55 years.

Total Time = 20 years + 5.55 years = 25.55 years

The correct answer is option 3.

Given:

Principal (P) = Rs. 1,000

Rate of Interest (R) = 5% per annum

Interest is added to the principal every 10 years

Final Amount (A) = Rs. 2,000

Formula Used:

Simple Interest (SI) = P × R × T / 100

Calculation:

For the first 10 years:

SI₁ = 1000 × 5 × 10 / 100

SI₁ = 500

Amount after 10 years = Principal + SI₁

Amount₁ = 1000 + 500

Amount₁ = 1500

For the next 10 years:

Principal for the next 10 years = Amount₁

SI₂ = 1500 × 5 × 10 / 100

SI₂ = 750

Amount after 20 years = Principal + SI₂

Amount₂ = 1500 + 750

Amount₂ = 2250

Since Amount₂ (Rs. 2250) exceeds Rs. 2000, we need to find the exact time when it becomes Rs. 2000.

Let the time required after the first 10 years be T years to reach Rs. 2000:

SI = 1500 × 5 × T / 100

Interest needed = 2000 - 1500 = 500

⇒ 1500 × 5 × T / 100 = 500

⇒ 75T = 500

⇒ T = 500 / 75

⇒ T = 6 (2/3) years

Total time = 10 + 6 (2/3) years

Total time = 16 (2/3) years

Therefore, the correct answer is option 4: 16 (2/3) years.