Probability Distribution MCQ Quiz in मल्याळम - Objective Question with Answer for Probability Distribution - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 17, 2025

നേടുക Probability Distribution ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Probability Distribution MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Probability Distribution MCQ Objective Questions

Top Probability Distribution MCQ Objective Questions

Probability Distribution Question 1:

If the mean and variance of a binomial distribution are 5 and 4, respectively, then the value of n is:

  1. 25
  2. 10
  3. 15
  4. 20
  5. Not Attempted

Answer (Detailed Solution Below)

Option 1 : 25

Probability Distribution Question 1 Detailed Solution

The correct answer is 25

Key PointsGiven:

Mean = np =5

Variance = np (1−p) = 4

Calculation:

Variance = 4

⇒ np (1−p) = 4

⇒ 1 − p = 4/5​

⇒ 1 − p = 4/5

⇒ p = 1/5 

Since, np = 5

⇒ n × 1/5 = 5

⇒ n = 25

∴ The value of n is 25.

Given the mean and variance of a binomial distribution, we can find the values of n and p. The mean of a binomial distribution is equal to n * p, and the variance is equal to n * p * (1 - p). We can use these two equations to solve for n and p.

Additional Information 

  • The binomial distribution is a discrete probability distribution that describes the number of successes in a fixed number of independent Bernoulli trials.
  • The parameters of a binomial distribution are n (the number of trials) and p (the probability of success in each trial).
  • The mean and variance of a binomial distribution are n * p and n * p * (1 - p), respectively.
  • Given the mean and variance of a binomial distribution, we can use these two equations to find the values of n and p.
  • Understanding the properties of binomial distributions and how to find the mean and variance is important in many areas of statistics and data analysis.

Probability Distribution Question 2:

Which of the following conditions are satisfied in case of a symmetrical distribution ?

I. The value of mean, median and mode coincide

II. The value of mean, median and mode do not coincide

III. Data plotted on graph gives bellshaped curve

IV. Quartiles are equidistant from the median

Codes :

  1. I only
  2. I and II only
  3. I, III and IV only
  4. I, II, III and IV

Answer (Detailed Solution Below)

Option 3 : I, III and IV only

Probability Distribution Question 2 Detailed Solution

The correct answer is 'option 3'

Key Points

  • In a symmetrical distribution or symmetrical curve, skewness is not present.
  • The values of mean, median and mode coincide i.e. Mean=Meadian=Mode. The spread of the frequencies is the same on both sides of the central point curve. 
  • Symmetrical distribution occurs when the values of variables occur at regular frequencies and the mean, median and mode occur at the same point.
  • In graph form, symmetrical distribution often appears as a bell curve.
  • If a line were drawn dissecting the middle of the graph, it would show two sides that mirror each other.
  • If the distribution is symmetric, like normal distribution, then the quartiles are equidistant from the median in either direction.

Therefore, the correct answer is 'I, III and IV'

Additional Information

Meaning of Skewness:

  • The term skewness means lack of symmetry in a frequency distribution.
  • Skewness denotes the degree of departure of a distribution from symmetry and reveals the direction of scatteredness of the items.
  • It gives us an idea about the shape of the frequency curve.
  • When a distribution is not symmetrical, It is called a skewed distribution. 

Symmetrical distribution is a core concept in technical trading as the price action of an asset is assumed to fit a symmetrical distribution curve over time.

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