Bolted Connections MCQ Quiz in मल्याळम - Objective Question with Answer for Bolted Connections - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 14, 2025
Latest Bolted Connections MCQ Objective Questions
Top Bolted Connections MCQ Objective Questions
Bolted Connections Question 1:
Centre to centre distance of adjacent rivet or bolt holes measured in the direction of stress is called _____.
Answer (Detailed Solution Below)
Bolted Connections Question 1 Detailed Solution
Pitch: It’s the centre to centre spacing of bolts in a row, measured in the direction of the load.
Gauge: It is the distance between two adjacent bolt rows, measured right angle to the direction of load.
It should satisfy requirements specified in clause 10.2, IS 800: 2007, regarding spacing, such as
1) Pitch shall not be less than 2.5 × d (d is the diameter of bolt)
2) Minimum edge distance = 1.7 × do in case of hand cut edges and 1.5 do in case of rolled or machine cut edges. (do is the diameter of bolt hole).Bolted Connections Question 2:
Two steel plates, each of 12 mm thickness, are connected by a double-cover butt joint by bolts as shown in the figure below. If the bolt diameter is 20 mm and steel is of grade Fe 410, which one of the following sections is the most critical section for a cover plate?
Answer (Detailed Solution Below)
Bolted Connections Question 2 Detailed Solution
Critical section for Cover Plate:
The cross-sectional area of the plate through various sections.
Let the width of the plate be ‘b’, the thickness of plate ‘t’ and diameter of the hole be ‘dh’
For section 1-1: Asection 1-1 = (b – 3 dh) × t
For section 2-2: Asection 2-2 = (b – 2 dh) × t
For section 3-3: Asection 3-3 = (b – 1 dh) × t
∴ Critical section for the cover plate is section 1-1 as the cross-sectional area is least.
Critical section for Main Plate:
Bolted Connections Question 3:
What is the permissible tensile stress in bolts used for column bases?
Answer (Detailed Solution Below)
Bolted Connections Question 3 Detailed Solution
Explanation:
Permissible tensile stresses in bolts used for column bases is 120 N/mm2.
Additional Information
Permissible Maximum Stress |
Stress Value |
Permissible average shear stress |
0.40 fy |
Permissible maximum shear stress |
0.45 fy |
Permissible axial tensile stress |
0.60 fy |
Permissible compressive or tensile bending Stress |
0.66 fy |
Permissible bearing stress |
0.75 fy |
Bolted Connections Question 4:
What is the efficiency of joint when strength of bolt per pitch length is 55 kN and strength of plate per pitch length is 120 kN?
Answer (Detailed Solution Below)
Bolted Connections Question 4 Detailed Solution
Concept:
Efficiency = (strength of bolt per pitch length / strength of plate per pitch length) x100
Calculation:
Strength of bolt per pitch length = 55 kN
Strength of plate per pitch length is 120 kN
Efficiency = (strength of bolt per pitch length / strength of plate per pitch length) × 100
η = (55 / 120) × 100 = 45.83 %
Bolted Connections Question 5:
Due to the flexibility of the connected plates under tension, an additional force is induced in the bolts. This phenomenon is known as
Answer (Detailed Solution Below)
Bolted Connections Question 5 Detailed Solution
In the moment resisting connections, bolts will be required to transfer the load by direct tension. These are called prying forces and these are developed due to flexibility of end plate connections.
Shear lag is the non-uniform straining of member due to tension and it occurs when action and reaction do not pass through the centre of gravity of cross section.
If the steel is stressed into the inelastic range and then unloaded, then subjected to uniform compression in the opposite direction, it is found that and the stress-strain curve becomes nonlinear at a stress much lower than the initial yield strength. This is called Bauschinger effect.
It is assumed that bolts share applied axial load equally while designing bolted connection but in case of long joints, end bolts will take more load than inner bolts. So, failure of bolt in long joints is sequential (one after another), starting with outer bolts and progressing towards centre. This is called unbuttoning.
Bolted Connections Question 6:
The distance between center of fasteners shall not be less than Y times the nominal diameter of the fastener, where Y is:
Answer (Detailed Solution Below)
Bolted Connections Question 6 Detailed Solution
Explanation:
Pitch and gauge:
The distance between the centers of rivet holes measured along the applied stress is known as Pitch, whereas the distance the center of rivet holes measured perpendicular to the direction of the applied stress is known as Gauge.
As per IS 800, the minimum pitch specified is 2.5 times the nominal diameter of rivet.
Bolted Connections Question 7:
Oversize of hole shall NOT exceed _______ times the nominal diameter of the bolt.
Answer (Detailed Solution Below)
Bolted Connections Question 7 Detailed Solution
Explanation:
Oversized holes:
- The oversize hole shall not exceed 1.25 d or (d + 8) mm in diameter, where d is the nominal diameter of the bolt in mm.
- A short slotted hole shall not exceed the appropriate hole size in width and 1.33 d in length, where d is the nominal diameter of the bolt in mm.
- A long slotted hole shall not exceed the appropriate hole size in width and 2.5 d in length, where d is the nominal diameter of the bolt in mm.
Note:
1. The recommended size of Bolt/Rivet Hole diameter is given below:
Rivet Diameter |
Size of hole |
≤ 25 mm |
1.5 mm |
> 25 mm |
2 mm |
Bolted Connections Question 8:
In a steel plate with bolted connection the rupture of the net section is a mode of failure under
Answer (Detailed Solution Below)
Bolted Connections Question 8 Detailed Solution
Concept-
The design strength of a tension member is based on two limit states-
(a) Limit state based on the yield strength of the member due to its large elongation.
(b) Limit state based on the ultimate strength of the member.
The design strength of a tension member is the minimum of the following:
a) Design strength due to yielding of the gross section (Tdg)-
In this type of failure wherein yielding of the gross section occurs there a significant amount of deformation occurs before the material actually gets fractured. This significant amount of deformation makes the structure unserviceable.
b) Rupture strength of the critical section (Tdn)-
When the net section of the member reaches the ultimate stress, then rupture (or fracture) of the member takes place.
c) Block shear strength (Tdb)-
Here a segment of the block of the material at the corner of the connection shears out due to possible high bearing strength of steel and high strength of bolts.
In a steel plate with bolted connection, the rupture of the net section is a mode of failure under tension.
Additional Information
Bolted Connections Question 9:
Eccentricity of connections introduces
Answer (Detailed Solution Below)
Bolted Connections Question 9 Detailed Solution
Concept:
Primary stresses are mainly force driven and are caused by imposed mechanical loading on the structure and excessive primary stress causes yielding and plastic deformation of the material. They are not self limiting. e.g Dead and Live load on a cantilever beam etc.
Secondary stresses are mainly displacement driven and are caused due to geometric discontinuity and stress concentration. They are self limiting and beyond a certain stage the stresses begin to decrease. e.g Thermal loads, Eccentric loads etc.
Eccentric connection: If the applied forces do not pass through the C.G of joint, it causes an additional moment about the C.G and these types of connections are called eccentric connections.
The stresses induced due to these eccentric connections are known as secondary stresses because they arise due to geometric dissimilarity.
Here eccentricity ‘e’ introduces a moment Pe and secondary stresses are generated consequently.'
Eccentric connection in lap joint
Here also secondary stresses are generated due to eccentricity in connections.
Bolted Connections Question 10:
If the load is transmitted by bolts or rivets through some but not all the cross-sectional elements of the member, the effective area Ae is computed by using net area An and the reduction coefficient U as
Answer (Detailed Solution Below)
Bolted Connections Question 10 Detailed Solution
Concept:
Shear lag:
- Shear lag occurs when some elements of the member cross-section are not connected.
- Shear lag is a function of the distribution of steel in the section and the length of the load transfer.
- Consider an angle section tension member connected with one leg only. Consequently, due to this partial connection, the connected leg will be overloaded and the unconnected leg will not be fully stressed.
- Further, since at the joint/connection more of the load is carried by the connected leg, and it takes the transition distance, for the stress to spread uniformly across the whole angle, stress distribution in the two legs of the section would be different.
- In the transition region, the stress in the connected part of the member may even exceed fy and go into strain—hardening range; the member may fracture prematurely. Away from joint/connection, the stress distribution is more uniform. Ie the transition region, the shear transfer lags.
- Since shear lag reduces the effectiveness of the component plates of the tension member that are not connected directly to a gusset plate, the outstanding legs are kept shorter in length. For this reason, unequal angles with long legs connected are preferred.
- It is independent of the type of load and applies to both bolted and welded connections. Of course, bolted connections will be affected more than welded connections because of the reduction of the effective area due to bolt holes. The shear lag can be accounted for by using reduced net area and is known as effective net area.
Ae = UAn
where
Ae = Effective area
U = reduction factor
An = net area