Scheduling MCQ Quiz - Objective Question with Answer for Scheduling - Download Free PDF

1) X born in a month which have odd number of days but not on even date of a month.

2) Only one person born between X and O.

3) More than three person born between E and the person who lives in Delhi.

4) J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5) Person who lives in Mumbai born immediately after O.

6) Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7) Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Since, O born on 9th April and J and E both born in May.

Hence, More than one option is correct.

1) X born in a month which have odd number of days but not on even date of a month.

2) Only one person born between X and O.

3) More than three person born between E and the person who lives in Delhi.

4) J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5) Person who lives in Mumbai born immediately after O.

6) Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7) Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Hence, all except O born in the month which have odd number of days.

1) X born in a month which have odd number of days but not on even date of a month.

2) Only one person born between X and O.

3) More than three person born between E and the person who lives in Delhi.

4) J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5) Person who lives in Mumbai born immediately after O.

6) Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7) Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Since, on 9th May J was born and just before him M was born. 

1) X born in a month which have odd number of days but not on even date of a month.

2) Only one person born between X and O.

3) More than three person born between E and the person who lives in Delhi.

4) J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5) Person who lives in Mumbai born immediately after O.

6) Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7) Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Since, J born on 9 May and R born on 26 March.

Hence, two person born between them which are O and M.

1) X born in a month which have odd number of days but not on even date of a month.

2) Only one person born between X and O.

3) More than three person born between E and the person who lives in Delhi.

4) J lives in a city which start with the same alphabetical letter. Therefore, case 1 further divided into two cases.

5) Person who lives in Mumbai born immediately after O.

6) Only three person born between R and the person who lives in Patna. Therefore, case 1(b) and case 2 are eliminated.

7) Person who lives in Kolkata born before M but not immediately before him. Therefore, case 3 is eliminated. Hence, the final arrangement is as follows

Hence, M ​lives in Mumbai.

I. Only Sunday is a holiday.

We cannot answer on what day does shyama go to Shimla using the statement given.

II. Shyama was in Shimla on a holiday.

We cannot answer on what day does shyama go to Shimla using the statement given.

I and II:

We cannot answer On what day does Shyama go to Shimla using statements I and II together.

Some additional data is needed to answer the question.

We cannot answer On what day does Shyama go to Shimla using statements I and II together.

we know that Shyama was in Shimla on Sunday, but we have no idea of when she went to Shimla. 

The correct answer is Option 4.

Key Point:

• Given : Statement-1: Lecture F is preceded by A followed by C. Statement-2: No lecture after lecture B .
• Case 1 : AFC_ _ B
• Case 2 : _AFC_B
• Case 3 : _ _ AFCB
• It’s pretty evident that neither of the two statements is sufficient alone.  So, even by using both the statements we cannot determine the answer. 
• Even on combining the two, we get multiple possible cases
• Hence in Statement 1 there are many possibilities. 
• There may be even more cases as it’s not necessary that A, F and C are consequent lectures.
• Hence Option 4 is correct. 

Given: A, B, C, D, E and F have interviews on different days of a week from Monday to Saturday but not necessarily in the same order

I) D has an interview just before E. Two persons have an interview between D’s and F’s interviews. So, we cannot determine the person, who has an interview on Tuesday.

II) C has an interview on Friday. B has an interview two days before D.So, we cannot determine the person, who has an interview on Tuesday.

By combining I and II,

Therefore, A has an interview on Tuesday.

Hence, option 4 is the correct answer. 

Given:

Cricket clubs in five towns A, B, C, D, and E have one team each named P, Q, R, S, and T, not necessarily in the same order.

The team in A has beaten R, P, and S

This means A will have team Q or T

Q has beaten the teams in E, C, and A. 

This means A will not have Q as a team. Then A has T team.

Team R is in B.

Q will not in E and C as beaten.

S is not in C then is in E.

Hence, A has team T.

From statement I:

Gaurav has purchased a car after September but not in the last month

Gaurav has purchased a car either in October or November.

Therefore, statement I alone is not sufficient to answer the question.

From statement III:

Gaurav has purchased a car in that month which has 30 days.

Possible options are April / June / September / November.

Therefore, statement III alone is not sufficient to answer the question.

On combining I and II:

So, Gaurav has purchased a car in November.

Therefore, statement I and II together are sufficient to answer the question.

On combining I and III:

So, Gaurav has purchased a car in November.

Therefore, statement I and III together are sufficient to answer the question.

On combining II and III:

Possible options are April / June / September / November.

Therefore, statement II and III together are not sufficient to answer the question.

Hence, either statement II or III along with I are sufficient to answer the question.

Given:

Cricket clubs in five towns A, B, C, D, and E have one team each named P, Q, R, S, and T, not necessarily in the same order.

The team in A has beaten R, P, and S

This means A will have team Q or T

Q has beaten the teams in E, C, and A.

This means A will not have Q as a team. Then A has T team.

Team R is in B.

Q will not in E and C as beaten.

S is not in C then is in E.

Hence, team Q is in D

From Statement I: Saritha drinks tea on 4 alternative days.

Saritha can drink milk on Monday, Tuesday, Wednesday, Thursday, Friday Saturday or Sunday as the 4 days are not known.

Hence, Statement I alone is not sufficient to answer the question.

From Statement II: She drinks coffee on Tuesday and Thursday.

Saritha does not drink milk on Tuesday and Thursday as she drinks coffee.

Saritha can drink milk on Monday, Wednesday, Friday, Saturday or Sunday.

Hence, Statement II alone is not sufficient to answer the question.

From Statement III: Saritha drinks tea on Monday.

Saritha does not drink milk on Monday as she drinks tea.

Saritha can drink milk on Tuesday, Wednesday, Thursday, Friday Saturday or Sunday.

Hence, Statement III alone is not sufficient to answer the question.

By combining Statements I and II: Saritha drinks tea on 4 alternative days. She drinks coffee on Tuesday and Thursday.

Saritha does not drink milk on Tuesday and Thursday as she drinks coffee.

Saritha does not drink milk on Monday, Wednesday, Friday and Sunday as she drinks Tea.

Saritha drinks milk on Saturday.

Hence, Statement I and II together are sufficient to answer the question.

1. Chitra reached the destination 1 hour after Esha.

2. Deeksha reached the destination at 2:30 pm.

Statement I: Two persons reached the destination between the time on which Ankur and Fatima reached. Fatima does not reach at 5:00 pm. So, we have,

Statement II: Gaurav reached destination after Brian. Brian does not reach at 10:30 am.

Statement I and II together:

Therefore, Gaurav reached at 5:00 pm.

Given six persons- B1, B2, B3, B4, B5 and B6 go on a trip on two different dates- 8 and 19.

Three different months- April, May and June.

From statement I,

From statement II, we can’t get any clarity or possibility because of insufficient information.

Also from statement III, we can’t get any clarity or possibility because of insufficient information. Because we can't determine on which date B4 is going. Also, we know B2 goes after B6. But we can't determine the date.

But combining statement I and III we get that case- I, III and IV are cancelled. Because only in case-II, B4 goes on an odd number date which is 19th May. Also, two persons go between B6 and B2. B2 goes after B6. So, we can find the answer,

B2 goes on 8th June.

Hence, only statement I and III are sufficient to find the answer.

From the question, the exam is scheduled on the second week.

From statement I, the exam is scheduled on the sixth working day, the first day is Sunday, so the sixth working day will be Friday.

Now, from statement II, the exam is scheduled after Thursday, before the last day of the week.

The last day of the week is Saturday, so the exam is scheduled for Friday.