Query Language MCQ Quiz - Objective Question with Answer for Query Language - Download Free PDF

Last updated on May 6, 2025

Latest Query Language MCQ Objective Questions

Query Language Question 1:

In a relational data model, which one of the following statements is TRUE?

  1. A relation with only two attributes is always in BCNF.
  2. If all attributes of a relation are prime attributes, then the relation is in BCNF.
  3. Every relation has at least one non-prime attribute
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : A relation with only two attributes is always in BCNF.

Query Language Question 1 Detailed Solution

The correct answer is option 1.

Concept:

Option 1: A relation with only two attributes is always in BCNF.

True, Relation with two attributes always in BCNF

Example:

A relation R(XY) and functional dependency are {X→Y} it is in BCNF.

{Y→X} it is in BCNF.

{x→Y, Y→X} it is in BCNF.

Option 2: If all attributes of a relation are prime attributes, then the relation is in BCNF.

False, If all prime attributes then the relation is always in 3NF but may not be in BCNF.

Example:

A relation R(ABCD) and functional dependency are {AB→C, B→D, D→B } it is in 3NF.

Candidate key= AB, AD

AB→C is BCNF

B→D is in 3NF

D→B is in 3NF

Hence the relation is 3NF.

Option 3: Every relation has at least one non-prime attribute.

False, It is not mandatory for at least one non-prime attribute in the Relational database management system table.

Option 4: BCNF decompositions preserve functional dependencies.

False, It is not every relation can decompose into BCNF with dependency preserving. Every non-prime attribute in BCNF should be functionally dependent on one of the schema's super keys. If there is any FD that does not follow this, we must divide it into a new relationship in that case. Now, if any other FD employs the prior FD, the FD will not be preserved in BCNF.

Query Language Question 2:

An instance of relational schema R (A, B, C) has distinct values of A including NULL values. Which one of the following is true ?

  1. A is a candidate key 
  2. A is not a candidate key 
  3. A is a primary Key
  4. Both (1) and (3)

Answer (Detailed Solution Below)

Option 1 : A is a candidate key 

Query Language Question 2 Detailed Solution

The correct answer is A is a candidate key.

key-point-image Key Points

  • A candidate key is a column, or set of columns, in a table that can uniquely identify any database record without referring to any other data. A candidate key's values are unique and can be used as a primary key.
  • In the given relational schema R (A, B, C), column A has distinct values including NULL values. This means that each value in column A is unique among all entries in that column, which is a requirement for being a candidate key.
  • A candidate key must have unique values, and while it can have NULL values, it means it is not suitable to be a primary key (as primary keys cannot have NULL values). Hence, column A qualifies as a candidate key.
  • A primary key is a candidate key that is chosen by the database designer to uniquely identify records in a table. Since A contains NULL values, it cannot be a primary key.

additional-information-image Additional Information

  • Relational database systems typically require that each table has a primary key. This key is used to enforce entity integrity.Other candidate keys can be used as alternative keys or for creating unique constraints.
  • NULL values in candidate keys can be useful in certain scenarios where not all records need to have a value for the key column.
  • In SQL, the UNIQUE constraint can be used to designate a column (or combination of columns) as a candidate key.
  • When designing a database schema, it's essential to identify candidate keys to ensure data integrity and efficient data retrieval.

Query Language Question 3:

Consider the following statements :

I - The primary key of a relation cannot contain null values.

II - Unique Key can have null values.

Which among the following is true ? 

  1. Both I and II are true
  2. Both I and II are false
  3. Only I is true
  4. Only II is true

Answer (Detailed Solution Below)

Option 1 : Both I and II are true

Query Language Question 3 Detailed Solution

The correct answer is Both I and II are true.

key-point-image Key Points

  • The primary key of a relation cannot contain null values. This is because the primary key uniquely identifies each record in a database table, and having a null value would violate this uniqueness constraint.
  • A unique key can have null values. While unique keys ensure that all values in a column are different, they do allow for null values, as nulls are not considered equal to any other value, including other nulls.

additional-information-image Additional Information

  • Primary keys are used to establish and enforce entity integrity, ensuring that each record in a table is unique and identifiable.
  • Unique keys help in ensuring the uniqueness of the column values but can be used in scenarios where null values are permissible.
  • Both primary keys and unique keys can be used to enforce constraints and indexes, improving the performance of database queries.
  • In a relational database, both primary and unique keys are crucial for maintaining data integrity and efficient data retrieval.

Query Language Question 4:

Single row or scalar functions are applied on a single value and return a single value.

Which of the following is NOT a Date Function?

  1. DATE()
  2. NOW()
  3. THEN()
  4. DAY()

Answer (Detailed Solution Below)

Option 3 : THEN()

Query Language Question 4 Detailed Solution

- halleshangoutonline.com

The correct answer is THEN().

key-point-imageKey Points

  • Date functions are used in SQL to manipulate and retrieve date and time values from the database. They are essential for performing operations on date and time data types.
  • Common date functions include:
    • DATE(): Returns the current date.
    • NOW(): Returns the current date and time.
    • DAY(): Returns the day part of a date.
  • The function THEN() is not a recognized date function in SQL. It does not perform any operations related to dates or times.

additional-information-imageAdditional Information

  • Date functions are pivotal in database management systems for scheduling, logging, and tracking events over time.
  • They help in calculating intervals between dates, formatting dates, and extracting specific parts of date values.
  • Other notable date functions include:
    • MONTH(): Returns the month part of a date.
    • YEAR(): Returns the year part of a date.
    • TIMESTAMP(): Returns a date and time value.
  • Understanding and using date functions can significantly enhance the capability to perform temporal queries and reports.

Query Language Question 5:

Which SQL function will return the following output:

mysql > Select ____?_____ (53, 10);

output __ 3

  1. Truncate
  2. ROUND
  3. MOD
  4. POW

Answer (Detailed Solution Below)

Option 3 : MOD

Query Language Question 5 Detailed Solution

The correct answer is MOD.

key-point-image Key Points

  • The SQL MOD function is used to find the remainder of a division operation between two numbers.
    • In the given example, MOD(53, 10), 53 is divided by 10.
    • The quotient of this division is 5 (since 53 divided by 10 equals 5 with a remainder).
    • The remainder of this division is 3, hence the output of MOD(53, 10) is 3.

additional-information-image Additional Information

  • The MOD function is supported by many SQL databases, including MySQL, PostgreSQL, Oracle, and SQL Server.
  • The syntax of the MOD function can vary slightly between different SQL databases.
  • In some databases, the MOD function might be called REMAINDER.
  • Understanding the MOD function is essential for mathematical calculations and data analysis in SQL.

Top Query Language MCQ Objective Questions

Consider the following statements S1 and S2 about the relational data model:

S1: A relation scheme can have at most one foreign key.

S2: A foreign key in a relation scheme R cannot be used to refer to tuples of R.

Which one of the following choices is correct? 

  1. S1 is true and S2 is false.  
  2. Both S1 and S2 are true.  
  3. Both S1 and S2 are false.  
  4. S1 is false and S2 is true. 

Answer (Detailed Solution Below)

Option 3 : Both S1 and S2 are false.  

Query Language Question 6 Detailed Solution

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Answer: Option 3

Concept

Foreign Key :is the set of attributes in a particular relation whose values are belongs to primary key of same relation or other relation.

Explanation

Statement 1: A relation scheme can have at most one foreign key.

There is no such restriction on how many number of Foreign keys a particular relation can have. A relation can have as many number of Foreign keys as Required

So this statement is false.

Statement 2: foreign key in a relation scheme R cannot be used to refer to tuples of R.

There is no such constraint. Foreign key can be used to refer to primary key of the same relation. Self-referencing relations are examples of such foreign key. So this statement is also false.

So option 3 is the correct answer.

Consider the relation scheme R = (E, F, G, H, I, J, K, L, M, N) and the set of functional dependencies {(E, F} → {G}, {F} → {I, J}, {E, H} → {K, L}, {K} → {M}, {L} → {N}} on R. What is the key for R ?

  1. {E, F}
  2. {E, F, H}
  3. {E, F, H, K, L}
  4. {E}

Answer (Detailed Solution Below)

Option 2 : {E, F, H}

Query Language Question 7 Detailed Solution

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Function Dependencies:

{(E, F} → {G}, {F} → {I, J}, {E, H} → {K, L}, {K} → {M}, {L} → {N}}

Option 1: {E, F}

{E, F}+ = {E, F, G, I, J}

Since K, L, M and N is missing in RHS ∴ it is not a key

Also, {E} cannot be a key because {E} is subset of {E, F}

Option 2: {E, F, H}

{E, F, H}+ = {E, F, H, G, I, J, K, L, M, N}

∴ it is a key

Key for R is {E, F, H}.

Important Points:

In relation algebra, key is primary key or candidate key.

{E, F, H, K, L} is super key. 

A prime attribute of a relation schema R is an attribute that appears

  1. in all candidate keys of R
  2. in some candidate key of R
  3. in a foreign key of R
  4. only in the primary key of R

Answer (Detailed Solution Below)

Option 2 : in some candidate key of R

Query Language Question 8 Detailed Solution

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  • Attributes of the relation which exist in at least one of the possible candidate keys, are called prime or key attributes
  • Candidate key is a minimal super key and a Super key is a set of attributes that uniquely identify a tuple in a relation.
  • Therefore, a prime attribute of a relation scheme R is an attribute that appears in some candidate key of R


Important Point:

  • Primary key is selected from a set of candidate keys of a relation.

Mistake Points 
Option 1) is not correct. Because a prime attribute is an attribute that can appear in any candidate key. The attribute need not appear in all candidate keys of R. Example:- if A is a prime attribute then for a relationship it is not required for A to be present in all candidate keys of relation R.

What is the full form of SQL?

  1. Simple Query Language
  2. Structured Queuing Language
  3. Structured Query Language
  4. Structured Queuing Lexicon

Answer (Detailed Solution Below)

Option 3 : Structured Query Language

Query Language Question 9 Detailed Solution

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Key Points

 SQL (Structured Query Language) is a standardized programming language that's used to manage relational databases and perform various operations on the data in them. ... SQL became the de facto standard programming language for relational databases after they emerged in the late 1970s and early 1980s.

  • SQL is regularly used not only by database administrators, but also by developers writing data integration scripts and data analysts looking to set up and run analytical queries.
  • The uses of SQL include modifying database table and index structures; adding, updating and deleting rows of data; and retrieving subsets of information from within a database for transaction processing and analytics applications.

Hence the correct answer is Structured Query Language.

_______ symbol is used to see every column of a table.

  1. /
  2. _ _
  3. *
  4. !

Answer (Detailed Solution Below)

Option 3 : *

Query Language Question 10 Detailed Solution

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The * symbol is used to see every column of a table.

 For Example, Let us consider a table Table1

ID NAME AGE ADDRESS SALARY
1 Akash 24 Bijnor 12000
2 sema 23 Delhi 15000
3 diya 33 Banglore 33000
4 Badal 29 Odisha 40000

If you want to fetch only some specific columns from the table, then we can use this query,

Select ID,NAME,AGE from Table1;    / Syntax is Select (column_name1, coloumn_name2.....coloum_name) from table_name;

ID NAME AGE
1 Akash 24
2 sema 23
3 diya 33
4 Badal 29

If you want to fetch all the fields of the Table1 table, then you should use the following query 

Select * from Table1;    Syntax is Select * from table_name;

ID NAME AGE ADDRESS SALARY
1 Akash 24 Bijnor 12000
2 sema 23 Delhi 15000
3 diya 33 Banglore 33000
4 Badal 29 Odisha 40000

Therefore Option 3 is correct

Which of the following is NOT a superkey in a relational schema with attributes V, W, X, Y, Z and primary key V Y?

  1. VXYZ
  2. VWXZ
  3. VWXY
  4. VWXYZ

Answer (Detailed Solution Below)

Option 2 : VWXZ

Query Language Question 11 Detailed Solution

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Concept:

Superkey is a set of attributes within a table whose values can be used to uniquely identify a tuple. A candidate key is a minimal superkey.

Superkey is superset of candidate key or primary key.

Explanation:

Primary key is VY. (given)

All superkeys must contain this primary key VY. From the given keys, key, which doesn’t contain

the VY.

Here, option 2: VWXZ

“VWXZ” doesn’t contain the primary key VY. So, it is not a superkey.

Properties of ‘DELETE’ and ‘TRUNCATE’ commands indicate that

  1. After the execution of ‘TRUNCATE’ operation, COMMIT, and ROLLBACK statements can be performed to retrieve the lost data, while ‘DELETE’ does not allow it.
  2. After the execution of ‘DELETE’ and ‘TRUNCATE’ operation retrieval is easily possible for the lost data
  3. After the execution of ‘DELETE’ operation, COMMIT and ROLLBACK statements can be performed to retrieve the lost data., while TRUNCATE do not allow it
  4. After the execution of ‘DELETE’ and ‘TRUNCATE’ operation no retrieval is possible for the lost data

Answer (Detailed Solution Below)

Option 3 : After the execution of ‘DELETE’ operation, COMMIT and ROLLBACK statements can be performed to retrieve the lost data., while TRUNCATE do not allow it

Query Language Question 12 Detailed Solution

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TRUNCATE

  • Is a DDL command hence it cannot be rolled back.
  • It resets the identity of the table and locks that state of the table.
  • Hence, Commit and Rollback will have no effect after TRUNCATE.

 

DELETE

  • Is a DML command hence it can be rolled back
  • It does not rest the identity of the table, it just locks the table row
  • Hence Commit and Rollback can have effect depending on the lock techniques used.

 

Hence, it can be said that after the execution of ‘TRUNCATE’ operation, COMMIT, and ROLLBACK statements cannot be performed to retrieve the lost data, while ‘DELETE’ allows it.

It can also be said that after the execution of ‘DELETE’ operation, COMMIT and ROLLBACK statements can be performed to retrieve the lost data, while TRUNCATE does not allow it

NOTE

In official ISRO CS 2020, both option 1 and 3 were correct and hence option is slightly modified to get only correct answer.

Consider a relational database containing the following schemes.

Catalogue

sno

pno

Cost

S1

P1

150

S1

P2

50

S1

P3

100

S2

P4

200

S2

P5

250

S3

P1

250

S3

P2

150

S3

P5

300

S3

P4

250

 

Suppliers

sno

sname

location

S1

M/s Royal furniture

Delhi

S2

M/s Balaji furniture

Bangalore

S3

M/s Premium furniture

Chennai

 

Parts

pno

Pname

Part_spec

P1

Table

Wood

P2

Chair

Wood

P3

Table

Steel

P4

Almirah

Steel

P5

Almirah

Wood

 

The primary key of each table is indicated by underling the constituent fields.

SELECT  s.sno, s.sname

FROM   Suppliers s, Cataloque c

WHERE s.sno = c.sno AND

                Cost > (SELECT AVG (cost)

FROM Cataloque

WHERE pno = ‘P4’

GROUP BY pno);

The number of rows returned by the above SQL query is

  1. 4
  2. 5
  3. 0
  4. 2

Answer (Detailed Solution Below)

Option 1 : 4

Query Language Question 13 Detailed Solution

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Inner Query: SELECT AVG (cost) FROM Cataloque WHERE pno = ‘P4’ GROUP BY pno

The execution of the inner query gives the average of the cost of parts with part-id P4

Output:

Avg (cost)

225

 

Outer Query:

SELECT s.sno, s.sname FROM Suppliers s, Cataloque c WHERE s.sno = c.sno AND Cost > (225)

The execution of the entire query output the following table:

sno

sname

S2

M/s Balaji furniture

S3

M/s Premium furniture

S3

M/s Premium furniture

S3

M/s Premium furniture

 

Hence, there are 4 rows in the resultant table. 

In relational database minimal super keys is known as -

  1. Reference keys
  2. Candidate keys
  3. Foreign keys
  4. Primary keys

Answer (Detailed Solution Below)

Option 2 : Candidate keys

Query Language Question 14 Detailed Solution

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The correct option is (2)

Candidate key

Concept:-

The candidate key can be called a super key, as each candidate key is a subset of the super key. The super key with all necessary attributes is known as the candidate key. The super key with unnecessary attributes cannot be considered a candidate key.

Key Points

  • A Candidate key is a minimal super key, meaning that it would cease to be a super key if you removed any attribute from the set.
  • A minimum super key is referred to as a candidate and the main key since the primary key is chosen from the candidate keys.
  • The minimal set of attributes that can uniquely identify a tuple is known as candidate key. For example, STUD_NO in STUDENT relation. It is a minimal super key.

Additional InformationForeign keys:- The characteristic that establishes the relationship between tables is the foreign key of a table. A foreign key is a column or columns of data in one table that connects to the primary key data in the original table.

Primary key:- The very minimum set of characteristics necessary to identify each row in a database is known as the primary key. It is chosen from a list of potential keys. The primary key might be any candidate's key.

Reference key:- The primary key that is used as a reference in the other table is known as the Reference key.

In context of a relation in database, choose a false statement:

  1. There can be more than one super keys.
  2. A candidate key is a minimal super key.
  3. One of the candidate keys is designated as primary key.
  4. Primary key is obtained by removing one or more attributes from a candidate key.

Answer (Detailed Solution Below)

Option 4 : Primary key is obtained by removing one or more attributes from a candidate key.

Query Language Question 15 Detailed Solution

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Super Key

  • It is an attribute (or set of attributes) that is used to uniquely identifies all attributes in a relation. 
  • All super keys can’t be candidate keys but its reverse is true. 
  • There can be more than one super key.
  • In relation, the number of super keys is always greater than or equal to the number of candidate keys.
  • There always exists at least one super key in a table.

Candidate key

  • It is a minimal set of attributes necessary to identify a tuple; this is also called a minimal super key.
  • Candidate key can be more than one.
  • One of the candidate keys is designated as the primary key.

Primary key

  • Candidate key from the table selected by the database administrator to uniquely identify tuples in a table known as the primary key.
  • Since the candidate is a minimal set of attributes necessary to identify a tuple therefore the primary key is also  a minimal set of attributes necessary to identify a tuple and hence primary key cannot be obtained by removing one or more attributes from a candidate key.

Therefore option 4 is false

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