Precipitation MCQ Quiz - Objective Question with Answer for Precipitation - Download Free PDF
Last updated on May 8, 2025
Latest Precipitation MCQ Objective Questions
Precipitation Question 1:
In a Symons rain gauge, the collected rainfall is measured using:
Answer (Detailed Solution Below)
Precipitation Question 1 Detailed Solution
Explanation:
A Symons rain gauge is a non-recording type of rain gauge. It collects rain in a cylindrical container, and the collected water is then measured using a measuring glass or cylinder with a graduated scale to determine the depth of rainfall manually, usually in millimeters.
Additional Information A digital display –
- Digital displays are used in modern automated rain gauges, not in the traditional Symons rain gauge.
- Symons rain gauge is a manual instrument and does not involve electronics or digital readouts.
A rotating drum –
- This is typically found in self-recording rain gauges (like the tipping bucket type with chart recorders), not in the Symons type.
- The Symons rain gauge does not use any mechanical recording device.
A pressure sensor –
- Pressure sensors are used in advanced weather instruments but are not part of the Symons rain gauge design.
Precipitation Question 2:
In isohyets, the line joining points on a map where
Answer (Detailed Solution Below)
Precipitation Question 2 Detailed Solution
Isohyets: It is a line joining points of equal rainfall for a given interval. Isohyets are contours of equal precipitation analogous to contour lines on a topographic map.
In the isohyetal method, precipitation values are plotted at their respective stations on a suitable base map, and isohyets are drawn to create an isohyet map.
Precipitation Question 3:
Identify the form of precipitation with the following description.
'It is frozen rain drops cooled to the ice stage while falling through air at sub-freezing temperature."
Answer (Detailed Solution Below)
Precipitation Question 3 Detailed Solution
Different forms of Precipitation are as follows:
i) Rain: It is the most common form of precipitation. In this the water droplet size are larger than 0.5 mm and smaller than 6 mm.
On the basis of intensity, rainfall is classified as:
Type |
Intensity (mm/hr) |
Light rain |
2.5 |
Moderate rain |
2.5 - 7.5 |
Heavy rain |
7.5 |
ii) Snowfall:
- Snowfall is another important form of precipitation. Snow is made up of ice crystals which usually combine to form flakes.
- When these flakes reach the earth’s surface then snowfall occurs. The average density of snow is 0.1 g/cm3.
iii) Drizzle:
- A fine sprinkle of numerous water droplets which have size less than 0.5 mm and intensity of these water droplets is less than 1 mm/hr, then we call them drizzle.
iv) Glaze:
- When the water droplet (rain or drizzle) come in contact with ground which have a temperature near about 0° C or less than it, these water drops freeze and form ice coating on ground surface which is called glaze or freezing rain.
v) Sleet:
- It is frozen raindrops which have transparent grains. These are formed when rainfall is at subfreezing temperature.
- Sleet denotes both rain and snow and the size of sleet is less than 5 mm.
vi) Hail:
- It is a large size of snow which have size greater than 8 mm. They are in the form of irrigator pellets or lumps of ice.
Precipitation Question 4:
A rainfall of 1.6 cm occurred in a 5-hour storm, and the Φ-index was 0.20 cm/hour. How much was the rainfall excess?
Answer (Detailed Solution Below)
Precipitation Question 4 Detailed Solution
Explanation:
ϕ Index:
- It gives the total runoff depth of a catchment is defined as the constant infiltration capacity that would yield the actual total runoff for a given rainfall amount and is represented as
Φ = (P-R/t)
Φ-Index = (Precipitation-Total Runoff Depth/Duration of Excess Rainfall)
Calculation:
Rainfall excess = i = P - Φ × t
i = 1.6 - 0.20 × 5 = 0.6 cm = 6 mm
Precipitation Question 5:
Which of the following factors does NOT influence the type and amount of precipitation that falls in a given area?
Answer (Detailed Solution Below)
Precipitation Question 5 Detailed Solution
Explanation:
Factors Influencing Precipitation
The type and amount of precipitation that falls in a given area are influenced by several factors such as vegetation type, orographic lift, Earth's axial tilt, and proximity to bodies of water. Here's a detailed analysis of each option:
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"Vegetation type" (Influences Precipitation)
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Vegetation can influence precipitation through processes like transpiration and affecting local humidity levels.
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Dense vegetation can lead to increased local rainfall due to higher moisture content in the air.
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"Orographic lift" (Influences Precipitation)
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Orographic lift occurs when air is forced to rise over a mountain range, causing cooling and condensation, leading to rainfall.
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This process is responsible for significant precipitation on the windward side of mountains.
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"Earth's axial tilt" (Does NOT directly influence Precipitation)
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Earth's axial tilt primarily affects the seasons and the distribution of solar energy, not the immediate type and amount of precipitation in a specific area.
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While it does influence broader climate patterns, its impact on local precipitation is indirect.
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Therefore, it is the correct answer for the factor that does NOT directly influence precipitation.
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"Proximity to bodies of water" (Influences Precipitation)
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Bodies of water provide a significant source of moisture for the atmosphere, leading to increased evaporation and subsequent precipitation.
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Regions close to large water bodies often experience higher humidity and more rainfall.
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Top Precipitation MCQ Objective Questions
Which one of the following points should be kept in mind while selecting the site for a rain gauge station?
Answer (Detailed Solution Below)
Precipitation Question 6 Detailed Solution
Download Solution PDFConcept
While selecting the site for rain gauge stations the following points should be considered:
- The site should be on level ground and on open space. It should never be on sloping ground.
- The site should be such that the distance between the gauge station and the objects (like a tree, building, etc) should be at least twice the height of the objects.
- In the hilly area, where level ground is not available, the site should be so selected that the station may be well shielded from high wind.
- The site should be easily accessible to the observer.
- The site should be well protected from cattle by wire fencing.
Rainfall with an intensity of 6 mm/h is classified as:
Answer (Detailed Solution Below)
Precipitation Question 7 Detailed Solution
Download Solution PDFConcept:
Precipitation- It is the fall of water in various forms on the earth from the clouds.
The usual forms of precipitation are as follows:
Forms of precipitation |
Characteristics |
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Water droplets of size 0.5mm to 6mm Based on its intensity it is classified as:
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Ice crystals of density 0.1 g/cc |
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Water droplets of size < 0.5 mm and intensity < 1 mm/hr |
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Water droplets in contact with cold water surface (0℃) |
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Frozen raindrops |
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Lumps of Ice > 8 mm |
Note:
A catchment has 5 rain gauge stations, for a 6% error in estimation of mean rainfall and coefficient of variation of rainfall values of existing stations is 20. Determine additional no. of stations needed
Answer (Detailed Solution Below)
Precipitation Question 8 Detailed Solution
Download Solution PDFConcept
The optimum number of rain gauges is given by
\(N = {\left( {\frac{{{C_v}}}{\epsilon}} \right)^2} \)
Where,
Cv is the coefficient of variation
ϵ is error percentage
The coefficient of variation is given by
\({C_v} = \frac{{{\sigma _{n - 1}}}}{{\bar P}}\)
Where,
\(\bar P\) is average rainfall
σ is the standard deviation
Calculation:
Given,
Number of Rain gauge = 5, error = 6 %, Cv = 20
The optimum number of rain gauge → n = (20/6)2 = 11.11 we take it as 12
∴ The number of Optimum Gauges = 12.
As asked about the additional number of Stations i.e. 12 - 5 = 7.
∴ Number of Additional Stations = 7
Under the same conditions, which one of the following is most suitable for using the Isohyetal method to evaluate mean aerial depth of rainfall?
Answer (Detailed Solution Below)
Precipitation Question 9 Detailed Solution
Download Solution PDFExplanation:
Isohyetal method:
- This method is used to estimate the mean precipitation across an area by drawing lines of equal precipitation and uses topographical and other data to yield reliable estimates.
- Isohyets are contours of equal ppt analogous to contour lines on a topographical map.
- In the isohyetal method, ppt values are plotted at their respective station on a suitable base map, and isohyets are drawn to create an isohyetal map.
- Isohyetal lines are based on interpolation between rain gauge stations. While constructing isohyets, it is assumed that rainfall between 2 stations varies linearly, unless abrupt changes in topography indicate otherwise.
- So, a gently sloped basin is most suitable for linearly changing rainfall and hence for the isohyetal method
For Undulating countries, rainfall will not vary linearly, and for the plain country, rainfall is assumed to be constant over the area, hence the isohyetal method doesn't yield accurate results for these 2 cases but can be used if required
Snow precipitation is generally not taken into consideration for drawing isohyets
The coefficient of variation of the rainfall for six rain gauge stations in catchments was found to be 29.54%. The optimum number of stations in the catchments for an admissible 10% error in the estimation of the mean rainfall will be :
Answer (Detailed Solution Below)
Precipitation Question 10 Detailed Solution
Download Solution PDFConcept:
N = \({\left( {\frac{{{{\rm{C}}_{\rm{v}}}}}{{\rm{\varepsilon }}}} \right)^2}\)
where
N = optimum number of rain gauges
Cv = Coefficient of variation
\({{\rm{C}}_v} = \frac{{\rm{\sigma }}}{{{\rm{\bar X}}}} \times 100\)
σ = standard deviation = \(\sqrt {\frac{{\sum {{\left( {{{\rm{X}}_{\rm{i}}} - {\rm{\bar X}}} \right)}^2}}}{{{\rm{n}} - 1}}} \)
X̅ = Mean Precipitation
n = number of rain gauge stations
Calculation:
Given,
Coefficient of variation (Cv) = 29.54%
The allowable degree of error in the estimate of mean rainfall (ϵ) = 10
N = \({\left( {\frac{{{{\rm{C}}_{\rm{v}}}}}{{\rm{\varepsilon }}}} \right)^2}\)
\(\epsilon{} = \frac{{{C_v}}}{{\sqrt n }}\)
\(10 = \frac{{29.54}}{{\sqrt n }}\)
\(\sqrt n = \frac{{29.54}}{{10}} =2.95\)
n = 8.72
n ≈ 9
The theissen weights of 4 rain gauges A, B, C and D covering a river basin are 0.15, 0.25, 0.30 and 0.30 respectively. If the average depth of rainfall for the basin is 5 cm and rainfall recorded at B, C and D are 5 cm, 4 cm and 5 cm respectively, what is the rainfall at A?
Answer (Detailed Solution Below)
Precipitation Question 11 Detailed Solution
Download Solution PDFConcept:
Thiessen polygon method:
In this method, the rainfall recorded at each station is given a weightage on the basis of area closest to the station. The average precipitation over the catchment area is given as,
\({P_{avg}} = \frac{{{P_1}{A_1} + {P_2}{A_2} + {P_3}{A_3} + \ldots {P_n}{A_n}}}{{{A_1} + {A_2} + {A_3} + \ldots {A_n}}} = \frac{{{P_1}{A_1} + {P_2}{A_2} + {P_3}{A_3} + \ldots {P_n}{A_n}}}{A}\)
Where, \(\mathop \sum \limits_{i = 1}^n \frac{{{A_i}}}{A}\) is called the weightage factor
Calculation:
Given,
Pavg = 5 cm
PB = 5 cm, PC = 4 cm, PD = 5 cm
PA =?
Weightage factor for station A, B, C and D is given, 0.15, 0.25, 0.30 and 0.30.
∵ We know, The average rainfall
\({P_{avg}} = \frac{{{P_A}{A_A} + {P_B}{A_B} + {P_C}{A_C} + {P_D}{A_D}}}{{{A_A} + {A_B} + {A_C} + {A_D}}} = \frac{{{P_A}{A_A} + {P_B}{A_B} + {P_C}{A_C} + {P_D}{A_D}}}{A}\)
5 = PA × 0.15 + 5 × 0.25 + 4 × 0.30 + 5 × 0.30
5 = PA × 0.15 + 3.95
PA = 7 cm
The total rainfall in a catchment area 1200 km2 during a 6 hours storm is 16 cm. While the surface run-off due to storm is 1.2 × 108 m3. The φ index is
Answer (Detailed Solution Below)
Precipitation Question 12 Detailed Solution
Download Solution PDFConcept:
\(\emptyset - {\rm{index}} = \frac{{{\rm{P}} - {\rm{R}}}}{{\rm{t}}}\)
Where,
R (Runoff) (m): It is defined as the part of water cycle that flows over land as surface water instead of being absorbed into the ground water or evaporated. Runoff is that part of precipitation that appears in uncontrolled surface streams, rivers drains or sewers.
P (Precipitation) (m): It is any liquid or frozen water that forms in the atmosphere and falls back to the earth. Precipitation is any product of the condensation of atmospheric water vapour that falls under gravity from clouds. The main forms of precipitation include drizzle, rain, sleet, snow, ice pellets, graupel and hail.
Infiltration Capacity: It is the rate at which water infiltrates into ground is called infiltration capacity. For consistency, in hydrological calculations, a constant value of infiltration rate for the entire storm duration is adopted.
The average infiltration rate is called the infiltration index and two types of infiltration indices commonly used:
- 𝛗 – Index: It is defined as the rate of infiltration above which volume equals the runoff volume.
- w – index: It is the average infiltration rate during the time when the rainfall intensity exceeds the infiltration rate.
Calculation:
Given, Rainfall (P) = 16cm and t = 6 hours
Runoff \({\rm{R}} = {\rm{\;}}\frac{{1.2{\rm{\;}} \times {{10}^8}}}{{1200 \times {{10}^6}}} = 0.1{\rm{m}} = 10{\rm{cm}}\)
\(\emptyset - {\rm{index}} = \frac{{{\rm{P}} - {\rm{R}}}}{{\rm{t}}} = \frac{{16 - 10}}{6} = \frac{6}{6} = 1{\rm{cm}}/{\rm{hr\;}}\)
How many additional rain gauges are required in a catchment, if the error allowed in estimation of mean rainfall is to be reduced by half than the present one ?
Answer (Detailed Solution Below)
Precipitation Question 13 Detailed Solution
Download Solution PDFConcept:
Optimum number of rain gauges is given by
\(N = {\left( {\frac{{{C_v}}}{ϵ}} \right)^2}\)
Where,
Cv is coefficient of variation
ϵ is error percentage
Coefficient of variation is given by
\({C_v} = \frac{{{\sigma _{n - 1}}}}{{\bar P}}\)
Where,
\(\bar P\) is average rainfall
σ is standard deviation
Calculation
Optimum number of rain gauge is
\(N = {\left( {\frac{{{C_v}}}{ϵ}} \right)^2}\)
When error reduced to half, ϵ' = 0.5ϵ
\(n = {\left( {\frac{{{C_v}}}{0.5ϵ}} \right)^2} =4{\left( {\frac{{{C_v}}}{ϵ}} \right)^2} \)
Additional rain gauges = n - N = \(4{\left( {\frac{{{C_v}}}{ \in }} \right)^2} - 1{\left( {\frac{{{C_v}}}{ \in }} \right)^2} = 3{\left( {\frac{{{C_v}}}{ \in }} \right)^2}\)= 3N
So, Additional rain gauges are required in a catchment = Thrice the present number
Imaginary lines joining equal ___________ is known as isohyets
Answer (Detailed Solution Below)
Precipitation Question 14 Detailed Solution
Download Solution PDFConcept-
Isohyets are the imaginary lines joining the points of equal rainfall.
An isohyet is a contour line drawn on maps that connect places or points that received the same amount of rainfall or precipitation at a given period of time.
It is used to represent areas that received a similar amounts of rain or equal density of rain during a particular storm.
These lines help to estimate the various rainfall parameters like the minimum and maximum, an average rainfall of a particular region.
A map formed by these isohyetal lines is called the isohyetal map.
Important Points
Name of the line |
Points of equal |
Isohyets |
Rainfall |
Contour |
Elevation |
Isoclinic |
Dip |
Isogonic |
Magnetic declination |
Isobars |
Pressure |
Isohume |
Humidity |
Isotherm |
Temperature |
Isohel |
Duration of sunshine |
The equipment used for the measurement of Evapotranspiration for a given vegetation type in the fields is:
Answer (Detailed Solution Below)
Precipitation Question 15 Detailed Solution
Download Solution PDFExplanation:
Instruments used in the measurement
Instrument |
Use |
Psychrometer |
Relative humidity |
Hygrometer |
Humidity |
Tensiometer |
Capillary potential |
Anemometer |
Wind velocity |
Ombrometer/pluviometer |
Rainfall depth |
Lysimeter |
Evapotranspiration |
Atmometer |
Evaporation |
Phytometer |
Transpiration |
Permeameter |
Hydraulic conductivity |
Rainfall simulator |
Infiltration capacity |