Limit and Continuity MCQ Quiz - Objective Question with Answer for Limit and Continuity - Download Free PDF

Last updated on May 20, 2025

Latest Limit and Continuity MCQ Objective Questions

Limit and Continuity Question 1:

If f(x) = \frac{\pi}{2}\end{array}\right.\), is continuous at x = , then

  1. m = 1, n = 0
  2. m =  + 1
  3. n = 
  4. More than one of the above

Answer (Detailed Solution Below)

Option 3 : n = 

Limit and Continuity Question 1 Detailed Solution

Concept:

A function f(x) is continuous at x = a, if  f(x) = f(x) = f(a).

Calculation:

Given: f(x) = \frac{\pi}{2}\end{array}\right.\)

f() = m ×  + 1

Left-hand limit = 

Applying the limits:

Left- hand limit = m ×  + 1

Right-hand limit = 

Applying the limits:

 

Right-hand limit = 1 + n

For the function to be continuous at x = ,

Left-hand limit = Right-hand limit = f(π/2)

⇒ m×  + 1 = 1 + n

⇒ n = 

The correct answer is n =  .

Limit and Continuity Question 2:

The function f(x) = x Sin (1/x), If x = 0 and f(0) = 1 has discontinuity at _________

  1. 3
  2. 0
  3. 1
  4. More than one of the above

Answer (Detailed Solution Below)

Option 2 : 0

Limit and Continuity Question 2 Detailed Solution

Concept:

If a function is continuous at a point a, then

sin(∞) = a, Where -1≤ a ≤ 1

Calculation:

Given:

f(0) = 1

f(x) = x sin (1/x)

Checking continuity at x = 0

L.H.L

= 0 × sin(∞)

= 0 

R.H.L

= f(0) = 1

L.H.L ≠ R.H.L

Hence, function is discontinuous at x = 0.

Limit and Continuity Question 3:

The value of k which makes the function defined by f(x) = , continuous at x = 0 is

  1. 8
  2. 1
  3. –1
  4. None of the above

Answer (Detailed Solution Below)

Option 4 : None of the above

Limit and Continuity Question 3 Detailed Solution

Concept:

If a function is continuous at x = a, then L.H.L = R.H.L = f(a).

Left hand limit (L.H.L) of f(x) at x = a is  

Right hand limit (R.H.L) of f(x) at x = a is 

Calculation:

Given f(x) = ,
f(0) = k

Left hand limit (L.H.L) of f(x) at x = 0 is 

=  

We know that -1 ≤ sin θ ≤ 1 

⇒ - 1 ≤  ≤ 1

∴   is a finite value.

Let   = a

∴ L.H. L = - a

Right hand limit (R.H.L) of f(x) at x = 0 is 

=  

R.H.L. = a   

Clearly, L.H.L. ≠  R.H.L.

Hence, there does exist any value of k for which the function f(x) is continuous at x = 0.

Limit and Continuity Question 4:

If f(x)=|x|, then f(x) is 

  1. Continuous for all x
  2. Differentiable at x = 0
  3. Neither continuous nor differentiable at x = 0
  4. continuous but not differentiable

Answer (Detailed Solution Below)

Option 1 : Continuous for all x

Limit and Continuity Question 4 Detailed Solution

Concept:

The function f(x) is continuous at x = a if

 f(a-) = f(a) = f(a+)

Calculation:

Given, f(x) = |x| 

For x ≥ 0, f(x) = x

and for x

So function is continuous for x > 0 and x

At x = 0, 

f(0-) = f(0) = f(0+) = 0

⇒ f(x) is continuous at x = 0

∴ The correct answer is option (1).

Limit and Continuity Question 5:

If f(x)=|x|, then f(x) is 

  1. Continuous for all x
  2. Differentiable at x = 0
  3. Neither continuous nor differentiable at x = 0
  4. continuous but not differentiable

Answer (Detailed Solution Below)

Option 1 : Continuous for all x

Limit and Continuity Question 5 Detailed Solution

Concept:

The function f(x) is continuous at x = a if

 f(a-) = f(a) = f(a+)

Calculation:

Given, f(x) = |x| 

For x ≥ 0, f(x) = x

and for x

So function is continuous for x > 0 and x

At x = 0, 

f(0-) = f(0) = f(0+) = 0

⇒ f(x) is continuous at x = 0

∴ The correct answer is option (1).

Top Limit and Continuity MCQ Objective Questions

Answer (Detailed Solution Below)

Option 3 : 8

Limit and Continuity Question 6 Detailed Solution

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Concept:

Calculation:

Let 

If x → ∞ then t → 0

= 8 × 1 

= 8 

Answer (Detailed Solution Below)

Option 3 : 4

Limit and Continuity Question 7 Detailed Solution

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Concept:

  • 1 - cos 2θ = 2 sin2 θ

 

Calculation:

          (1 - cos 2θ = 2 sin2 θ)

= 4 × 1 = 4

Answer (Detailed Solution Below)

Option 2 : 1

Limit and Continuity Question 8 Detailed Solution

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Concept:

 

Calculation:

As we know  and 

Therefore,  and 

Hence 

Answer (Detailed Solution Below)

Option 3 :

Limit and Continuity Question 9 Detailed Solution

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Calculation:

We have to find the value of 

       [Form ]

This limit is of the form , Here, We can cancel a factor going to ∞  out of the numerator and denominator.

Factor x becomes ∞ at x tends to ∞, So we need to cancel this factor from numerator and denominator.

Answer (Detailed Solution Below)

Option 2 : 1

Limit and Continuity Question 10 Detailed Solution

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Calculation:

We have to find the value of 

       [Form ]

This limit is of the form , Here, We can cancel a factor going to ∞  out of the numerator and denominator.

Factor x2 becomes ∞ at x tends to ∞, So we need to cancel this factor from numerator and denominator.

The value of  is

  1. 1
  2. -1
  3. 0
  4. Does not exist

Answer (Detailed Solution Below)

Option 4 : Does not exist

Limit and Continuity Question 11 Detailed Solution

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Concept:

For a limit to exist, Left-hand limit and right-hand limit must be equal.

Calculations:

For a limit to exist Left-hand limit and right-hand limit must be equal.

|x| can have two values 

|x | = - x when x is negative 

|x| = x when x is positive.

 = 

​ = 

Here, 

Hence, does not exist

Examine the continuity of a function f(x) = (x - 2) (x - 3)

  1. Discontinuous at x = 2
  2. Discontinuous at x = 2, 3
  3. Continuous everywhere
  4. Discontinuous at x = 3

Answer (Detailed Solution Below)

Option 3 : Continuous everywhere

Limit and Continuity Question 12 Detailed Solution

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Concept:

  • We say f(x) is continuous at x = c if

LHL = RHL = value of f(c)

i.e., 

Calculation:

            (a ϵ Real numbers)

∴ f(x) = f(a), So continuous at everywhere

Important tip:

Quadratic and polynomial functions are continuous at each point in their domain

If  is continuous at x = 0, then k = ?

Answer (Detailed Solution Below)

Option 4 :

Limit and Continuity Question 13 Detailed Solution

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Concept:

Definition:

  • A function f(x) is said to be continuous at a point x = a in its domain, if  exists or or if its graph is a single unbroken curve at that point.
  • f(x) is continuous at x = a ⇔ .

 

Formulae:

 

Calculation: 

Since f(x) is given to be continuous at x = 0, .

Also,  because f(x) is same for x > 0 and x

 

.

Answer (Detailed Solution Below)

Option 4 :

Limit and Continuity Question 14 Detailed Solution

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Concept:

  • .
  • .
  • .
  • .

 

Indeterminate Forms: Any expression whose value cannot be defined, like , , 00, ∞0 etc.

  • For the indeterminate form , first try to rationalize by multiplying with the conjugate, or simplify by cancelling some terms in the numerator and denominator. Else, use the L'Hospital's rule.
  • L'Hospital's Rule: For the differentiable functions f(x) and g(x), the , if f(x) and g(x) are both 0 or ±∞ (i.e. an Indeterminate Form) is equal to the  if it exists.

 

Calculation:

 is an indeterminate form. Let us simplify and use the L'Hospital's Rule.

.

We know that , but  is still an indeterminate form, so we use L'Hospital's Rule:

, which is still an indeterminate form, so we use L'Hospital's Rule again:

, which is still an indeterminate form, so we use L'Hospital's Rule again:

.

∴ .

If  is a continuous function at x = 0, then the value of k is:

  1. 2
  2. 1
  3. None of these

Answer (Detailed Solution Below)

Option 4 : None of these

Limit and Continuity Question 15 Detailed Solution

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Concept:

Definition:

  • A function f(x) is said to be continuous at a point x = a in its domain, if  exists or or if its graph is a single unbroken curve at that point.
  • f(x) is continuous at x = a ⇔ .


Calculation:

For x ≠ 0, the given function can be re-written as:

Since the equation of the function is same for x 0, we have:

For the function to be continuous at x = 0, we must have:

⇒ K = .

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