Ketones MCQ Quiz - Objective Question with Answer for Ketones - Download Free PDF

Last updated on Apr 18, 2025

Latest Ketones MCQ Objective Questions

Ketones Question 1:

The structure of the product of the following reaction is:
F4 Vinanti Teaching 10.05.23 D15

  1. F4 Vinanti Teaching 10.05.23 D16
  2. F4 Vinanti Teaching 10.05.23 D17
  3. F4 Vinanti Teaching 10.05.23 D18
  4. F4 Vinanti Teaching 10.05.23 D19
  5. None of the above  

Answer (Detailed Solution Below)

Option 2 : F4 Vinanti Teaching 10.05.23 D17

Ketones Question 1 Detailed Solution

Explanation:-

F4 Vinanti Teaching 10.05.23 D20
NaBH4 can reduce aldehyde and ketone functional groups into primary and secondary alcohol respectively.

Ketones Question 2:

Match List - I and List - II.

 

List - I

 

List - II

(a)


F1 Madhuri UG Entrance 03.10.2022 D29

(i)

Br2/NaOH

(b)


F1 Madhuri UG Entrance 03.10.2022 D30


(ii)

H2/Pd – BaSO4

(c)


F1 Madhuri UG Entrance 03.10.2022 D31

(iii)

Zn(Hg)/Conc.HCI

(d)


F1 Madhuri UG Entrance 03.10.2022 D32

(iv)

CI2/Red P, H2O

Choose the correct answer from the options given below:

  1. (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
  2. (a) - (iii), (b) - (i), (c) - (iv), (d) - (ii)
  3. (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
  4. (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
  5. (a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)

Answer (Detailed Solution Below)

Option 4 : (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

Ketones Question 2 Detailed Solution

Explanation:

First, it is important to understand each reaction :

 
F1 Madhuri UG Entrance 03.10.2022 D33

This reaction is known as Rosenmund reduction. It involves the conversion of acyl chlorides into an aldehyde. It is a hydrogenation process where H2 reacts with an acyl chloride in presence of a catalyst ( Pd-BaSO4).
F1 Madhuri UG Entrance 03.10.2022 D34

This reaction is known as the Hell-Volhard Zelinsky reaction. Carboxylic acids with one or more alpha-hydrogen atoms react with Cl/Br2 in presence of Red P resulting in the formation of alpha-halocarboxylic acids.
F1 Madhuri UG Entrance 03.10.2022 D35

This reaction is known as the Hofmann bromamide degradation reaction. This method is used for the preparation of primary amine from amide by treating it with bromine in an aqueous ethanolic solution of NaOH.
F1 Madhuri UG Entrance 03.10.2022 D36

This reaction is known as Clemmensen's reduction. It involves the reduction of carbonyl compounds to alkanes using Zn-Hg amalgam and conc.HCl.

Answer: According to all these reactions, option (4)  : (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii) , is correct.

Ketones Question 3:


F1 Madhuri UG Entrance 03.10.2022 D43

Which of the following reagent is suitable for the preparation of the product in the above reaction?

  1. NaBH4
  2. NH2 – NH2 / \(\rm C_2H_5 \overset{\oplus}{O}\overset{\oplus}{N}a\)
  3. Ni / H2
  4. Red P + Cl2
  5. AlCl3

Answer (Detailed Solution Below)

Option 2 : NH2 – NH2 / \(\rm C_2H_5 \overset{\oplus}{O}\overset{\oplus}{N}a\)

Ketones Question 3 Detailed Solution

Concept:

Wolf-Kischner reduction - 

  • It is used to reduce the carbonyl group into alkane.
  • In this reaction, hydrazine (- NH2-NH2) in presence of a strong base is used as a reducing agent.
  • The reaction occurs in the high protic solvent.

,
F1 Madhuri UG Entrance 03.10.2022 D44

  • N2 is released in the reaction.
  • Hydrazine is converted into nitrogen gas.

Explanation:

In the given reaction -


F1 Madhuri UG Entrance 03.10.2022 D45

The reaction follows Wolf Kischner's reduction as -CO reduced into corresponding alkane without harming the other double bonds.

Hence, hydrazine in presence of a strong base is used a reducing agent.

∴ NH2 – NH2 / \(\rm C_2H_5 \overset{\ominus}{O}\overset{\oplus}{N}a\) is a reducing agent that works in the given reaction.

The complete reaction will be- 


F1 Madhuri UG Entrance 03.10.2022 D46

Hence, the correct answer is option 2.

Ketones Question 4:

In the following reactions, P, Q, R and S are the major products.

\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CN} \xrightarrow[\text { (ii) } \mathrm{PhMgBr} \text {, then } \mathrm{H}_{2} \mathrm{O}]{\text { (i) } \mathrm{PhMgBr} \text {, then } \mathrm{H}_{3} \mathrm{O}^{\oplus}} \text { P }\)

 

Task Id 1098 Daman (18)

Task Id 1098 Daman (19)

The correct statement(s) about P, Q, R and S is(are)

  1. Both P and Q have asymmetric carbon(s)
  2. Both Q and R have asymmetric carbon(s)
  3. Both P and R have asymmetric carbon(s)
  4. P has asymmetric carbon(s), S does not have any asymmetric carbon

Answer (Detailed Solution Below)

Option :

Ketones Question 4 Detailed Solution

CONCEPT:

Asymmetric Carbon

  • An asymmetric carbon is a carbon atom that is attached to four different groups, making the molecule chiral.
  • In organic synthesis, identifying asymmetric carbons in the final product helps in determining its chirality and properties.

EXPLANATION:

 

Task Id 1098 Daman (110)

  • P: The compound contains a carbon atom bonded to four different groups (CH3, C2H5, OH, and Ph). Hence, P has an asymmetric carbon.
  • Q: The product contains a phenyl ring attached to a carbon with OH, CH3, and Ph. This makes the carbon asymmetric.
  • R: The product contains a central carbon bonded to four different groups (CH2CH3, OH, Ph, and another phenyl group), making it asymmetric.
  • S: The product is an alkyne with no asymmetric carbon as the triple bond and surrounding groups are symmetrical.

Conclusion: P and R have asymmetric carbons.

Ketones Question 5:

In the following reactions, P, Q, R, and S are the major products.

IMG-1100  24-03-25 Sachin kumar Mishra 26

The correct statement(s) about P, Q, R, and S is(are)

  1. P and Q are monomers of polymers dacron and glyptal, respectively. 
  2. P, Q, and R are dicarboxylic acids.
  3. Compounds Q and R are the same.
  4. R does not undergo aldol condensation and S does not undergo Cannizzaro reaction.

Answer (Detailed Solution Below)

Option :

Ketones Question 5 Detailed Solution

CONCEPT:

Organic Reactions and Product Analysis

  • Oxidation of compounds with KMnO4 and KOH yields carboxylic acids.
  • Hydrolysis of esters under alkaline or acidic conditions produces carboxylic acids.
  • Grignard reagents react with CO2 followed by hydrolysis to give carboxylic acids.
  • Cannizzaro reaction occurs only in aldehydes without α-hydrogen atoms.

EXPLANATION:

IMG-1100  24-03-25 Sachin kumar Mishra 27

  • Identify products P, Q, R, and S:
    • P: Formed by oxidation of the side chain in the given compound to carboxylic acid using KMnO4.
    • Q: Ester hydrolysis results in the formation of a carboxylic acid.
    • R: Hydrolysis of the cyanide group and subsequent oxidation produces a carboxylic acid.
    • S: Grignard reagent reacts with CO2 followed by hydrolysis to yield a carboxylic acid, and ammoniacal AgNO3 confirms the absence of Cannizzaro reaction in S.
  • Analyze statements:
    • Statement 1: P and Q are monomers of polymers Dacron and Glyptal.
      The monomers for Dacron are ethylene glycol and terephthalic acid, while the monomers for Glyptal are ethylene glycol and phthalic acid
      This is incorrect.
    • Statement 2: P, Q, and R are dicarboxylic acids. This is incorrect, as only Q and R are dicarboxylic acids.
    • Statement 3: Q and R are the same compounds. This is correct.
    • Statement 4: R does not undergo aldol condensation, and S does not undergo Cannizzaro reaction. This is correct.

Conclusion: The correct statements are  3 and 4.

Top Ketones MCQ Objective Questions

The structure of the product of the following reaction is:
F4 Vinanti Teaching 10.05.23 D15

  1. F4 Vinanti Teaching 10.05.23 D16
  2. F4 Vinanti Teaching 10.05.23 D17
  3. F4 Vinanti Teaching 10.05.23 D18
  4. F4 Vinanti Teaching 10.05.23 D19

Answer (Detailed Solution Below)

Option 2 : F4 Vinanti Teaching 10.05.23 D17

Ketones Question 6 Detailed Solution

Download Solution PDF

Explanation:-

F4 Vinanti Teaching 10.05.23 D20
NaBH4 can reduce aldehyde and ketone functional groups into primary and secondary alcohol respectively.

Match list I with list II

List - I

(Nomenclature)

List - II

(Sturucture)

A.

Acetophenone

I.

F4 Vinanti Teaching 10.05.23 D3

B.

Benzaldehyde

II.

F4 Vinanti Teaching 10.05.23 D4

C.

Benzoic acid

III.

F4 Vinanti Teaching 10.05.23 D5 

D.

Benzophenone

IV.

F4 Vinanti Teaching 10.05.23 D6


Choose the correct answer from the options given below:

  1. A - III, B - I, C - II, D - IV
  2. A - II, B - I, C - IV, D - III
  3. A - I, B - II, C - III, D - IV
  4. A - IV, B - III, C - II, D - I

Answer (Detailed Solution Below)

Option 2 : A - II, B - I, C - IV, D - III

Which of the following reduces Tollens’ reagent?

  1. Cane sugar
  2. Starch
  3. Glucose
  4. More than one of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : Glucose

Ketones Question 8 Detailed Solution

Download Solution PDF

The correct answer is option 3 .

Concept:

  • Ammonia is diluted with silver ions to create Tollens' reagent. Since the silver ion is reduced to metallic silver and the aldehyde is oxidized to carboxylic acids, this reagent is used to separate aldehydes from ketones.
  • This is frequently observed as a "silver mirror" developing inside the test tube.

Explanation:

  • To check if aldehydes are present, use Tollens' reagent. It contains silver ions, which, in the presence of an aldehyde, are converted to metallic silver.
  • Sucrose, often known as cane sugar, hydrolyzes when heated with diluted acid to produce glucose and fructose, both of which are reducing sugars, although it does not directly reduce Tollens' reagent.
  • Starch: Tollen's reagent will not be reduced by starch because it is not a reducing sugar.
  • glucose: Tollens' reagent will be reduced by glucose, a reducing sugar, creating a silver mirror.

Ketones Question 9:

The structure of the product of the following reaction is:
F4 Vinanti Teaching 10.05.23 D15

  1. F4 Vinanti Teaching 10.05.23 D16
  2. F4 Vinanti Teaching 10.05.23 D17
  3. F4 Vinanti Teaching 10.05.23 D18
  4. F4 Vinanti Teaching 10.05.23 D19

Answer (Detailed Solution Below)

Option 2 : F4 Vinanti Teaching 10.05.23 D17

Ketones Question 9 Detailed Solution

Explanation:-

F4 Vinanti Teaching 10.05.23 D20
NaBH4 can reduce aldehyde and ketone functional groups into primary and secondary alcohol respectively.

Ketones Question 10:

Match list I with list II

List - I

(Nomenclature)

List - II

(Sturucture)

A.

Acetophenone

I.

F4 Vinanti Teaching 10.05.23 D3

B.

Benzaldehyde

II.

F4 Vinanti Teaching 10.05.23 D4

C.

Benzoic acid

III.

F4 Vinanti Teaching 10.05.23 D5 

D.

Benzophenone

IV.

F4 Vinanti Teaching 10.05.23 D6


Choose the correct answer from the options given below:

  1. A - III, B - I, C - II, D - IV
  2. A - II, B - I, C - IV, D - III
  3. A - I, B - II, C - III, D - IV
  4. A - IV, B - III, C - II, D - I

Answer (Detailed Solution Below)

Option 2 : A - II, B - I, C - IV, D - III

Ketones Question 10 Detailed Solution

qImage644150efa70fe81b552797d0

F4 Vinanti Teaching 10.05.23 D7

F4 Vinanti Teaching 10.05.23 D3

F4 Vinanti Teaching 10.05.23 D6
F4 Vinanti Teaching 10.05.23 D5

Ketones Question 11:

19-5-2025 IMG-649 Ankit -183 Product (A) is :

  1. 19-5-2025 IMG-649 Ankit -184
  2. 19-5-2025 IMG-649 Ankit -185
  3. 19-5-2025 IMG-649 Ankit -186
  4. 19-5-2025 IMG-649 Ankit -187

Answer (Detailed Solution Below)

Option 4 : 19-5-2025 IMG-649 Ankit -187

Ketones Question 11 Detailed Solution

CONCEPT:

Acid-Catalyzed Rearrangement of Cyclic Ketones

  • The starting compound is a bicyclic compound with two ketone functional groups.
  • When treated with acid (H⁺), cyclic ketones can undergo rearrangement reactions due to the protonation of the carbonyl group, making it more susceptible to ring opening or reorganization.
  • This reaction typically results in the formation of a new, more stable cyclic structure by rearranging the bonds in the molecule.

REACTION EXPLANATION:

  • The given bicyclic compound is treated with an acid (H⁺), which protonates one of the carbonyl groups, making the structure more reactive.
  • This leads to a rearrangement, potentially involving a ring contraction or expansion, to form a new cyclic structure with stabilized keto groups.
  • qImage6713db16591eb2e17c367f4219-5-2025 IMG-649 Ankit -188

CONCLUSION:

The correct option is: Option 4

Ketones Question 12:

Identify product (A) in the following reaction:

qImage668d60d1b70344443687758b

  1. qImage668d60d1b70344443687758e
  2. qImage668d60d2b703444436877590
  3. qImage668d60d2b7034444368775f9
  4. qImage668d60d2b703444436877606

Answer (Detailed Solution Below)

Option 1 : qImage668d60d1b70344443687758e

Ketones Question 12 Detailed Solution

CONCEPT:

Clemmensen Reduction

  • The Clemmensen reduction is a chemical reaction used to reduce ketones or aldehydes to alkanes using zinc amalgam (Zn-Hg) and concentrated hydrochloric acid (HCl).
  • This reaction effectively removes the carbonyl group (C=O) and replaces it with hydrogen atoms (H).
  • qImage66b1fa46419fba7e9c491c1e

Mechanism:-

  • The given compound is a diketone with two carbonyl groups attached to a benzene ring and a cyclohexane ring.
  • Under Clemmensen reduction conditions, both carbonyl groups are reduced to methylene groups (CH2).
  • The resulting product is a compound where the benzene ring is directly attached to the cyclohexane ring via a CH2 group.

qImage66b1fa46419fba7e9c491c2c

Explanation:-

  • The correct structure of the product (A) should have no carbonyl groups and should have two methylene (CH2) groups connecting the benzene ring and the cyclohexane ring.
  • Among the given options, Option 1 matches this structure.

qImage66b1fac6b2f9126d95396f21

The correct answer is Option 1.

Ketones Question 13:

Match the following

Column-1 

Reaction 

Column-2

Product

A F1 Vinanti Teaching 02.03.23 D6 I Cyclohexanol
B F1 Vinanti Teaching 02.03.23 D7 II Benzyl alcohol
C F1 Vinanti Teaching 02.03.23 D8 III Toluene
    IV Benzaldehyde
    V Cyclohexane
The correct match is 

  1. (A - III), (B - IV), (C - V) 
  2. (A - III), (B - II), (C - V) 
  3. (A - III), (B - IV), (C - I) 
  4. (A - II), (B - IV), (C - I)

Answer (Detailed Solution Below)

Option 1 : (A - III), (B - IV), (C - V) 

Ketones Question 13 Detailed Solution

Explanation:

A. The reaction is Clemmenson reduction,

  • Reaction of aldehyde and ketones in zinc amalgam in concn. HCl will reduce the aldehyde or ketone to the corresponding hydrocarbon.

The reaction is shown as - 

F1 Vinanti Teaching 02.03.23 D9

The product formed here is toluene.

B. The reaction is Rosenmund reaction,

  • Pd-BaSO is known as the Rosenmund catalyst.
  • The reaction used to reduce acyl chloride to their corresponding aldehyde using Rosenmund catalyst and H2.

The reaction is shown as - 

F1 Vinanti Teaching 02.03.23 D10

The product of the reaction is benzaldehyde.

C. The reaction is Wolf-Kischner reduction,

  • The carbonyl group of aldehydes and ketones is reduced to corresponding hydrocarbon on treatment with hydrazine(NH2NH2) followed by heatingwith sodium or potassium hydroxide.
  • The reaction proceed through hydrazine intermediate.

The reaction is shown as - 

F1 Vinanti Teaching 02.03.23 D11

The product formed is cyclohexane.

Conclusion:

Matching the given reaction with the product obtained we get, (A - III), (B - IV), (C - V) .

Therefore, the correct answer is option 1.

 

Ketones Question 14:

Match List - I and List - II.

 

List - I

 

List - II

(a)


F1 Madhuri UG Entrance 03.10.2022 D29

(i)

Br2/NaOH

(b)


F1 Madhuri UG Entrance 03.10.2022 D30


(ii)

H2/Pd – BaSO4

(c)


F1 Madhuri UG Entrance 03.10.2022 D31

(iii)

Zn(Hg)/Conc.HCI

(d)


F1 Madhuri UG Entrance 03.10.2022 D32

(iv)

CI2/Red P, H2O

Choose the correct answer from the options given below:

  1. (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
  2. (a) - (iii), (b) - (i), (c) - (iv), (d) - (ii)
  3. (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
  4. (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

Answer (Detailed Solution Below)

Option 4 : (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

Ketones Question 14 Detailed Solution

Explanation:

First, it is important to understand each reaction :

 
F1 Madhuri UG Entrance 03.10.2022 D33

This reaction is known as Rosenmund reduction. It involves the conversion of acyl chlorides into an aldehyde. It is a hydrogenation process where H2 reacts with an acyl chloride in presence of a catalyst ( Pd-BaSO4).
F1 Madhuri UG Entrance 03.10.2022 D34

This reaction is known as the Hell-Volhard Zelinsky reaction. Carboxylic acids with one or more alpha-hydrogen atoms react with Cl/Br2 in presence of Red P resulting in the formation of alpha-halocarboxylic acids.
F1 Madhuri UG Entrance 03.10.2022 D35

This reaction is known as the Hofmann bromamide degradation reaction. This method is used for the preparation of primary amine from amide by treating it with bromine in an aqueous ethanolic solution of NaOH.
F1 Madhuri UG Entrance 03.10.2022 D36

This reaction is known as Clemmensen's reduction. It involves the reduction of carbonyl compounds to alkanes using Zn-Hg amalgam and conc.HCl.

Answer: According to all these reactions, option (4)  : (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii) , is correct.

Ketones Question 15:


F1 Madhuri UG Entrance 03.10.2022 D43

Which of the following reagent is suitable for the preparation of the product in the above reaction?

  1. NaBH4
  2. NH2 – NH2 / \(\rm C_2H_5 \overset{\oplus}{O}\overset{\oplus}{N}a\)
  3. Ni / H2
  4. Red P + Cl2

Answer (Detailed Solution Below)

Option 2 : NH2 – NH2 / \(\rm C_2H_5 \overset{\oplus}{O}\overset{\oplus}{N}a\)

Ketones Question 15 Detailed Solution

Concept:

Wolf-Kischner reduction - 

  • It is used to reduce the carbonyl group into alkane.
  • In this reaction, hydrazine (- NH2-NH2) in presence of a strong base is used as a reducing agent.
  • The reaction occurs in the high protic solvent.

,
F1 Madhuri UG Entrance 03.10.2022 D44

  • N2 is released in the reaction.
  • Hydrazine is converted into nitrogen gas.

Explanation:

In the given reaction -


F1 Madhuri UG Entrance 03.10.2022 D45

The reaction follows Wolf Kischner's reduction as -CO reduced into corresponding alkane without harming the other double bonds.

Hence, hydrazine in presence of a strong base is used a reducing agent.

∴ NH2 – NH2 / \(\rm C_2H_5 \overset{\ominus}{O}\overset{\oplus}{N}a\) is a reducing agent that works in the given reaction.

The complete reaction will be- 


F1 Madhuri UG Entrance 03.10.2022 D46

Hence, the correct answer is option 2.

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