General Design Principles MCQ Quiz - Objective Question with Answer for General Design Principles - Download Free PDF

Last updated on May 12, 2025

Latest General Design Principles MCQ Objective Questions

General Design Principles Question 1:

What are beams fabricated using rolled plates called?

  1. Plate girders
  2. Castellated beams
  3. Hybrid beams
  4. Composite beams

Answer (Detailed Solution Below)

Option 1 : Plate girders

General Design Principles Question 1 Detailed Solution

Explanation:

  1. Plate girders are beams fabricated using rolled plates that are welded or bolted together to form a beam.
  2. These girders are often used in large structures like bridges or buildings where the span is long and the loads are significant.
  3. The plates used in the fabrication of plate girders are usually made of steel and are shaped to form the web and flanges of the girder.

 Additional Information

  1. Castellated beams: These are beams that are created by cutting a regular beam (usually an I-beam) in a pattern and then reassembling it to form a beam with an enlarged web, which helps reduce weight and increase the depth of the beam for larger spans.

  2. Hybrid beams: Hybrid beams combine two or more materials, such as steel and concrete, to take advantage of the benefits of both materials.

  3. Composite beams: These beams combine two materials, typically steel and concrete, where the concrete works in compression and the steel works in tension, offering better load distribution and efficiency.

General Design Principles Question 2:

For a column subjected to bending and compression, the maximum slenderness ratio as per IS 800:2007 is:

  1. 180
  2. 200
  3. 300
  4. 250

Answer (Detailed Solution Below)

Option 1 : 180

General Design Principles Question 2 Detailed Solution

Explanation:

As per IS 800:2007, for steel structures:

  • When a column is subjected to axial compression and bending, the maximum permissible slenderness ratio is 180.

This limit ensures the stability and safety of compression members under combined stresses and helps to prevent buckling.

Additional InformationOther Slenderness Ratio Limits (for context):

  • 250 – For members subjected to axial tension.

  • 350 – For members under compression resulting from wind or earthquake forces only (temporary loads).

  • 180 – For columns under combined axial compression and bending (as in this question).

General Design Principles Question 3:

For the same depth, the heavier section is-

  1. ISLB
  2. ISMB
  3. ISHB
  4. ISWB
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : ISHB

General Design Principles Question 3 Detailed Solution

Concept-

Beam, column, channel, and angle sections are classified as follows:

Beams

a) Indian Standard junior beams (ISJB)

b) Indian Standard light weight beams (ISLB)

c) Indian Standard medium weight beams (ISMB)

d) Indian Standard wide flange beams (ISWB)

Columns/Heavy Weight Beams

a) Indian Standard column sections (ISSC)

b) Indian Standard heavyweight beam (ISHB)

Channels

a) Indian Standard junior channels (ISJC)

b) Indian Standard lightweight channels (ISLC)

c) Indian Standard medium weight channels (ISMC)

d) Indian Standard medium weight parallel flange channels (ISMCP)

Angles

a) Indian Standard equal leg angles (ISA)

b) Indian Standard unequal leg angles (ISA)

General Design Principles Question 4:

Identify the INCORRECT statement related to the maximum slenderness ratio of steel structural elements, according to IS 800: 2007.

  1. The maximum slenderness ratio shall not exceed 350 for a member subjected to compression forces resulting only from combination with wind/earthquake actions, provided the deformation of such a member does not adversely affect the stress in any part of the structure.
  2. Tension members, such as bracings, pre-tensioned to avoid sag, need not satisfy the maximum slenderness ratio limits. 
  3. The maximum slenderness ratio shall not exceed 300 for a compression flange of a beam against lateral torsional buckling.
  4. The maximum slenderness ratio shall not exceed 180 for a member carrying compressive loads resulting from dead loads and imposed loads.

Answer (Detailed Solution Below)

Option 1 : The maximum slenderness ratio shall not exceed 350 for a member subjected to compression forces resulting only from combination with wind/earthquake actions, provided the deformation of such a member does not adversely affect the stress in any part of the structure.

General Design Principles Question 4 Detailed Solution

Explanation:

Statement 1:

"The maximum slenderness ratio shall not exceed 350 for a member subjected to compression forces resulting only from combination with wind/earthquake..."

  • IS 800:2007 Table 3, Sl. No. iii clearly states:
    Limit is 250, not 350.

Hence, this statement is INCORRECT.

Statement 2:

"Tension members, such as bracings, pre-tensioned to avoid sag, need not satisfy slenderness ratio limits."

  • Confirmed by Note (1) below the table:
    Such members are exempted from the slenderness ratio limit.

Correct

Statement 3:

"The maximum slenderness ratio shall not exceed 300 for a compression flange of a beam against lateral torsional buckling."

  • IS 800:2007 Table 3, Sl. No. iv
    ➤ Confirmed as 300.

Correct

Statement 4:

"The maximum slenderness ratio shall not exceed 180 for a member carrying compressive loads from dead and imposed loads."

  • IS 800:2007 Table 3, Sl. No. i
    ➤ Value is 180.

Correct

General Design Principles Question 5:

In the design of members subjected to combined axial force and bending moment, what should be the value constant α1 considered as per IS 800 for I & channel section?

  1. 1.73 + 1.8 m3
  2. 2
  3. 5n ≥ 1
  4. 0

Answer (Detailed Solution Below)

Option 3 : 5n ≥ 1

General Design Principles Question 5 Detailed Solution

Explanation:

As per IS 800

Table 17: Constants \( \alpha_1 \) and \( \alpha_2 \) (Clause 9.3.1.1)

Sl No. Section \( \alpha_1 \) \( \alpha_2 \)
i I and channel \( 5n \geq 1 \) 2
ii Circular tubes 2 2
iii Rectangular tubes \( \frac{1.66}{(1 - 1.13n^2)} \leq 6 \) \( \frac{1.66}{(1 - 1.13n^2)} \leq 6 \)
iv Solid rectangles \( 1.73 + 1.8n^3 \) \( 1.73 + 1.8n^3 \)

NOTE: \( n = N/N_d \)

Top General Design Principles MCQ Objective Questions

When the effect of wind or earthquake load is taken into account, the permissible stress as specified in rivets may be increased by

  1. 33.33%
  2. 50%
  3. 10%
  4. 25%

Answer (Detailed Solution Below)

Option 4 : 25%

General Design Principles Question 6 Detailed Solution

Download Solution PDF

Concept:

According to clause no. 11.1.4 of IS 800: 2007, when the effect of wind or earthquake load is taken into account, the permissible stress as specified in rivets (or in anchor bolts) may be increased by 25%.

Confusion/Mistake Point:

According to clause no. 11.1.4 of IS 800: 2007, when the effect of wind or earthquake load is taken into account, the permissible stress as specified in structural steel member may be increased by 33.33%.

The maximum allowable vertical deflection under live load for a cantilever member supporting brittle cladding in an industrial building is:

  1. Span/240
  2. Span/180
  3. Span/120
  4. Span/150

Answer (Detailed Solution Below)

Option 4 : Span/150

General Design Principles Question 7 Detailed Solution

Download Solution PDF

Explanation:

As per IS 800:2007, Clause No. 5.6.1:

The maximum vertical deflection for cantilever beam:
  • Supported by elastic cladding, deflection is limited to Span/120.
  • Supported by brittle cladding, deflection is limited to Span/150.

The maximum vertical deflection for simply supported beam:

  • Supported by elastic cladding, deflection is limited to Span/240.
  • Supported by brittle cladding, deflection is limited to Span/300.
  • Max deflection < L/325 of the span in general

As per IS 456:2000, Clause 23.2:

The deflection shall generally be limited to the following:

  • The final deflection due to all loads including the effects of temperature, creep, and shrinkage and measured from the as-cast level of the supports of floors, roofs, and all other horizontal members, should not normally exceed span/250.
  • The deflection including the effects of temperature, creep and shrinkage occurring after the erection of partitions and the application of finishes should not normally exceed span/350 or 20 mm whichever is less.

For simply supported beams, the maximum permitted deflection is (As pe IS 800:2007)

  1. 1/325 of the span
  2. 1/300 of the span
  3. 1/350 of the span
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 1/300 of the span

General Design Principles Question 8 Detailed Solution

Download Solution PDF

Explanation:

Maximum permissible deflection in simply supported steel beam other than industrial building is given by = \(\frac{1}{{300}} \times {\bf{Span}}\)

Some of the reason for limiting deflection is:

  • Excessive deflection may create problems for floor or roof drainage.
  • Excessive deflection may lead to crack in the plaster of ceilings & may damage the material attached to or supported by the beam.
  • There may cause undesirable twisting and distortion of connections and connected materials.

Confusion Points

325 is as per IS 800: 1984, Question is asking as per IS 800: 2007, according to which 300 is the correct answer.

For an industrial building, the allowable vertical deflection of a cantilever beam of span 5 m supporting the brittle cladding and subjected to live load is ______.

  1. 41.66 mm
  2. 33.33 mm
  3. 10 mm
  4. 20 mm

Answer (Detailed Solution Below)

Option 2 : 33.33 mm

General Design Principles Question 9 Detailed Solution

Download Solution PDF

Concept:

As per IS 800:2007, Clause No. 5.6.1

The maximum vertical deflection for cantilever beam:

a) Supported by elastic cladding, deflection is limited to Span/120.

b) Supported by brittle cladding, deflection is limited to Span/150.

Calculation:

Span of beam = 5 m = 5000 mm

Vertical Deflection = 5000/150 =  33.33 mm

Additional InformationThe maximum vertical deflection for simply supported beam:

a) Supported by elastic cladding, deflection is limited to Span/240.

b) Supported by brittle cladding, deflection is limited to Span/300.

c) Max deflection < L/325 of the span in general

The permissible maximum deflection of a purlin of 4.5 m which is subjected to live load supporting GI metal sheet and supported by elastic cladding is:

  1. 15 mm
  2. 18.75 mm
  3. 30 mm
  4. 37.5 mm

Answer (Detailed Solution Below)

Option 3 : 30 mm

General Design Principles Question 10 Detailed Solution

Download Solution PDF
Concept: 

Vertical Deflection limits for industrial buildings as per IS 800:2007 are:

a) For Purlins and Girts subjected to live load/wind load supported on elastic cladding, maximum deflection is limited to span / 150.

b) For Purlins and Girts subjected to live load/wind load supported on Brittle cladding, maximum deflection is limited to span / 180.

Calculation:

∴ Permissible maximum deflection = Span/150 = 4500/150 = 30 mm

As per IS : 800 - 2007, the partial safety factor for materials, in which resistance is governed by the ultimate stress, is ______.

  1. 1.10
  2. 0.85
  3. 1.25
  4. 1.05

Answer (Detailed Solution Below)

Option 3 : 1.25

General Design Principles Question 11 Detailed Solution

Download Solution PDF

Explanation:

As per IS 800:2007, Table 5, Partial safety factors for materials are given as:

(i) When resistance is governed by ultimate stress, γm1 = 1.25

(ii) When resistance is governed by yielding, γmo = 1.1

(iii) Resistance of member to buckling,γmo = 1.1

(iv) Resistance of connection:

  • Bolts-Friction Type or Rivets = 1.25
  • Welds = 1.25 (shop fabrications) and 1.5 (Field fabrications)

Match the following.

List – I

List – II

  A)  

Type of beam connection

1.  

Connecting members used

 B)

Framed Connection

2. 

Flange cleats only

C)

Un-stiffened seated connection

3. 

Flange and web clips

D)

Stiffened seated connection

4. 

Web cleat only

  1. A – 1, B – 3, C – 2, D - 4
  2. A – 4, B – 3, C – 2, D - 1
  3. A – 3, B – 1, C – 4, D - 2
  4. A – 3, B – 4, C – 2, D - 1

Answer (Detailed Solution Below)

Option 4 : A – 3, B – 4, C – 2, D - 1

General Design Principles Question 12 Detailed Solution

Download Solution PDF

Types of beam connection: Two or more beams at a junction are connected each other using either flange or web clips.

Framed Connection: Framed connection are usually connected through web cleats only as shown in the figure below:

F1 N.M Deepak 21.02.2020 D2

Stiffened and unstiffened beam seated connections are depicted in the figure below:

F1 N.M Deepak 21.02.2020 D3

It can be clearly observed, the unstiffened connection requires flange cleat only, and an additional connecting member is used for stiffened connection.

Yielding in structural members with partial safety factor as 1.1 is governed by

  1. net area of connected lug angle
  2. sectional area
  3. effective area
  4. gross area

Answer (Detailed Solution Below)

Option 4 : gross area

General Design Principles Question 13 Detailed Solution

Download Solution PDF

Concept:

As per IS 800: 2007 

1. Design strength due to yielding of Gross section.

2. Design strength due to Rupture of Net Section.

As per table 5 of IS 800:2007 partial safety for different mode of failure is given below-

Sr.no

Definitions

Partial Safety Factor

1

Resistance, governed by yielding (γmo)

1.10

2

Resisitane of member to buckling (γmo)

1.10

3

Resistance governed by ultimate stress(γml)

1.25

4

Resistance of connections

Shop Fabrication

Field Fabrication

 

a) Bolts friction type γmf

1.25

1.25

 

b) Bolts Bearing type γmb

1.25

1.25

 

c) Rivets γmr

1.25

1.25

 

d) Welds γmw

1.25

1.50

Find out the working stress if a steel column carries a load of 1.6 MN with a factor of safety of 5. The ultimate stress for steel is 472 MN/m2:

  1. 54.44 MN/m2

  2. 94.44 MN/m2
  3. 84.44 MN/m2
  4. 44.44 MN/m2

Answer (Detailed Solution Below)

Option 2 : 94.44 MN/m2

General Design Principles Question 14 Detailed Solution

Download Solution PDF

Concept:

Factor of safety (FOS) = Ultimate stress / Working stress

Calculation:

Given,

Ultimate stress = 472 MN/m2

FOS = Ultimate stress / Working stress

Working stress = 472 / 5 = 94.4 MN/m2

For steel members exposed to weather and not accessible for repainting, the thickness of steel should not be less than

  1. 4.5 mm
  2. 6 mm
  3. 8 mm
  4. 10 mm

Answer (Detailed Solution Below)

Option 3 : 8 mm

General Design Principles Question 15 Detailed Solution

Download Solution PDF

Concept:

Following are the specifications for steel member exposed to weather:

  • When the steelwork is directly exposed to weather and is fully accessible for cleaning and repainting the thickness shall not be less than 6 mm.
  • When the steelwork directly exposed to weather and is not accessible for cleaning and repainting the thickness shall not be less than 8 mm.
  • When the steelwork is not directly exposed to weather, the thickness of steel in main members shall not be less than 6 mm.
  • When the steelwork is not directly exposed to weather, the thickness of steel in secondary members shall not be less than 6 mm.
Get Free Access Now
Hot Links: teen patti cash teen patti baaz teen patti list teen patti king teen patti casino apk