Efficiency of Joint MCQ Quiz - Objective Question with Answer for Efficiency of Joint - Download Free PDF
Last updated on Apr 10, 2025
Latest Efficiency of Joint MCQ Objective Questions
Efficiency of Joint Question 1:
Figure shows riveted joint, where, Pt = tensile resistance of plate per pitch length (N), p = pitch of rivets (mm), t = thickness of plate (mm), σt = permissible tensile stress of plate material (N/mm2). The tensile resistance of the plate between two rivets is given by:
Answer (Detailed Solution Below)
Efficiency of Joint Question 1 Detailed Solution
Concept:
In a riveted joint, the tensile resistance of the plate is determined based on the net cross-sectional area left between rivet holes.
\( P_t = (\text{Net Area}) \times \sigma_t \)
Net area between two rivets = \( (p - d) \cdot t \)
Given:
\( p \) = pitch of rivets (mm)
\( d \) = diameter of rivet hole (mm)
\( t \) = thickness of plate (mm)
\( \sigma_t \) = permissible tensile stress of plate material (N/mm2)
Calculation:
\( P_t = (p - d) \times t \times \sigma_t \)
Efficiency of Joint Question 2:
What will be the efficiency of single riveted lap joint of 10 mm thick plate with rivet diameter of 20 mm having the pitch of 50 mm? [Given: Permissible tensile stress in plate = 150 MPa; Permissible shear stress in rivet = 100 MPa; Permissible crushing stress in rivets = 200 MPa; π = 3.14]
Answer (Detailed Solution Below)
Efficiency of Joint Question 2 Detailed Solution
Concept:
The efficiency of a riveted joint is the ratio of the strength of the joint (minimum of tearing, shearing, or crushing strength) to the strength of the solid plate without holes.
Given:
Plate thickness, t = 10 mm
Rivet diameter, d = 20 mm
Pitch of rivets, p = 50 mm
Permissible tensile stress in plate = 150 MPa
Permissible shear stress in rivet = 100 MPa
Permissible crushing stress in rivet = 200 MPa
π = 3.14
Calculation:
Tearing strength of plate, \( P_t = (p - d) \times t \times \sigma_t = (50 - 20) \times 10 \times 150 = 45000~N \)
Shearing strength of rivet, \( P_s = \frac{\pi}{4} \times d^2 \times \tau = \frac{3.14}{4} \times 20^2 \times 100 = 31400~N \)
Crushing strength of rivet, \( P_c = d \times t \times \sigma_c = 20 \times 10 \times 200 = 40000~N \)
Strength of joint is minimum of tearing, shearing and crushing: \( P = \min(45000, 31400, 40000) = 31400~N \)
Strength of solid plate (without rivet hole), \( P_{solid} = p \times t \times \sigma_t = 50 \times 10 \times 150 = 75000~N \)
Efficiency of the joint, \( \eta = \frac{P}{P_{solid}} \times 100 = \frac{31400}{75000} \times 100 = 41.86\% \)
Efficiency of Joint Question 3:
The efficiency of the circumferential lap joint is obtained as
(where p1 is the pitch of the rivets for the lap joint and d is the diameter of the rivet hole)
Answer (Detailed Solution Below)
Efficiency of Joint Question 3 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{η _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{η _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore η = \frac{{p - d}}{p}\)
if p1 is the pitch of the rivets for the lap joint and d is the diameter of the rivet hole, then the above equation will be written as:
\(\therefore η = \frac{{p_1 - d}}{p_1}\)
Efficiency of Joint Question 4:
If the ratio of the diameter of the rivet hole to the pitch of the rivets is 0.3 mm then the percentage tearing efficiency of this riveted joint is?
Answer (Detailed Solution Below) 70
Efficiency of Joint Question 4 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of the main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as the tearing strength or tearing value of the plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{η _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{η _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore η = \frac{{p - d}}{p}\)
Calculation:
Given: d/p = 0.3,
Tearing efficiency,
\(η =1-\frac{d}{p}\)
⇒ η = 1 - 0.3
⇒ η = 0.7
⇒ η = 70%
Efficiency of Joint Question 5:
If the tearing efficiency of a riveted joint is 75% then the ratio of diameter of rivet to the pitch is equal to:
Answer (Detailed Solution Below)
Efficiency of Joint Question 5 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.75
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.75 \Rightarrow \frac{d}{p} = 0.25\)
Top Efficiency of Joint MCQ Objective Questions
The tearing resistance of the plate in single riveted butt joint is 35 kN. The shearing resistance and the crushing resistance of the rivet are 20 kN and 30 kN, respectively. Determine the efficiency of rivet joint and assume the strength of plate as 25 kN.
Answer (Detailed Solution Below)
Efficiency of Joint Question 6 Detailed Solution
Download Solution PDFConcept:
Riveted joint:
- The permanent joining of parts with the help of rivets is called a riveted joint.
- Rivets are cylindrical-shaped metal body used to leakproof the joining of dissimilar metals.
- When two pieces of sheet joint with the help of riveted joint such that one sheet overlaps the other one then this type of joint is called lap joint.
The efficiency of the riveted joint is defined as the ratio of the strength of the plate in an unpunched condition.
\(\eta = \frac{{Strength\;of\;riveted\;joint}}{{Strength\;of\;unriveted\;solid\;plate}}\)
As the strength of the riveted joint depends on the tearing strength, shearing strength or crushing strength of the joint, the efficiency can be tearing efficiency, shearing efficiency, and crushing efficiency.
The efficiency of the riveted joint,
\(\eta = \frac{{Lowest\;of\;{P_s},\;{P_t}\;and\;{P_c}}}{P}\)
Where Ps = Shearing resistance, Pt = Tearing resistance, Pc = Crushing resistance, P = Strength of plate.
Calculation:
Given:
Ps = 20 kN, Pc = 30 kN, Pt = 35 kN, P = 25 kN.
Among These Ps is the Lowest
∴ The efficiency of the riveted joint is given by:
\(\eta = \frac{P_s}{P} = \frac{20}{25} = 0.8\)
∴ The efficiency of the rivet joint is 0.8.
If the tearing efficiency of a riveted joint is 60%, then ratio of rivet hole diameter to the pitch of rivets is _____.
Answer (Detailed Solution Below)
Efficiency of Joint Question 7 Detailed Solution
Download Solution PDFConcept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p} \times t\times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.60
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.6 \Rightarrow \frac{d}{p} = 0.4\)
If the tearing efficiency of a riveted joint is 50%, then the ratio of rivet hole diameter to the pitch of rivets is
Answer (Detailed Solution Below)
Efficiency of Joint Question 8 Detailed Solution
Download Solution PDFConcept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.50
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.5 \Rightarrow \frac{d}{p} = 0.5\)
Figure shows riveted joint, where, Pt = tensile resistance of plate per pitch length (N), p = pitch of rivets (mm), t = thickness of plate (mm), σt = permissible tensile stress of plate material (N/mm2). The tensile resistance of the plate between two rivets is given by:
Answer (Detailed Solution Below)
Efficiency of Joint Question 9 Detailed Solution
Download Solution PDFConcept:
In a riveted joint, the tensile resistance of the plate is determined based on the net cross-sectional area left between rivet holes.
\( P_t = (\text{Net Area}) \times \sigma_t \)
Net area between two rivets = \( (p - d) \cdot t \)
Given:
\( p \) = pitch of rivets (mm)
\( d \) = diameter of rivet hole (mm)
\( t \) = thickness of plate (mm)
\( \sigma_t \) = permissible tensile stress of plate material (N/mm2)
Calculation:
\( P_t = (p - d) \times t \times \sigma_t \)
What will be the efficiency of single riveted lap joint of 10 mm thick plate with rivet diameter of 20 mm having the pitch of 50 mm? [Given: Permissible tensile stress in plate = 150 MPa; Permissible shear stress in rivet = 100 MPa; Permissible crushing stress in rivets = 200 MPa; π = 3.14]
Answer (Detailed Solution Below)
Efficiency of Joint Question 10 Detailed Solution
Download Solution PDFConcept:
The efficiency of a riveted joint is the ratio of the strength of the joint (minimum of tearing, shearing, or crushing strength) to the strength of the solid plate without holes.
Given:
Plate thickness, t = 10 mm
Rivet diameter, d = 20 mm
Pitch of rivets, p = 50 mm
Permissible tensile stress in plate = 150 MPa
Permissible shear stress in rivet = 100 MPa
Permissible crushing stress in rivet = 200 MPa
π = 3.14
Calculation:
Tearing strength of plate, \( P_t = (p - d) \times t \times \sigma_t = (50 - 20) \times 10 \times 150 = 45000~N \)
Shearing strength of rivet, \( P_s = \frac{\pi}{4} \times d^2 \times \tau = \frac{3.14}{4} \times 20^2 \times 100 = 31400~N \)
Crushing strength of rivet, \( P_c = d \times t \times \sigma_c = 20 \times 10 \times 200 = 40000~N \)
Strength of joint is minimum of tearing, shearing and crushing: \( P = \min(45000, 31400, 40000) = 31400~N \)
Strength of solid plate (without rivet hole), \( P_{solid} = p \times t \times \sigma_t = 50 \times 10 \times 150 = 75000~N \)
Efficiency of the joint, \( \eta = \frac{P}{P_{solid}} \times 100 = \frac{31400}{75000} \times 100 = 41.86\% \)
Efficiency of Joint Question 11:
The tearing resistance of the plate in single riveted butt joint is 35 kN. The shearing resistance and the crushing resistance of the rivet are 20 kN and 30 kN, respectively. Determine the efficiency of rivet joint and assume the strength of plate as 25 kN.
Answer (Detailed Solution Below)
Efficiency of Joint Question 11 Detailed Solution
Concept:
Riveted joint:
- The permanent joining of parts with the help of rivets is called a riveted joint.
- Rivets are cylindrical-shaped metal body used to leakproof the joining of dissimilar metals.
- When two pieces of sheet joint with the help of riveted joint such that one sheet overlaps the other one then this type of joint is called lap joint.
The efficiency of the riveted joint is defined as the ratio of the strength of the plate in an unpunched condition.
\(\eta = \frac{{Strength\;of\;riveted\;joint}}{{Strength\;of\;unriveted\;solid\;plate}}\)
As the strength of the riveted joint depends on the tearing strength, shearing strength or crushing strength of the joint, the efficiency can be tearing efficiency, shearing efficiency, and crushing efficiency.
The efficiency of the riveted joint,
\(\eta = \frac{{Lowest\;of\;{P_s},\;{P_t}\;and\;{P_c}}}{P}\)
Where Ps = Shearing resistance, Pt = Tearing resistance, Pc = Crushing resistance, P = Strength of plate.
Calculation:
Given:
Ps = 20 kN, Pc = 30 kN, Pt = 35 kN, P = 25 kN.
Among These Ps is the Lowest
∴ The efficiency of the riveted joint is given by:
\(\eta = \frac{P_s}{P} = \frac{20}{25} = 0.8\)
∴ The efficiency of the rivet joint is 0.8.
Efficiency of Joint Question 12:
If the tearing efficiency of a riveted joint is 60%, then ratio of rivet hole diameter to the pitch of rivets is _____.
Answer (Detailed Solution Below)
Efficiency of Joint Question 12 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p} \times t\times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.60
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.6 \Rightarrow \frac{d}{p} = 0.4\)
Efficiency of Joint Question 13:
If the tearing efficiency of a riveted joint is 50%, then the ratio of rivet hole diameter to the pitch of rivets is
Answer (Detailed Solution Below)
Efficiency of Joint Question 13 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.50
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.5 \Rightarrow \frac{d}{p} = 0.5\)
Efficiency of Joint Question 14:
If the ratio of the diameter of rivet hole to the pitch of rivets is 0.5, the tearing efficiency of the rivet joint is
Answer (Detailed Solution Below)
Efficiency of Joint Question 14 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{η _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{η _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore η = \frac{{p - d}}{p}\)
Calculation: \(\frac dp=0.5\)
\(η = \frac{{p - d}}{p}\)
\(η =1 - \frac{d}{p} \Rightarrowη =1-0.5\)
η = 50%
Efficiency of Joint Question 15:
If the tearing efficiency of a riveted joint is 75% then the ratio of diameter of rivet to the pitch is equal to:
Answer (Detailed Solution Below)
Efficiency of Joint Question 15 Detailed Solution
Concept:
Tensile Stresses in the main plates might result in tearing of main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as tearing strength or tearing value of plate.
Tearing efficiency of joints is given by,
\(\begin{array}{*{20}{c}} {{\eta _t} = \frac{\rm{Tearing\;strength}}{{\rm Strength\;of\;solid\;plate}}}\\ {{\eta _t} = \frac{{\left( {p - d} \right) \times t \times {\sigma _t}}}{{{p_t} \times {\sigma _t}}} = \frac{{p - d}}{p}} \end{array}\)
\(\therefore \eta = \frac{{p - d}}{p}\)
Calculation:
Given that tearing efficiency = 0.75
\(\eta = \frac{{p - d}}{p}\)
\(1 - \frac{d}{p} = 0.75 \Rightarrow \frac{d}{p} = 0.25\)