Double Lineup MCQ Quiz - Objective Question with Answer for Double Lineup - Download Free PDF

To get a call from all colleges, Bhama should clear all sectional cut-offs & also aggregate cut-off. Thus, 45 + 45 + 46 + 45 = 181 satisfies this condition.

The minimum aggregate marks required to get at least 2 calls is 175 (as there are exactly 2 colleges namely college 2 & college 3 below 175).

Given: Ten javelin players viz. A, B, C, D, E, P, Q, R, S and T are throwing javelin at ten different distances (Distance will be between 70 – 100 meters but no distance will be in multiple of ten.) Each player is allowed a maximum of two chances. Any throw above 100 meters will be considered foul/faulty throw. No two throw have the same distance. Only players who faulted in their first attempt will be allowed a second attempt.

1. The distance travelled by the javelin thrown by B is a perfect square.

 The difference between the distance covered by B and R is 6 meters.

 The distance travelled by the javelin thrown by A is a perfect cube more than 100 meters but less than 200 meters.

2. The distance travelled by the javelin thrown by S is 6 meters more than the distance travelled by R.

The distance travelled by the javelin thrown by P is 5 meters more than the maximum a person could throw without getting a faulty throw.

The difference between the distance travelled by B and D is 7 meters.

 The distance travelled by the javelin thrown by E is 3 meters less than that of D.

3. The distance travelled by javelin thrown by T is a faulty one.

The difference between javelin thrown by P and T is 11 meters.

The distance travelled by javelin thrown by C is a multiple of 3 more than 93 meters and did not travel the maximum distance.

4. The distance travelled by javelin thrown by E is not a multiple of 5.

The distance travelled by javelin thrown by E and Q is 18 meters.

5. P got a second chance and this time the distance travelled by javelin was maximum a person could throw.

A got a second chance and this time the distance travelled by javelin was more than B and at least 2 meters less than R. The distance travelled is even and is not divisible by 4.

T got a second chance and this time the distance travelled by javelin was 2 meters less than the distance travelled by S.

Therefore from the above statement we can see that,  E - 87 meters is incorrectly matched pair from the given options.

Hence, E - 87 meters is incorrectly matched pair.

Given: Ten javelin players viz. A, B, C, D, E, P, Q, R, S and T are throwing javelin at ten different distances (Distance will be between 70 – 100 meters but no distance will be in multiple of ten.) Each player is allowed a maximum of two chances. Any throw above 100 meters will be considered foul/faulty throw. No two throw have the same distance. Only players who faulted in their first attempt will be allowed a second attempt.

1. The distance travelled by the javelin thrown by B is a perfect square.

 The difference between the distance covered by B and R is 6 meters.

 The distance travelled by the javelin thrown by A is a perfect cube more than 100 meters but less than 200 meters.

2. The distance travelled by the javelin thrown by S is 6 meters more than the distance travelled by R.

The distance travelled by the javelin thrown by P is 5 meters more than the maximum a person could throw without getting a faulty throw.

The difference between the distance travelled by B and D is 7 meters.

 The distance travelled by the javelin thrown by E is 3 meters less than that of D.

3. The distance travelled by javelin thrown by T is a faulty one.

The difference between javelin thrown by P and T is 11 meters.

The distance travelled by javelin thrown by C is a multiple of 3 more than 93 meters and did not travel the maximum distance.

4. The distance travelled by javelin thrown by E is not a multiple of 5.

The distance travelled by javelin thrown by E and Q is 18 meters.

5. P got a second chance and this time the distance travelled by javelin was maximum a person could throw.

A got a second chance and this time the distance travelled by javelin was more than B and at least 2 meters less than R. The distance travelled is even and is not divisible by 4.

T got a second chance and this time the distance travelled by javelin was 2 meters less than the distance travelled by S.

Therefore from the above statement we can see that, the difference between the distance travelled by C and S is 96 - 93 = 3 meters.

Hence, the difference between the distance travelled by C and S is 3 meters​.

Articles: Bat, Ball, Fan, Table and Chair.

The topmost position is numbered as 1, the one below it is numbered as 4 and so on.

1) The bat is four places above the fan.

2) The Table is between the ball and the chair.

3) The chair is three places below the bat.

Ball is at the second position from the top.

According to Ankit’s memory, his birthday is either on 9^th Aug, 10^th Aug or 11^th Aug.

According to his mother’s memory, his birthday is either on 6^th Aug, 7^th Aug, 8^th Aug or 9^th Aug.

The only common date is 9^th Aug.

Therefore, the answer will be 9.

People = A, B, C, D, E, F, G, H, I, J, and K

Departments = HR, IT, and Finance

1) K works in the HR department.

2) C and D work in the same department and they do not work in the IT department.

3) Not more than three people work in the HR department.

4) G works in the same department as D.

Implies, G, C, and D work in the same department. Now, G, C, and D cannot be in the HR department as there are only three people in the HR department. Thus, G, C, and D work in the Finance department.

5) B works neither with G nor K.

G works in the Finance department and K works in the HR department. Thus, B works in the IT department.

6) F does not work with either G or B.

G works in the Finance department and B works in the IT department. Implies, F works in the HR department.

7) H works with F in the same department.

Implies, H also works in the HR department. Thus, H, F, and K are the three people who work in the HR department.

8) A does not work in the IT department.

A cannot be in the HR department because we have already found three people who work in the HR department. Thus, A works in the Finance department.

9) E works in the same department as J.

E and J cannot be in the Finance department because then there would be six people in one department which is not possible. Thus, E and J work in the IT department.

10) E does not work with I.

Implies, I works in the Finance department as he does not work in the IT department. Also, we already know the three people who work in the HR department.

Hence, "C works with I" in the same department.

A college offers two papers to a student.

(1) If a student studies Philosophy, he or she must study French.

(2) One who studies History cannot choose Psychology and only History students can study Political Science.

(3) French students cannot study History and French students cannot opt for Spanish.

(4) No Psychology student has opted for Sociology.

Five boys: B1, B2, B3, B4, and B5.

Five colours: Red, Yellow, Green, Orange and Pink.

Five bikes: L, M, N, P and T.

1) B2 has a bike M and he likes the green colour.

2) B1 likes the colour red or yellow and has bike L.

3) B4 likes either red or yellow. 

4) B5 has either N or T bike. 

5) Boy who likes orange has a bike P.

B1 and B4 do not like the orange colour because they like either Red or Yellow.

B5 has either N or T.

So, B3 likes orange colour and has a bike P.

So, B5 likes pink colour and B4 has a bike N or T.

Hence, "T – Yellow – B4" is the correct answer.

Radha wears five different coloured clothes, red, green, yellow, purple and brown, on five different days of a week, from Monday to Friday.

1. She wears red clothes on Wednesday.

2. She does not wear green and brown clothes on Monday or Friday.

3. She wears green clothes on the next day of wearing yellow clothes.

Only Purple and Brown clothes are left, which will be put in the order as shown below:

Clearly, Radha wear brown clothes on Thursday.

Hence, 'Thursday' is the correct answer.

Six persons - Seema, Vaibhav, Ajay, Manisha, Tulika and Ananya.

States - Assam, Gujarat, Madhya Pradesh, Punjab, Bihar and Rajasthan.

Games - Chess, Football, Hockey, Ludo, Badminton and Cricket.

(1) Ananya was born in Gujarat and she plays Cricket.

(2) The person who was born in Bihar plays Football.

(3) Seema plays Hockey and she was not born in Assam or Madhya Pradesh. Therefore she was born in Punjab, 

(4) Manisha was born in Rajasthan and she plays badminton.

Persons – Sharayn, Pinky, Tanisha and Mamta.

1. Tanisha is studying in A college

2. Pinky is good at Maths.

3. Of those studying in J college, one is good at Maths and the other in all subjects.

4. Sharayn is not good at Science.

From 2 and 3, it is clear that Pinky studies in J Colelge.

Also, from 3 and 4, it is clear that Sharayn does not studies in J College as Sharayn is not good at Science and Of those studying in J college, one is good at Maths and the other in all subjects.

From the above statements, it is clear that Mamta studies in J College and is good in all subjects and Sharayn is from College X.

Mamta is good at all the subjects.

Hence, ‘Mamta’ is the correct answer.

Seven chocolates: A, B, C, D, E, F and G.

Cost: 41, 42, 43, 45, 46, 47, 48, and 49 (none of the chocolates cost Rs. 44)

(1) The cost of chocolate C is Rs. 5 less than that of chocolate E, implies C = E - 5.

(2) The cost of chocolate A is a prime number.

(3) The cost of chocolate F is Rs. 2 more than that of chocolate A, implies F = A + 2.

Five phones - H, M, R, T and V.

1.V is at the bottom.

2. There are two phones between M and V.

3. The number of phones above T is same as the number of phones below V.

There are 0 phones below V, so there must be 0 phones above T.

Hence, T is on the top.

4. R is just above H.

Hence, ‘M and T’ phones are above R.