Design of Sewer MCQ Quiz - Objective Question with Answer for Design of Sewer - Download Free PDF

Last updated on May 9, 2025

Latest Design of Sewer MCQ Objective Questions

Design of Sewer Question 1:

The egg-shaped sewer is placed, such that:

  1. the velocity of flow is always lesser than the velocity of flow in hydraulically equivalent circular sewer
  2. the larger base has to support the weight of the upper smaller section
  3. the smaller base has to support the weight of the upper broader section
  4. the base and upper section has the same area and the middle section has large area

Answer (Detailed Solution Below)

Option 3 : the smaller base has to support the weight of the upper broader section

Design of Sewer Question 1 Detailed Solution

Explanation:

F1 Abhayraj.L 21-12-20 Savita D13

The egg-shaped sewer is designed for combined sewer systems, which carry both sanitary sewage and stormwater. It has a narrower bottom and wider top, and is placed with the smaller (narrow) end at the bottom for the following reasons:

  • Self-cleansing velocity: During dry weather (low flow), the narrow bottom ensures higher velocity to prevent sediment deposition.

  • High discharge capacity: During storms, the upper wider section accommodates large volumes of water.

  • The smaller base (narrower section) supports the broader upper portion of the sewer.

Additional InformationEgg-shaped Sewer

Shape and Design:

  • The sewer has a distinctive egg-like shape with a narrower bottom (smaller base) and a wider top (larger base).

Purpose:

  • Primarily used in combined sewer systems to handle both sanitary sewage and stormwater flows.

Flow Efficiency:

  • The design is intended to optimize flow conditions during varying discharge rates.

  • Self-cleansing velocity is achieved by the narrow bottom section, which promotes higher velocity during low flow conditions, preventing sedimentation.

Capacity:

  • The wider top section provides more capacity during high flow conditions, such as during heavy rainfall or storms, allowing the system to handle increased discharge.

Advantages:

  • Minimizes sediment deposition during low flow by maintaining sufficient flow velocity.

  • Increases discharge capacity in storm conditions due to the larger upper section.

  • Optimized for combined sewage systems by providing efficient flow at various conditions.

Design of Sewer Question 2:

What is the size of "Soil Pipe and Vent Pipe" commonly adopted for house drains in average conditions?

  1. 100 mm, 50 mm
  2. 210 mm, 75 mm
  3. 70 mm, 32 mm
  4. 400 mm, 20 mm
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : 100 mm, 50 mm

Design of Sewer Question 2 Detailed Solution

Explanation:

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A water closet is a water flushed plumbing fixture designed to receive the human excreta directly and is connected to the soil pipe by means of a trap.

Soil pipe:

  • A soil pipe conveying to a drain any solid or liquid filth shall be circular and shall have a minimum diameter of 100 mm.
  •  Asbestos cement building pipes may also be used as soil pipes only above ground level.
  • Soil pipes, whether inside or outside the building, shall not be connected with any rainwater pipe and there shall not be any trap in such soil pipe or between it any drain with which it is connected.
 

Vent pipe –

  • The pipe installed for the purpose of ventilation is known as a vent pipe through which foul gases escape into the atmosphere. It is provided in a septic tank for the discharge of foul gases.
  • The diameter of the main ventilating pipe shall not be less than 50 mm.
  • A branch ventilating pipe on a waste pipe in both one and two-pipe systems shall be of not less than two-thirds the diameter of the branch waste ventilated subject to a minimum of 25 mm.
  • A branch ventilating pipe on a soil pipe in both one- and two-pipe systems shall be not less than 32 mm in diameter

Anti-siphonage pipe –

Anti-siphonage pipe means any pipe provided in conjunction with a trap in the sanitary fitting to prevent unsealing of the trap by siphonage or backpressure.

Back-siphonage causes breaking of the water seal therefore anti-siphonage pipe is required.

Manholes-

Manholes are masonry or R.C.C. chamber constructed at suitable intervals along the sewer lines for providing access into them.

Design of Sewer Question 3:

The given figure in an example of a ________.

F5 Vinanti Engineering 11.11.22 D1

  1. P-trap
  2. Q-trap
  3. half-S-trap
  4. S-trap
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : P-trap

Design of Sewer Question 3 Detailed Solution

Explanation:

Traps: 

  • As the name suggests, traps simply trap the water and sewer gas.
  • It is a plumbing device used to prevent smell, bacteria, also insects from entering your home.

Different types of trap mention bellow:

  • Gully trap is provided outside the building before connecting it to the external sewerage line. It also collects wastewater from the kitchen sink, washbasin, bath, and wash area.
  • Intercepting trap is provided to prevent the foul gases from the public sewer from entering into the building sewer.
  • Anti-siphon trap is used to prevent siphoning action.
  • p trap is used with an Indian water closet. The traps are made from UPVC or cast-iron sheets. This trap also has a water seal and prevents entry of foul gases to the house.

F1 Abhayraj Anil 10.03.21 D9

F1 Abhayraj Anil 10.03.21 D7

F1 Abhayraj Anil 10.03.21 D8

Design of Sewer Question 4:

In Self cleansing velocity

  1. Solid particles get settled at the bottom
  2. Solid particles will float on surface
  3. Solid along with water move at very high speed 
  4. Solid particles will remain in suspension
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : Solid particles will remain in suspension

Design of Sewer Question 4 Detailed Solution

Concept:

Self Cleansing Velocity:

  • self-cleansing velocity is that which does not allow the silting of solid in the sewer more-ever also carry out the removal of solids that have already settled.
  • Self-cleansing velocity for 1 mm inorganic particle and for 5 mm organic particle is 0.45 m/sec.
  • This minimum self-cleansing velocity of 0.45 m/sec is attained at minimum hourly discharge. If the sewer is designed for design flow condition and velocity at design depth of flow is greater than 0.8- 0.9 m/sec.

Self-cleansing velocity in the sewer is given by,

\({{\rm{v}}_{\rm{s}}}{\rm{ = }}\sqrt {\frac{{{\rm{8kgd}}\left( {{\rm{G - 1}}} \right)}}{{\rm{f}}}} \)

K is a constant which depends upon the type of solids present in the sewage 

f = Friction factor

d = Diameter of the particle

Design of Sewer Question 5:

Which sewer appurtenance/structure is represented by the given figure?

3-5-2025 IMG-1200 Ashish Verma -16

  1. A typical section of a vertical inlet
  2. A typical section of a lamp hole
  3. A typical section of a catch basin
  4. A typical section of a circular drop manhole

Answer (Detailed Solution Below)

Option 4 : A typical section of a circular drop manhole

Design of Sewer Question 5 Detailed Solution

Explanation:

Drop Manhole:

A drop manhole is a type of manhole where the vertical pipe is permitted to flow between the main sewer and branch sewer.

  • Drop manholes are provided at the junction of sewer lines when a high-level branch sewer enters a low-level main sewer. If the difference of more than 600 mm in the water lines and inverse level of two sewers are connected with a drop manhole.
  • The branch sewer is joined to a manhole through a vertical pipe. The sewage coking through the branch sewer dips in through the vertical pipe, and trickles over the main sewer channel, just above it.

  • A plug is provided at the point where the branch sewer if taken straight intersects the wall of the manhole.

  • A plug is provided at the point where the branch sewer if taken straight intersects the wall of the manhole.

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Top Design of Sewer MCQ Objective Questions

Which of the following tests is performed to detect the leakage of rain water pipe in the testing of house sewers?

  1. Water test
  2. Smoke test
  3. Temperature test
  4. Air test

Answer (Detailed Solution Below)

Option 2 : Smoke test

Design of Sewer Question 6 Detailed Solution

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The laid pipes are usually tested to ascertain the water-tightness of the pipes and joints. There are three tests that are commonly performed to test leakage of the pipes and are as follows:

  1. Air Test - Generally used to test underground and vertical pipes. The escape of air from the leaky joint forms bubbles that can be seen visually.
  2. Water Test - Most commonly used for underground house sewer pipes. The drain is plugged at the lower end and the water is filled in the pipe through the upper manhole to maintain a pressure of 1 to 1.5 m depth of water. If there is no drop in the water level in 10 minutes, then there is no leakage from the pipe.
  3. Smoke Test - Generally used to detect leakage of existing vertical sullage pipe or rainwater pipes. In this test, smoke is forced into the pipe with the help of a blower to test the leakage.

Minimum daily flow occurring through the sewer during night hour may be assumed -

  1. \(\frac{1}{3}\) × Average Daily Flow
  2. \(\frac{3}{2}\) × Average Daily Flow 
  3. \(\frac{2}{3}\) × Average Daily Flow
  4. \(\frac{1}{2}\) × Average Daily Flow

Answer (Detailed Solution Below)

Option 3 : \(\frac{2}{3}\) × Average Daily Flow

Design of Sewer Question 7 Detailed Solution

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Explanation:

Design of sewer:

  • The peak flow can be considered as 1.5 times the annual average daily flow.
  • For a design of the treatment facility, the peak factor is considered as 1.5 times the annual average daily flow.
  • The minimum flow passing through sewers is also important to develop self-cleansing velocity to avoid silting in sewers. This flow will generate in the sewers during late night hours. The effect of this flow is more pronounced on lateral sewers than the main sewers.
  • Sewers must be checked for minimum velocity as follows:
  • Minimum daily flow = 2/3 Annual average daily flow
  • Minimum hourly flow = 1/2 Minimum daily flow
  • Minimum hourly flow = 1/3 Annual average daily flow

In sewerage system drop manholes are provided when there is a:

  1. Sloping ground, with drop more than 0.6 m is required to control the gradient.
  2. Change in alignment of sewer line
  3. Change in size of sewers
  4. Change from gravity system to pressure system

Answer (Detailed Solution Below)

Option 1 : Sloping ground, with drop more than 0.6 m is required to control the gradient.

Design of Sewer Question 8 Detailed Solution

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Explanation:

Drop Manhole

A drop manhole is a manhole in which a vertical pipe is provided to allow for flow between the branch sewer and the main sewer.

  • Drop manholes are provided when there is change in elevation of ground level.
  • A drop manhole reduces the turbulence in the manhole when the elevation difference between the incoming and outflow sewers is greater than 0.5 meter.
  • Sloping ground, with drop more than 0.6 m is required to control the gradient.
  • Therefore they are provided in hilly townships.

The hydraulic radius of a circular sewer of internal diameter 100 cm, running in fully occupied cross section is given by:

  1. 100 cm
  2. 25 cm
  3. 50 cm
  4. 75 cm

Answer (Detailed Solution Below)

Option 2 : 25 cm

Design of Sewer Question 9 Detailed Solution

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Concept:

The hydraulic mean depth or also called hydraulic radius is defined as:

\(R = \frac{{\rm{Wetted}\;\rm{Area}}}{{\rm{Wetted}\;\rm{perimeter}}}=\frac{A}{P}\)

Wetted area = \(A = \frac{\pi }{4}{d^2} \)  

Wetted perimeter P = πd

Hydraulic mean deppth = \(R = \frac{A}{P} = \frac{{\pi {d^2}}}{{4\pi d}} = \frac{d}{4}\)

Calculation

Given:

d = 100 cm.

For circular pipe:

\(R = \frac{A}{P} =\frac{d}{4}\)

\(R =\frac{100}{4}=25\;mm\)

For a sewer line of 50 cm diameter, the spacing of manhole along straight run would be approximately.

  1. 10 m
  2. 100 m
  3. 500 m
  4. 1000 m

Answer (Detailed Solution Below)

Option 2 : 100 m

Design of Sewer Question 10 Detailed Solution

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Explanation:

As per IS 1742:1960:

Size of Sewer

Recommended spacing of manholes on straight reaches of sewer lines as per IS 1742:1960

Diameter up to 0.3 m

45 m

Diameter up to 0.6 m

75 m

Diameter up to 0.9 m

90 m

Diameter up to 1.2 m

120 m

Diameter up to 1.5 m

250 m

Diameter greater than 1.5 m

300 m

So as per the given options most appropriate answer, for 50 cm diameter of sewer spacing of manhole is 100 m

The diameter of a domestic sewer pipe laid at gradient 1 in 100 is recommended

  1. 100 mm
  2. 150 mm
  3. 200 mm
  4. 175 mm

Answer (Detailed Solution Below)

Option 2 : 150 mm

Design of Sewer Question 11 Detailed Solution

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As, per IS 1972 (1983), Clause 4.6.1.2 The approximate gradients which give this velocity for the sizes of pipes likely to be used in building drainage and the corresponding discharges when flowing half-full are as follows:

Dia. of Sewer (mm)

Minimum Gradient

100

1 in 57

150

1 in 100

200

1 in 145

230

1 in 175

250 1 in 195
300 1 in 250

Which of the following statements in the context of a circular sewer of full depth ‘D’ is correct?

  1. Maximum velocity is 20% higher than that when running full.
  2. Maximum discharge is obtained when depth of flow is 0.95 D.
  3. Maximum velocity is obtained when depth of flow is 0.95 D.
  4. Maximum discharge is obtained when depth of flow is 0.81 D.

Answer (Detailed Solution Below)

Option 2 : Maximum discharge is obtained when depth of flow is 0.95 D.

Design of Sewer Question 12 Detailed Solution

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Explanation:

For a circular section (a section which is converging on the top), hydraulic efficiency depends upon:

i) Maximum Velocity

For maximum velocity case, R = 0.30 × d and y = 0.81 × d

ii) Maximum discharge

For maximum discharge case, R = 0.29 × d and y = 0.95 × d

Where

d = diameter of the circular pipe

y = hydraulic depth

R = hydraulic radius

Two sewer pipelines A and B (having the same diameter and made of the same material) are laid at a bed slope of 1 in 225 and 1 in 625, respectively. Determine the ratio of their carrying capacities (QA to QB).

  1. \(\frac{5}{3}\)
  2. 1
  3. \(\frac{3}{5}\)
  4. \(\frac{2}{5}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{5}{3}\)

Design of Sewer Question 13 Detailed Solution

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Concepts:

The flow in sewer pipe takes place under atmospheric conditions i.e. open channel flow and also its is assumed to be a uniform flow. Hence, Manning’s formula can be applied for the calculation of discharge, which is given as :

\(Q= A (\frac{1}{N}R^{2/3} S^{1/2}) \)

Where

N is roughness coefficient, depends on pipe material

R hydraulic radius depends on pipe geometry

S is bed slope at which pipe is laid

A is a cross-sectional area

Q is the rate of flow in sewer pipe

Calculation:

Since, both sewer pipelines have same diameter and made of same material, they have same hydraulic radius and cross section area and roughness coefficient.

Therefore, it can be concluded that

Q ∝ S1/2

Now ,

\(\frac{Q_A}{Q_B} = \frac{S_A^{1/2}}{ S_B^{1/2}}\)

\(\frac{Q_A}{Q_B} = \frac{{(1/225})^{1/2}}{(1/625){1/2}}\)

\(\frac{Q_A}{Q_B} = 1.67\)

As per NBO, the gradient required to generate self-cleansing velocity for a 100 mm Φ sewer is _____.

  1. 1 in 60
  2. 1 in 100
  3. 1 in 150
  4. 1 in 225

Answer (Detailed Solution Below)

Option 1 : 1 in 60

Design of Sewer Question 14 Detailed Solution

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Concept:

Self-Cleansing Velocity:

  • self-cleansing velocity is that which does not allow the silting of solids in the sewer more-ever also carries out the removal of solids that have already settled.

NBO recommendations for minimum velocity for small sewers:

Diameter (mm) Gradient required to generate self-cleaning velocity Velocity generated in the sewer when running half full
100 1 in 60 0.58 m/sec
150 1 in 100 0.61 m/sec
225 1 in 120 0.79 m/sec

As per IS 1742-1983, normally a sewer shall be designed for discharging _______ times the dry-weather flow flowing half-full with a minimum self-cleansing velocity of _______.

  1. Five; 2.4 m/s
  2. Three; 0.75 m/s
  3. Four; 1.75 m/s
  4. Two; 0.5 m/s

Answer (Detailed Solution Below)

Option 2 : Three; 0.75 m/s

Design of Sewer Question 15 Detailed Solution

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Concept:

IS 1742-1983: Code of practice for building drainage

Normally, the sewer shall be designed for discharging three times the dry-weather flow flowing half-full with a minimum self-cleansing velocity of 0.75 m/s. The approximate gradients which give this velocity for the sizes of pipes likely to be used in building drainage and the corresponding discharges when flowing half-full are as follows:

Diameter

(mm)

Gradients

Discharge

(m3/min)

100 1 in 57 0.18
150 1 in 100 0.42
200 1 in 145 0.73
230 1 in 175 0.93
250 1 in 195 1.10
300 1 in 250 1.70

 

 

 

 

 

 

 

Important Points 1. In cases, where it is practically not possible to conform to the ruling gradients, a flatter gradient may be used but the minimum velocity in such cases shall on no account be less than 0.61 m/s

2. It is undesirable to employ gradients giving a velocity of flow greater than 2.4 m/s. Where it is unavoidable, cast-iron pipes shall be used.

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