Design Against Fluctuating Load MCQ Quiz - Objective Question with Answer for Design Against Fluctuating Load - Download Free PDF

Last updated on May 31, 2025

Latest Design Against Fluctuating Load MCQ Objective Questions

Design Against Fluctuating Load Question 1:

The S-N curve in fatigue testing shows the relationship between:

  1. the number of cycles and strain amplitude
  2. the number of cycles and stress amplitude
  3. stress and strain
  4. stress and displacement

Answer (Detailed Solution Below)

Option 2 : the number of cycles and stress amplitude

Design Against Fluctuating Load Question 1 Detailed Solution

Explanation:

Fatigue Testing and the S-N Curve

Definition: Fatigue testing is a method used to determine the durability and lifespan of a material under cyclic loading conditions. It is crucial in predicting how a material will behave when subjected to repeated stress or strain over time. The S-N curve, also known as the Wöhler curve, is a graphical representation that illustrates the relationship between the stress amplitude (S) and the number of cycles to failure (N).

Working Principle: During fatigue testing, a sample material is subjected to repeated cyclic loading until failure occurs. The stress amplitude and the number of cycles to failure are recorded. This data is then used to plot the S-N curve, where the x-axis represents the number of cycles to failure (N) on a logarithmic scale, and the y-axis represents the stress amplitude (S).

Correct Option Analysis:

The correct option is:

Option 2: The number of cycles and stress amplitude

This option accurately describes the S-N curve in fatigue testing. The S-N curve shows the relationship between the number of cycles to failure (N) and the stress amplitude (S). The curve typically displays how the material's endurance limit or fatigue limit is determined, which is the stress level below which the material can endure an infinite number of cycles without failing.

The S-N curve is critical for engineers and designers to understand the fatigue behavior of materials and to ensure the reliability and safety of components subjected to cyclic loading in various applications, such as in automotive, aerospace, and structural engineering

Design Against Fluctuating Load Question 2:

Notch sensitivity factor (A) is related as [A = Notch sensitivity factor, B = Theoretical stress concentration factor, C = Fatigue stress concentration factor]

  1. A = [B - 1] [C - 1]
  2. B = 1 + A [C - 1]
  3. A = BC
  4. C = 1 + A [B - 1]

Answer (Detailed Solution Below)

Option 4 : C = 1 + A [B - 1]

Design Against Fluctuating Load Question 2 Detailed Solution

Explanation:

Notch sensitivity:

Notch sensitivity is defined as the susceptibility of a material to succumb to the damaging effect of stress raising notches in fatigue loading

\({{q}} = \frac{{{{increase}}\;{{of}}\;{{actual}}\;{{stress}}\;{{over}}\;{{nominal}}\;{{stress}}}}{{{{increase}}\;{{of}}\;{{theoretical}}\;{{stress}}\;{{over}}\;{{nominal}}\;{{stress}}}}\)

Key Parameters:

  • A = Notch Sensitivity Factor
  • B = Theoretical Stress Concentration Factor (Kt)
  • C = Fatigue Stress Concentration Factor (Kf)

actual stress = Kσo, theoretical stress = Kσo

where, σ= nominal stress, Kf = actual stress concentration factor Kt = theoretical stress concentration factor.

Increase of actual stress = (Kσ- σo)

Increase of theoretical stress = (Kσ- σo)

\({\bf{q}} = \frac{{\left( {{{\bf{K}}_{\bf{f}}}{{\bf{\sigma }}_{\bf{o}}}\; - \;{{\bf{\sigma }}_{\bf{o}}}} \right)}}{{\left( {{{\bf{K}}_{\bf{t}}}{{\bf{\sigma }}_{\bf{o}}}\; - \;{{\bf{\sigma }}_{\bf{o}}}} \right)}} = \frac{{\left( {{{\bf{K}}_{\bf{f}}}\; - \;1} \right)}}{{\left( {{{\bf{K}}_{\bf{t}}}\; - \;1} \right)}}\)

⇒ C = 1 + A [B - 1]

Design Against Fluctuating Load Question 3:

How does the Goodman line differ from the Soderberg line in fatigue analysis? 

  1. The Goodman line applies to ductile materials, whereas the Soderberg line is for brittle materials. 
  2. The Goodman line is used for dynamic loading, while the Soderberg line is for static loading.  
  3. The Goodman line is based on the ultimate tensile strength, while the Soderberg line uses yield strength. 
  4. The Goodman line represents the elastic limit, while the Soderberg line represents the plastic limit.  

Answer (Detailed Solution Below)

Option 3 : The Goodman line is based on the ultimate tensile strength, while the Soderberg line uses yield strength. 

Design Against Fluctuating Load Question 3 Detailed Solution

Explanation:

Fatigue Analysis: Goodman Line vs. Soderberg Line

  • Fatigue analysis is essential in mechanical engineering to predict the life of a component under cyclic loading. Two common methods used in fatigue analysis are the Goodman line and the Soderberg line. These methods help engineers determine the safety and durability of materials subjected to fluctuating stresses.

Option 3: The Goodman line is based on the ultimate tensile strength, while the Soderberg line uses yield strength.

This option accurately describes the fundamental difference between the two lines used in fatigue analysis. The Goodman line incorporates the ultimate tensile strength (UTS) of the material, which is the maximum stress that a material can withstand while being stretched or pulled before breaking.
Soderberg line for ductile materials gives upper limit for any combination of mean and alternating stress. Following diagram depicts the same.

F1 R.Y 14.12.19 Pallavi D10

Considering following notations

σa = limiting safe stress amplitude

Se = endurance limit of the component

σm = limiting safe mean stress

Sut = ultimate tensile strength

Syt = Yield strength

N = Factor of safety

Soderberg line:

The line joining Syt (yield strength of the material) on the mean stress axis and Se (endurance limit of the component) on stress amplitude axis is called as Soderberg line. This line is used when yielding defines failure (Ductile materials).

The equation for the Soderberg line:

\(\frac{{{{\rm{\sigma }}_{\rm{m}}}}}{{{{\rm{S}}_{{\rm{yt}}}}}} + \frac{{{{\rm{\sigma }}_{\rm{a}}}}}{{{{\rm{S}}_{\rm{e}}}}} = \frac{1}{N}\)

Goodman line:  

Line joining Se on stress amplitude axis and Sut on mean stress axis is known as Goodman line. The triangular region below this line is considered a safe region. 
The equation for Goodman line:

\(\frac{{{\sigma _m}}}{{{S_{ut}}}} + \frac{{{\sigma _a}}}{{{S_e}}} = \frac{1}{N}\)

Design Against Fluctuating Load Question 4:

Which one of the following failure theories is the most conservative design approach against fatigue failure?

  1. Modified Goodman line
  2. Yield line
  3. Gerber line
  4. Soderberge line

Answer (Detailed Solution Below)

Option 4 : Soderberge line

Design Against Fluctuating Load Question 4 Detailed Solution

Explanation:

Soderberg line:
Soderberg line for ductile materials gives upper limit for any combination of mean and alternating stress. Soderberg line is the most conservative fatigue failure criterion. Following diagram depicts the same.

F1 R.Y 14.12.19 Pallavi D10

Considering following notations

σa = limiting safe stress amplitude

Se = endurance limit of the component

σm = limiting safe mean stress

Sut = ultimate tensile strength

Syt = Yield strength

N = Factor of safety

Soderberg line:

The line joining Syt (yield strength of the material) on the mean stress axis and Se (endurance limit of the component) on stress amplitude axis is called as Soderberg line. This line is used when yielding defines failure (Ductile materials).

The equation for the Soderberg line:

\(\frac{{{{\rm{\sigma }}_{\rm{m}}}}}{{{{\rm{S}}_{{\rm{yt}}}}}} + \frac{{{{\rm{\sigma }}_{\rm{a}}}}}{{{{\rm{S}}_{\rm{e}}}}} = \frac{1}{N}\)

Additional Information

Goodman line:

Line joining Se on stress amplitude axis and Sut on mean stress axis is known as Goodman line. The triangular region below this line is considered a safe region. 
The equation for Goodman line:

\(\frac{{{\sigma _m}}}{{{S_{ut}}}} + \frac{{{\sigma _a}}}{{{S_e}}} = \frac{1}{N}\)

Gerber Line: 

Line joining Se on stress amplitude axis and Sut on mean stress axis is joined by a parabolic curve. 
The equation for Gerber line:

Design Against Fluctuating Load Question 5:

A tension member of diameter ' d ' is designed with factor of safety of 3. If the load and the diameter are doubled, then factor of safety will be ---- for the same yield stress of 240MPa.
A. Unchanged
B. Reduced to half
C. Doubled
D. Tripled

  1. A
  2. B
  3. C
  4. D

Answer (Detailed Solution Below)

Option 3 : C

Design Against Fluctuating Load Question 5 Detailed Solution

When the load and diameter are doubled, the new cross-sectional area becomes four times the initial area, causing the new stress to be half of the initial stress. Since the factor of safety is the ratio of yield stress to working stress, halving the working stress results in doubling the factor of safety. This relationship demonstrates how changes in dimensions and loading conditions affect the safety and performance of structural members.

Top Design Against Fluctuating Load MCQ Objective Questions

Endurance limit of a beam subjected to pure bending decreases with

  1. decrease in the surface roughness and decrease in the size of the beam
  2. increase in the surface roughness and decrease in the size of the beam
  3. increase in the surface roughness and increase in the size of the beam
  4. decrease in the surface roughness and increase in the size of the beam

Answer (Detailed Solution Below)

Option 3 : increase in the surface roughness and increase in the size of the beam

Design Against Fluctuating Load Question 6 Detailed Solution

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Explanation:

Corrected endurance strength is defined as

σe = Ka Kb Kc Kde

where, σe = Endurance strength and Ka = size factor, Kb = surface factor, Kc = load factor, Kd = Temperature factor

{Ka, Kb, Kc, Kd} < 1

So, with the increases in surface roughness and size of the beam, endurance strength will decrease.

Which one of the following is the most conservative fatigue failure criterion?

  1. Soderberg
  2. Modified Goodman
  3. ASME Elliptic
  4. Gerber

Answer (Detailed Solution Below)

Option 1 : Soderberg

Design Against Fluctuating Load Question 7 Detailed Solution

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F1 R.Y 14.12.19 Pallavi D10

Soderberg line is the most conservative fatigue failure criterion. Even yielding is not considered in soderberg criterion. 

The Gerber parabola is the best fit for the failure points of the test data.

The Goodman is safer from design consideration since it lies completely inside the Geber parabola and failure points.

A component is subjected to varying tensile stresses such that maximum stress = 50 MPa and minimum stress = 10 MPa. It is made of the material having yield stress = 300 MPa and endurance stress = 100 MPa. According to the Soderberg criteria, the factor of safety will be:

  1. 2
  2. 2.5
  3. 3.33
  4. 4

Answer (Detailed Solution Below)

Option 3 : 3.33

Design Against Fluctuating Load Question 8 Detailed Solution

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Concept:

When a component is subjected to fluctuating stresses, there is mean stress (σmean) as well as stress amplitude (σamp).

To design those components certain methods are used based on the Endurance limit of the material σe.

When a straight-line joins Endurance limit σe on ordinate and Yield strength σyt on abscissa it is known as Soderberg line.

The abscissa represents σmean and ordinate represents σamp.

Soderberg Line is given by -

\(\frac{{{{\rm{\sigma }}_{{\rm{mean}}}}}}{{{{\rm{\sigma }}_{{\rm{yt}}}}}} + \frac{{{{\rm{\sigma }}_{{\rm{amp}}}}}}{{{{\rm{\sigma }}_{\rm{e}}}}} = \frac{1}{{{\rm{FOS}}}}\)

F1 R.Y 14.12.19 Pallavi D10

Calculation:

Given:

σmax = 50 MPa, σmin = 10 MPa, σyt = 300 MPa, σe = 100 MPa

\(\therefore {{\rm{\sigma }}_{{\rm{mean}}}} = \frac{{{{\rm{\sigma }}_{{\rm{max}}}} + {{\rm{\sigma }}_{{\rm{min}}}}}}{2} \Rightarrow \frac{{50 + 10}}{2} = 30{\rm{\;MPa}}\)

\(\therefore {{\rm{\sigma }}_{{\rm{amp}}}} = \frac{{{{\rm{\sigma }}_{{\rm{max}}}} - {{\rm{\sigma }}_{{\rm{min}}}}}}{2} \Rightarrow \frac{{50 - 10}}{2} = 20{\rm{\;MPa}}\)

Equation of Soderberg Line is given by –

\(\frac{{{{\rm{\sigma }}_{{\rm{mean}}}}}}{{{{\rm{\sigma }}_{{\rm{yt}}}}}} + \frac{{{{\rm{\sigma }}_{{\rm{amp}}}}}}{{{{\rm{\sigma }}_{\rm{e}}}}} = \frac{1}{{{\rm{FOS}}}}\)

\( \Rightarrow \frac{{30}}{{300}} + \frac{{20}}{{100}} = \frac{1}{{FOS}}\)

\( \Rightarrow 0.1 + 0.2 = \frac{1}{{FOS}}\)

\( \Rightarrow FOS = \frac{1}{{0.3}}\)

FOS = 3.33

Additional Information 

Goodman Line:

\(\frac{{{{\rm{\sigma }}_{{\rm{mean}}}}}}{{{{\rm{\sigma }}_{{\rm{ut}}}}}} + \frac{{{{\rm{\sigma }}_{{\rm{amp}}}}}}{{{{\rm{\sigma }}_{\rm{e}}}}} = \frac{1}{{{\rm{FOS}}}}\)

Gerber Line:

\({\left( {\frac{{{\rm{FOS}} \times {{\rm{\sigma }}_{{\rm{mean}}}}}}{{{{\rm{\sigma }}_{{\rm{ut}}}}}}} \right)^2} + \left( {\frac{{{\rm{FOS}} \times {{\rm{\sigma }}_{{\rm{amp}}}}}}{{{{\rm{\sigma }}_{\rm{e}}}}}} \right) = 1\)

For the given fluctuating fatigue load, the values of stress amplitude and stress ratio are respectively

F1 S.S Madhu 11.01.20 D2

  1. 100 MPa and 5
  2. 250 MPa and 5
  3. 100 MPa and 0.20
  4. 250 MPa and 0.20

Answer (Detailed Solution Below)

Option 3 : 100 MPa and 0.20

Design Against Fluctuating Load Question 9 Detailed Solution

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Concept:

Stress Amplitude: It is the amount of stress which deviates from mean stress.

Stress Amplitude = (σ­­max – σmin)/2 

Stress Ratio: It is the ratio of the minimum stress experienced during a cycle to the maximum stress experienced during a cycle.

Stress Ratio = σmin / σmax

σmax = Maximum stress experienced in a cycle

σmin = Minimum stress experienced in a cycle

Calculation:

σmax = 250 MPa σmin = 50 MPa

\(\begin{array}{l} {\rm{Stress\ Amplitude}} = \frac{{{{\rm{σ }}_{{\rm{max}}}} - {{\rm{σ }}_{{\rm{min}}}}}}{2} = \frac{{250 - 50}}{2} = 100\ {\rm{MPa}}\\ {\rm{Stress\ Ratio}} = \frac{{{{\rm{σ }}_{{\rm{min}}}}}}{{{{\rm{σ }}_{{\rm{max}}}}}} = \frac{{50}}{{250}} = 0.2 \end{array}\)

The S - N curve for steel becomes asymptotic nearly at

  1. 103 cycles
  2. 104 cycles
  3. 106 cycles 
  4. 109 cycles 

Answer (Detailed Solution Below)

Option 3 : 106 cycles 

Design Against Fluctuating Load Question 10 Detailed Solution

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Explanation:

The common form of presentation of fatigue data is by using the S-N curve, where the total cyclic stress (S) is plotted against the number of cycles to failure (N) in a logarithmic scale.

EKT Free Test1 images Q3a

the fatigue life reduces with respect to the increase in stress range and at a limiting value of stress, the curve flattens off. The point at which the S-N curve flattens off is called the ‘endurance limit’.

The line between 103 and 106 cycles is taken to represent high cycle fatigue.

From the S-N curve, we can see that the curve becomes asymptotic nearly at 106 cycles.

The notch sensitivity q is expressed in terms of fatigue stress concentration factor Kf and theoretical stress concentration factor Kt as

  1. \(\frac{{{K_f} + 1}}{{{K_t} + 1}}\)
  2. \(​\frac{{{K_f} - 1}}{{{K_t} - 1}}\)
  3. \(\frac{{{K_t} + 1}}{{{K_f} + 1}}\)
  4. \(\frac{{{K_t} - 1}}{{{K_f} - 1}}\)

Answer (Detailed Solution Below)

Option 2 : \(​\frac{{{K_f} - 1}}{{{K_t} - 1}}\)

Design Against Fluctuating Load Question 11 Detailed Solution

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Explanation:

Notch sensitivity:

Notch sensitivity is defined as the susceptibility of a material to succumb to the damaging effect of stress raising notches in fatigue loading

\({{q}} = \frac{{{{increase}}\;{{of}}\;{{actual}}\;{{stress}}\;{{over}}\;{{nominal}}\;{{stress}}}}{{{{increase}}\;{{of}}\;{{theoretical}}\;{{stress}}\;{{over}}\;{{nominal}}\;{{stress}}}}\)

actual stress = Kf σo, theoretical stress = Kt σo

where, σ= nominal stress, Kf = actual stress concentration factor Kt = theoretical stress concentration factor.

Increase of actual stress = (Kf σo - σo)

Increase of theoretical stress = (Kt σo - σo)

\({\bf{q}} = \frac{{\left( {{{\bf{K}}_{\bf{f}}}{{\bf{\sigma }}_{\bf{o}}}\; - \;{{\bf{\sigma }}_{\bf{o}}}} \right)}}{{\left( {{{\bf{K}}_{\bf{t}}}{{\bf{\sigma }}_{\bf{o}}}\; - \;{{\bf{\sigma }}_{\bf{o}}}} \right)}} = \frac{{\left( {{{\bf{K}}_{\bf{f}}}\; - \;1} \right)}}{{\left( {{{\bf{K}}_{\bf{t}}}\; - \;1} \right)}}\)

Additional Information

SSC JE ME Full test 3 Images-Q65

Theoretical stress factor (Kt) can also be calculated from the figure if irregularities dimension is given-

\({K_t} = 1 + 2\left( {\frac{A}{B}} \right)\)

where a = Semi-major axis perpendicular to the direction of load and b = semi-minor axis parallel to the direction of load.

For sharp crack:

B → 0 ∴ Kt = ∞

For circle:

A = B

∴ Kt = 3

S-N curve represents the:

  1. Fatigue strength (on y-axis) and numbers of fully reversed stress cycle (on x-axis)
  2. Hardness (on y-axis) and numbers of fully reversed stress cycle (on x-axis)
  3. Fracture toughness (on y-axis) and numbers of fully reversed stress cycle (on x-axis)
  4. Resilience (on y-axis) and numbers of fully reversed stress cycle (on x-axis)

Answer (Detailed Solution Below)

Option 1 : Fatigue strength (on y-axis) and numbers of fully reversed stress cycle (on x-axis)

Design Against Fluctuating Load Question 12 Detailed Solution

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The common form of presentation of fatigue data is by using the S-N curve, where the total cyclic stress (S) is plotted against the number of cycles to failure (N) in a logarithmic scale.

EKT Free Test1 images Q3a

the fatigue life reduces with respect to the increase in stress range and at a limiting value of stress, the curve flattens off. The point at which the S-N curve flattens off is called the ‘endurance limit’.

The line between 103 and 106 cycles is taken to represent high cycle fatigue.

From the S-N curve, we can see that the curve becomes asymptotic nearly at 106 cycles.

If the size of a standard specimen for fatigue testing machine is increased the endurance limit for the material will

  1. Have same value as that of standard specimen
  2. Increases
  3. Decreases
  4. None of these

Answer (Detailed Solution Below)

Option 3 : Decreases

Design Against Fluctuating Load Question 13 Detailed Solution

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Explanation:

The endurance limit of the specimen is given by

Se = Ka Kb Kc Kd Se'

where Ka =  Surface finish factor, Kb = Size factor, Kc = Reliability factor, Kd = Modifying factor to account for stress concentration, Se = Endurance limit stress of a particular mechanical component subjected to reversed bending stress (N/mm2), Se' = Endurance limit the stress of a rotating beam specimen subjected to reversed bending stress (N/mm2)

  • When the surface finish is poor, there are scratches and geometric irregularities on the surface. These surface scratches serve as stress raisers and result in stress concentration. The endurance limit is reduced due to the introduction of stress concentration on these scratches.
  • When the machine part is larger greater is the probability that a flaw exists somewhere in the component, the chances of fatigue failure originating at these flaws are more. The endurance limit, therefore, reduces with the increasing size of the component.
  • The greater the likelihood that a part will survive, the more is the reliability factor. The reliability factor Kc depends upon the reliability that is used in the design of the component.

The endurance limit is reduced due to stress concentration.

In the case of fatigue loading of materials, the stress level corresponding to infinite life is known as: 

  1. Loading limit
  2. Fatigue limit
  3. Tensile limit 
  4. Endurance limit

Answer (Detailed Solution Below)

Option 4 : Endurance limit

Design Against Fluctuating Load Question 14 Detailed Solution

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Explanation:

Fluctuating load:

When the magnitude of forces varies with time. Due to this varying load, varying stresses induced in a material. They are of three types-

  • Fluctuating stress
  • Repeated stress
  • Reversed stress

It is observed that 80 % of the failure of a mechanical component is due to fatigue failure resulting from fluctuating stresses.

Fatigue failure:

  • It is defined as a time-delayed fracture under cycling loading.
  • They are sudden and total.
  • It depends upon the number of cycles, mean stress, stress amplitude, stress concentration residual stress.

Endurance Limit:

  • The maximum amplitude of a completely reversed stress that the standard specimen can sustain for unlimited cycles without fatigue failure.
  • Since the fatigue test cannot be conducted for an unlimited or infinite number of cycles, 106 cycles are considered as infinite life of a material.

Additional Information

Components subjected to Low-cycle-fatigue (up to 103 cycles) are designed on the basis of Ultimate/Yield strength with a factor of safety (FOS).

Components subjected to High-cycle-fatigue (103 - 10cycles) are designed on the basis of the Endurance limit with a factor of safety (FOS).

The endurance limit of steel is associated with ________number of in fatigue loading. 

  1. low
  2. limited
  3. infinite
  4. 1000

Answer (Detailed Solution Below)

Option 3 : infinite

Design Against Fluctuating Load Question 15 Detailed Solution

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Explanation:

Endurance limit (σe):

It is defined as the maximum value of completely reversed bending stress which a polished standard specimen can withstand without failure, for an infinite number of cycles (usually 106 cycles).

Hence for steel in fatigue loading the endurance limit is the maximum reversed bending stress it can withstand without failure for an infinite number of cycle.

Additional Information

There are various factors on which endurance limits depends which changes the value of endurance limit by some factors.

i.e. σe’ = σe × (Ka × Kb × Kc × Km)

Surface finish factor (Ka): The endurance limit of the specimen depends on the surface conditions.

  • If the surface is smooth, the value of Ka is 1.
  • If crack increases and surface become rough, the value of Ka decreases.

Size factor (Kb): If the size of the standard specimen is increased. Then the endurance limit of the material will decrease. This is because a longer specimen will have more defects than a smaller one.

Load factor (Kc): The endurance limit changes as the type of loading changes.

  • For a completely reverse bending load → Kc = 1
  • For a completely reverse axial load → Kc = 0.85
  • For a completely reverse shear load → Kc = 0.5

Miscellaneous factor (Km): Apart from above factors there are other miscellaneous factors on which endurance limit depends such as reliability factor (Kr), temperature factor (K­­t), impact factor (Ki) etc.

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