Crystal Structures MCQ Quiz - Objective Question with Answer for Crystal Structures - Download Free PDF
Last updated on Jun 10, 2025
Latest Crystal Structures MCQ Objective Questions
Crystal Structures Question 1:
Atomic packing factor for FCC structure is:
Answer (Detailed Solution Below)
Crystal Structures Question 1 Detailed Solution
Explanation:
The atomic packing factor is defined as the ratio of the volume occupied by the average number of atoms in a unit cell to the volume of the unit cell.
Mathematically, Atomic Packing Factor (APF):
APF \( = \frac{{{N_{atoms}} ~\times ~{V_{atoms}}}}{{{V_{unit\;cell}}}}\)
Characteristics of various types of structures are shown in the table below:
Characteristics |
BCC |
FCC |
HCP |
a to r relation |
\(a = \frac{{4r}}{{√ 3 }}\) |
\(a = 2√ 2 r\) |
\(a = 2r\) |
The average number of atoms |
2 |
4 |
6 |
Co-ordination number |
8 |
12 |
12 |
APF |
0.68 |
0.74 |
0.74 |
Examples |
Na, K, V, Mo, Ta, W |
Ca, Ni, Cu, Ag, Pt, Au, Pb, Al |
Be, Mg, Zn, Cd, Te |
Calculation:
No of atoms in f.c.c unit cell = 4
\(APF = \frac{{{N_{atoms}}{V_{atom}}}}{{{V_{crystal}}}} = \frac{{4\left( {\frac{4}{3}} \right)\pi {r^3}}}{{{{\left( {a } \right)}^3}}}= \frac{{4\left( {\frac{4}{3}} \right)\pi {r^3}}}{{{{\left( {{{2√2r}}{}} \right)}^3}}}\)
for FCC a = 2√2 r where a is side of the cube and r is atomic radius.
APF = 0.74
Crystal Structures Question 2:
Atomic packing factor of Hexagonal Closed Packed (HCP) structure is:
Answer (Detailed Solution Below)
Crystal Structures Question 2 Detailed Solution
Hexagonal closed pack structure:
- In a hexagonal closedpacked structure the third layer has the same arrangement of spheres as the first layer.
- Since the structure repeats itself after every two layers the stacking for hcp may be described as "ababab".
- The atoms in a hexagonal closed packed structure efficiently occupy 74% of space while 26% is empty space.
- Ex: Mg, Zn
Coordination Number and Number of Atoms Per Unit Cell:
- The hexagonal closed packed (hcp) structure has a coordination number of 12 and contains 6 atoms per unit cell.
- The facecentered cubic (fcc) structure has a coordination number of 12 and contains 4 atoms per unit cell.
- The bodycentered cubic (bcc) structure has a coordination number of 8 and contains 2 atoms per unit cell.
- The simple cubic structure has a coordination number of 6 and contains 1 atom per unit cell.
Crystal structure of Material
FCC: Ni Cu Ag Pt Au Pb Al Austenite or Ƴiron
BCC: V Mo Ta W Ferrite or αiron δferrite or δiron
HCP: Mg Zn
Cobalt: HCP < 420°C FCC > 420°C
Chromium: HCP < 20°C BCC > 20°C
Glass: Amorphous
Important Points
In the crystal structure the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.
The atomic packing factor of different crystal structures is given in the table below:
Structure |
Atomic packing factor |
BCC |
0.68 |
HCP |
0.74 |
FCC |
0.74 |
Diamond cubic |
0.34 |
SC |
0.52 |
Crystal Structures Question 3:
Which of the following is correct?
Answer (Detailed Solution Below)
Crystal Structures Question 3 Detailed Solution
Hexagonal closed pack structure:
- In a hexagonal closedpacked structure the third layer has the same arrangement of spheres as the first layer.
- Since the structure repeats itself after every two layers the stacking for hcp may be described as "ababab".
- The atoms in a hexagonal closed packed structure efficiently occupy 74% of space while 26% is empty space.
- Ex: Mg, Zn
Coordination Number and Number of Atoms Per Unit Cell:
- The hexagonal closed packed (hcp) structure has a coordination number of 12 and contains 6 atoms per unit cell.
- The facecentered cubic (fcc) structure has a coordination number of 12 and contains 4 atoms per unit cell.
- The bodycentered cubic (bcc) structure has a coordination number of 8 and contains 2 atoms per unit cell.
- The simple cubic structure has a coordination number of 6 and contains 1 atom per unit cell.
Crystal structure of Material
FCC: Ni Cu Ag Pt Au Pb Al Austenite or Ƴiron
BCC: V Mo Ta W Ferrite or αiron δferrite or δiron
HCP: Mg Zn
Cobalt: HCP < 420°C FCC > 420°C
Chromium: HCP < 20°C BCC > 20°C
Glass: Amorphous
Important Points
In the crystal structure the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.
The atomic packing factor of different crystal structures is given in the table below:
Structure |
Atomic packing factor |
BCC |
0.68 |
HCP |
0.74 |
FCC |
0.74 |
Diamond cubic |
0.34 |
SC |
0.52 |
Crystal Structures Question 4:
If the radius of an in a close-packed hexagonal crystal is r, the length of the edge of the unit cell a is:
Answer (Detailed Solution Below)
Crystal Structures Question 4 Detailed Solution
Explanation:
Hexagonal Close-Packed (HCP) Crystal Structure
Definition: The hexagonal close-packed (HCP) crystal structure is one of the most efficient ways of arranging spheres in a solid, allowing atoms to pack together as closely as possible. In this structure, each atom has 12 nearest neighbors, and the atoms are packed in such a way that the distances between them are minimized.
Characteristics of various types of structures are shown in the table below:
Characteristics |
BCC |
FCC |
HCP |
a to r relation |
\(a = \frac{{4r}}{{√ 3 }}\) |
\(a = 2√ 2 r\) |
\(a = 2r\) |
The average number of atoms |
2 |
4 |
6 |
Coordination number |
8 |
12 |
12 |
APF |
0.68 |
0.74 |
0.74 |
Examples |
Na K V Mo Ta W |
Ca Ni Cu Ag Pt Au Pb Al |
Be Mg Zn Cd Te |
Crystal Structures Question 5:
Which of the following minerals is an example of a hexagonal close-packed (HCP) crystal structure?
Answer (Detailed Solution Below)
Crystal Structures Question 5 Detailed Solution
Explanation:
Hexagonal Close-Packed (HCP) Crystal Structure:
- The hexagonal close-packed (HCP) crystal structure is one of the most efficient ways of packing spheres, where each atom is surrounded by twelve others. In the HCP structure, the atoms are packed closely together in a repeating pattern that forms a hexagonal lattice. This type of structure is characterized by its high density and coordination number, which is 12.
Structure Details:
- In the HCP crystal structure, the atoms are arranged in layers. The pattern follows an ABAB stacking sequence where each atom in the 'A' layer is directly above or below an atom in another 'A' layer, while the 'B' layer atoms fit into the depressions of the 'A' layers. This results in a hexagonal unit cell with two atoms per unit cell.
Examples of HCP Structures:
- Metals like magnesium (Mg), titanium (Ti), and zinc (Zn) are common examples of elements that crystallize in the HCP structure. Additionally, certain minerals exhibit the HCP structure due to their atomic arrangement.
Top Crystal Structures MCQ Objective Questions
The unit cell of a certain type of crystal is defined by three vectors a, b and c. The vectors are mutually perpendicular, but a ≠ b ≠ c. The crystal structure is
Answer (Detailed Solution Below)
Crystal Structures Question 6 Detailed Solution
Download Solution PDFExplanation:
If the atoms or atom groups in the solid are represented by points and the points are connected, the resulting lattice will consist of an orderly stacking of blocks or unit cells.
- The orthorhombic unit cell is distinguished by three lines called axes of twofold symmetry about which the cell can be rotated by 180° without changing its appearance.
- This characteristic requires that the angles between any two edges of the unit cell be right angles but the edges may be any length.
Important Points
There are 7 types of crystal systems:
Crystal System |
Angles between Axis |
Unit Cell Dimensions |
Cubic |
α = β = γ = 90° |
a = b = c |
Tetragonal |
α = β = γ=90° |
a = b ≠ c |
Orthorhombic |
α = β = γ= 90° |
a ≠ b ≠ c |
Rhombohedral |
α = β = γ ≠ 90° |
a = b = c |
Hexagonal |
α = β = 90°, γ = 120° |
a = b ≠ c |
Monoclinic |
α = γ = 90°, β ≠ 90° |
a ≠ b ≠ c |
Triclinic |
α ≠ β ≠ γ |
a ≠ b ≠ c |
Which of the following is an amorphous material?
Answer (Detailed Solution Below)
Crystal Structures Question 7 Detailed Solution
Download Solution PDFExplanation:
The properties of a material depend not only on the bond strength but also on the arrangement of atoms.
The two types of solid based on the arrangement of their atoms are discussed in the table below.
Crystalline solids |
Non-crystalline/ Amorphous solids |
The arrangement of atoms is in a periodically repeating manner. |
It possesses an entangled chain of atoms without any periodicity. |
It presents a sharp diffraction pattern |
It does not present any sharp diffraction pattern |
It has high density due to its closed packing of atoms in the structure |
It has a lower density as the packing of atoms takes place in a random manner |
It has a sharp melting point |
It melts over a range of temperature |
It breaks along a particular point and direction |
It breaks suddenly and randomly |
Examples are diamonds, metals, salts etc. |
Examples are: Glass, Gels, plastics, various polymers, wax, thin films |
If atom is assumed to a hard sphere, then the value of highest APF (Atomic Packing factor) in metals will be:
Answer (Detailed Solution Below)
Crystal Structures Question 8 Detailed Solution
Download Solution PDFExplanation:
Atomic Packing Factor:
Packing factor is the fraction of the volume of a unit cell that is occupied by "hard sphere" atoms or ions.
It is the sum of the sphere volumes of all atoms within a unit cell (assuming the atomic hard - sphere model) divided by the unit cell volume (total volume).
The atomic packing factor of different crystal structures is given in the table below:
Structure |
Atomic packing factor |
BCC |
0.68 |
HCP |
0.74 |
FCC |
0.74 |
Diamond cubic |
0.34 |
SC |
0.52 |
The number of atoms per unit cell and the number of slip systems, respectively, for a face- centred cubic (FCC) crystal are
Answer (Detailed Solution Below)
Crystal Structures Question 9 Detailed Solution
Download Solution PDFConcept:
In the FCC unit cell effective number of atoms = 8 corner atoms x (1/8) (each atom is shared by 8-unit cells) + 6 face cantered atoms x (1/2) (each shared by two-unit cells) = 4
Unit Cell |
Coordination No. |
No. of Atoms Per Unit Cell |
Atomic packing factor |
Simple Unit Cell |
6 |
1 |
52% |
Body-centred Cubic |
8 |
2 |
68% |
Face-centred Cubic |
12 |
4 |
74% |
Hexagonal Closest Packed |
12 |
6 |
74% |
Diagram |
|
|
|
Effective no. of lattice points |
\(\Rightarrow \frac{1}{8} \times 8 = 1\) |
\(\frac{1}{8} \times 8 + 1 = 2\) |
\(\frac{1}{8} \times 8 + \frac{1}{2} \times 6 = 4\) |
Slip systems: The combination of a slip plane and its direction of slip is known as slip system. Each pattern of atomic arrangements results in different number of slip systems.
- For BCC crystal structure: 48
- For FCC crystal structure: 12
- For Hexagonal close packed structure: 3
Co-ordination number of FCC crystal is
Answer (Detailed Solution Below)
Crystal Structures Question 10 Detailed Solution
Download Solution PDFExplanation:
In the FCC unit cell effective number of atoms = 8 corner atoms x (1/8) (each atom is shared by 8-unit cells) + 6 faces cantered atoms x (1/2) (each shared by two-unit cells) = 4
Unit Cell |
Coordination No. |
No. of Atoms Per Unit Cell |
Atomic packing factor |
Simple Unit Cell |
6 |
1 |
52% |
Body-centred Cubic |
8 |
2 |
68% |
Face-centred Cubic |
12 |
4 |
74% |
Hexagonal Closest Packed |
12 |
6 |
74% |
Diagram |
|
|
|
Effective no. of lattice points |
\(\Rightarrow \frac{1}{8} \times 8 = 1\) |
\(\frac{1}{8} \times 8 + 1 = 2\) |
\(\frac{1}{8} \times 8 + \frac{1}{2} \times 6 = 4\) |
Slip systems: The combination of a slip plane and its direction of slip is known as a slip system. Each pattern of atomic arrangements results in a different number of slip systems.
- For the BCC crystal structure: 48
- For FCC crystal structure: 12
- For Hexagonal close packed structure: 3
Additional InformationCo-ordination Number:
- The coordination number of an atom is the number of atoms it is touching in a unit cell.
Atomic radius of BCC structure is given by ______.
Answer (Detailed Solution Below)
Crystal Structures Question 11 Detailed Solution
Download Solution PDFExplanation
BCC crystal structure: BCC stands for Body-Centered Cubic. In one unit cell, there is one atom at center, 1 atom at each corner. The crystal structure is used for Brittle materials only.
AC = Body diagonal of the unit cell
a = Side of the unit cell
\(a√ 3 = 4r\)
\(r = \frac{{√ 3 a}}{4}\)
characteristics |
BCC |
FCC |
HCP |
a to r relation |
\(a = \frac{{4r}}{{√ 3 }}\) |
a=2r√2 |
\(a = 2r\) |
The average number of atoms |
2 |
4 |
6 |
Co-ordination number |
8 |
12 |
12 |
APF |
0.68 |
0.74 |
0.74 |
Examples |
Na, K, V, Mo, Ta, W |
Ca, Ni, Cu, Ag, Pt, Au, Pb, Al |
Be, Mg, Zn, Cd, Te |
Which of the following is an amorphous material?
Answer (Detailed Solution Below)
Crystal Structures Question 12 Detailed Solution
Download Solution PDFThe correct answer is Glass.
Key Points
- The properties of a material depend not only on the bond strength but also on the arrangement of atoms.
- The two types of solid based on the arrangement of their atoms are discussed in the table below.
Crystalline solids |
Non-crystalline/ Amorphous solids |
The arrangement of atoms is in a periodically repeating manner. |
It possesses an entangled chain of atoms without any periodicity. |
It presents a sharp diffraction pattern |
It does not present any sharp diffraction pattern |
It has high density due to its closed packing of atoms in the structure |
It has a lower density as the packing of atoms takes place in a random manner |
It has a sharp melting point |
It melts over a range of temperature |
It breaks along a particular point and direction |
It breaks suddenly and randomly |
Examples are diamonds, metals, salts, etc. |
Examples are: Glass, Gels, plastics, various polymers, wax, thin films |
Match the crystal structure in Column A with the corresponding packing fractions in Column B of the table
Column A |
Column B |
1. Simple cubic |
P. 0.74 |
2. Hexagonal close-packed |
Q. 068 |
3. Body-centered cubic |
R. 0.52 |
4. Face-centered cubic |
|
Answer (Detailed Solution Below)
Crystal Structures Question 13 Detailed Solution
Download Solution PDFExplanation:
Atomic packing factor
In the crystal structure, the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.
The atomic packing factor of different crystal structures is given in the table below:
Unit Cell |
Coordination No. |
No. of Atoms Per Unit Cell |
Atomic packing factor |
Face-centred Cubic |
12 |
4 |
0.74 |
Simple Unit Cell |
6 |
1 |
0.52 |
Body-centred Cubic |
8 |
2 |
0.68 |
Hexagonal Closest Packed |
12 |
6 |
0.74 |
Co-ordination number: The coordination number of an atom is the number of atoms it is touching in a unit cell.
The effective number of lattice points in the unit cell of simple cubic, body centered cubic, and face centered cubic space lattices, respectively, are
Answer (Detailed Solution Below)
Crystal Structures Question 14 Detailed Solution
Download Solution PDFConcept:
Diagram |
|
|
|
Effective no. of lattice points |
\(\Rightarrow \frac{1}{8} × 8 = 1\) |
\(\frac{1}{8} × 8 + 1 = 2\) |
\(\frac{1}{8} × 8 + \frac{1}{2} × 6 = 4\) |
In the unit cell effective number of atoms = corner atoms × (1/8) + face cantered atoms × (1/2) + 1 (Inner atom)
Unit Cell |
Coordination No. |
No. of Atoms Per Unit Cell |
Atomic packing factor |
Simple Unit Cell |
6 |
1 |
52% |
Body-centred Cubic |
8 |
2 |
68% |
Face-centred Cubic |
12 |
4 |
74% |
Hexagonal Closest Packed |
12 |
6 |
74% |
The crystal structure of cementite is _____
Answer (Detailed Solution Below)
Crystal Structures Question 15 Detailed Solution
Download Solution PDFConcept:
- Cementite is a chemical compound of carbon & Iron. It is denoted by \({F_e}_3C\).
- Iron carbide is normally classified as a “ceramic”. i.e. it is hard, brittle, and insulator.
- It has an orthorhombic crystal structure.
Some other phrases & their crystal structure: -
α – Fe; Ferrite ⇒ BCC
γ – Fe, Austenite ⇒ FCC
\({F_{{e_3}}}C\), cementite ⇒ Orthorhombic
Martensite ⇒ Body-centered tetragonal (BCT)