Crystal Structures MCQ Quiz - Objective Question with Answer for Crystal Structures - Download Free PDF

Last updated on Jun 10, 2025

Latest Crystal Structures MCQ Objective Questions

Crystal Structures Question 1:

Atomic packing factor for FCC structure is:

  1. 0.68
  2. 0.52
  3. 0.74
  4. 0.62

Answer (Detailed Solution Below)

Option 3 : 0.74

Crystal Structures Question 1 Detailed Solution

Explanation:

The atomic packing factor is defined as the ratio of the volume occupied by the average number of atoms in a unit cell to the volume of the unit cell.

Mathematically, Atomic Packing Factor (APF):

APF \( = \frac{{{N_{atoms}} ~\times ~{V_{atoms}}}}{{{V_{unit\;cell}}}}\)

Characteristics of various types of structures are shown in the table below:

Characteristics

BCC

FCC

HCP

a to r relation

\(a = \frac{{4r}}{{√ 3 }}\)

\(a = 2√ 2 r\)

\(a = 2r\)

The average number of atoms

2

4

6

Co-ordination number

8

12

12

APF

0.68

0.74

0.74

Examples

Na, K, V, Mo, Ta, W

Ca, Ni, Cu, Ag, Pt, Au, Pb, Al

Be, Mg, Zn, Cd, Te

Calculation:

No of atoms in f.c.c unit cell = 4

\(APF = \frac{{{N_{atoms}}{V_{atom}}}}{{{V_{crystal}}}} = \frac{{4\left( {\frac{4}{3}} \right)\pi {r^3}}}{{{{\left( {a } \right)}^3}}}= \frac{{4\left( {\frac{4}{3}} \right)\pi {r^3}}}{{{{\left( {{{2√2r}}{}} \right)}^3}}}\)

for FCC a = 2√2 r where a is side of the cube and r is atomic radius.

APF = 0.74

Crystal Structures Question 2:

Atomic packing factor of Hexagonal Closed Packed (HCP) structure is:

  1. 0.52
  2. 0.68
  3. 0.58
  4. 0.74

Answer (Detailed Solution Below)

Option 4 : 0.74

Crystal Structures Question 2 Detailed Solution

Hexagonal closed pack structure:

  • In a hexagonal closedpacked structure the third layer has the same arrangement of spheres as the first layer.
  • Since the structure repeats itself after every two layers the stacking for hcp may be described as "ababab".
  • The atoms in a hexagonal closed packed structure efficiently occupy 74% of space while 26% is empty space.
  • Ex: Mg, Zn

F1 S.S Madhu 14.11.19 D6

 

Coordination Number and Number of Atoms Per Unit Cell:

  • The hexagonal closed packed (hcp) structure has a coordination number of 12 and contains 6 atoms per unit cell.
  • The facecentered cubic (fcc) structure has a coordination number of 12 and contains 4 atoms per unit cell.
  • The bodycentered cubic (bcc) structure has a coordination number of 8 and contains 2 atoms per unit cell.
  • The simple cubic structure has a coordination number of 6 and contains 1 atom per unit cell.

 

Crystal structure of Material

FCC: Ni Cu Ag Pt Au Pb Al Austenite or Ƴiron

BCC: V Mo Ta W Ferrite or αiron δferrite or δiron

HCP: Mg Zn

Cobalt: HCP < 420°C FCC > 420°C

Chromium: HCP < 20°C BCC > 20°C

Glass: Amorphous

Important Points

In the crystal structure the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.

The atomic packing factor of different crystal structures is given in the table below:

Structure

Atomic packing factor

BCC

0.68

HCP

0.74

FCC

0.74

Diamond cubic

0.34

SC

0.52

Crystal Structures Question 3:

Which of the following is correct?

  1. Coordination number of simple cubic structure is 12.
  2. Coordination number of body centered cubic (BCC) structure is 12.
  3. Coordination number of Hexagonal Closed Packed (HCP) structure is 12. 
  4. Coordination number of face centered cubic (FCC) structure is 8.

Answer (Detailed Solution Below)

Option 3 : Coordination number of Hexagonal Closed Packed (HCP) structure is 12. 

Crystal Structures Question 3 Detailed Solution

Hexagonal closed pack structure:

  • In a hexagonal closedpacked structure the third layer has the same arrangement of spheres as the first layer.
  • Since the structure repeats itself after every two layers the stacking for hcp may be described as "ababab".
  • The atoms in a hexagonal closed packed structure efficiently occupy 74% of space while 26% is empty space.
  • Ex: Mg, Zn

F1 S.S Madhu 14.11.19 D6

 

Coordination Number and Number of Atoms Per Unit Cell:

  • The hexagonal closed packed (hcp) structure has a coordination number of 12 and contains 6 atoms per unit cell.
  • The facecentered cubic (fcc) structure has a coordination number of 12 and contains 4 atoms per unit cell.
  • The bodycentered cubic (bcc) structure has a coordination number of 8 and contains 2 atoms per unit cell.
  • The simple cubic structure has a coordination number of 6 and contains 1 atom per unit cell.

 

Crystal structure of Material

FCC: Ni Cu Ag Pt Au Pb Al Austenite or Ƴiron

BCC: V Mo Ta W Ferrite or αiron δferrite or δiron

HCP: Mg Zn

Cobalt: HCP < 420°C FCC > 420°C

Chromium: HCP < 20°C BCC > 20°C

Glass: Amorphous

Important Points

In the crystal structure the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.

The atomic packing factor of different crystal structures is given in the table below:

Structure

Atomic packing factor

BCC

0.68

HCP

0.74

FCC

0.74

Diamond cubic

0.34

SC

0.52

Crystal Structures Question 4:

If the radius of an in a close-packed hexagonal crystal is r, the length of the edge of the unit cell a is:

  1. r/2
  2. r/4
  3. 2r
  4. 2r/3

Answer (Detailed Solution Below)

Option 3 : 2r

Crystal Structures Question 4 Detailed Solution

Explanation:

Hexagonal Close-Packed (HCP) Crystal Structure

Definition: The hexagonal close-packed (HCP) crystal structure is one of the most efficient ways of arranging spheres in a solid, allowing atoms to pack together as closely as possible. In this structure, each atom has 12 nearest neighbors, and the atoms are packed in such a way that the distances between them are minimized.

 

Characteristics of various types of structures are shown in the table below:

Characteristics

BCC

FCC

HCP

a to r relation

\(a = \frac{{4r}}{{√ 3 }}\)

\(a = 2√ 2 r\)

\(a = 2r\)

The average number of atoms

2

4

6

Coordination number

8

12

12

APF

0.68

0.74

0.74

Examples

Na K V Mo Ta W

Ca Ni Cu Ag Pt Au Pb Al

Be Mg Zn Cd Te

Crystal Structures Question 5:

Which of the following minerals is an example of a hexagonal close-packed (HCP) crystal structure? 

  1. Halite 
  2. Al2As3Cu6Cl18
  3. Be3Al2Si6O18
  4. Quart (SiO2)

Answer (Detailed Solution Below)

Option 3 : Be3Al2Si6O18

Crystal Structures Question 5 Detailed Solution

Explanation:

Hexagonal Close-Packed (HCP) Crystal Structure:

  • The hexagonal close-packed (HCP) crystal structure is one of the most efficient ways of packing spheres, where each atom is surrounded by twelve others. In the HCP structure, the atoms are packed closely together in a repeating pattern that forms a hexagonal lattice. This type of structure is characterized by its high density and coordination number, which is 12.

Structure Details:

  • In the HCP crystal structure, the atoms are arranged in layers. The pattern follows an ABAB stacking sequence where each atom in the 'A' layer is directly above or below an atom in another 'A' layer, while the 'B' layer atoms fit into the depressions of the 'A' layers. This results in a hexagonal unit cell with two atoms per unit cell.

Examples of HCP Structures:

  • Metals like magnesium (Mg), titanium (Ti), and zinc (Zn) are common examples of elements that crystallize in the HCP structure. Additionally, certain minerals exhibit the HCP structure due to their atomic arrangement.

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Top Crystal Structures MCQ Objective Questions

The unit cell of a certain type of crystal is defined by three vectors a, b and c. The vectors are mutually perpendicular, but a ≠ b ≠ c. The crystal structure is

  1. Triclinic
  2. Tetragonal
  3. Orthorhombic
  4. Monoclinic

Answer (Detailed Solution Below)

Option 3 : Orthorhombic

Crystal Structures Question 6 Detailed Solution

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Explanation:

If the atoms or atom groups in the solid are represented by points and the points are connected, the resulting lattice will consist of an orderly stacking of blocks or unit cells.

  • The orthorhombic unit cell is distinguished by three lines called axes of twofold symmetry about which the cell can be rotated by 180° without changing its appearance.
  • This characteristic requires that the angles between any two edges of the unit cell be right angles but the edges may be any length.

F9 Tapesh 29-1-2021 Swati D014

Important Points

There are 7 types of crystal systems:

Crystal System

Angles between Axis

Unit Cell Dimensions

Cubic

α = β = γ = 90°

a = b = c

Tetragonal

α = β = γ=90°

a = b ≠ c

Orthorhombic

α = β = γ= 90°

a ≠ b ≠ c

Rhombohedral

α = β = γ ≠ 90°

a = b = c

Hexagonal

α = β = 90°, γ = 120°

a = b ≠ c

Monoclinic

α = γ = 90°, β ≠ 90°

a ≠ b ≠ c

Triclinic

α ≠ β ≠ γ

a ≠ b ≠ c

Which of the following is an amorphous material?

  1. Mica
  2. Lead
  3. Rubber
  4. Glass

Answer (Detailed Solution Below)

Option 4 : Glass

Crystal Structures Question 7 Detailed Solution

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Explanation:

The properties of a material depend not only on the bond strength but also on the arrangement of atoms.

The two types of solid based on the arrangement of their atoms are discussed in the table below.

Crystalline solids

Non-crystalline/ Amorphous solids

The arrangement of atoms is in a periodically repeating manner.

It possesses an entangled chain of atoms without any periodicity.

It presents a sharp diffraction pattern

It does not present any sharp diffraction pattern

It has high density due to its closed packing of atoms in the structure

It has a lower density as the packing of atoms takes place in a random manner

It has a sharp melting point

It melts over a range of temperature

It breaks along a particular point and direction

It breaks suddenly and randomly

Examples are diamonds, metals, salts etc.

Examples are: Glass, Gels, plastics, various polymers, wax, thin films

If atom is assumed to a hard sphere, then the value of highest APF (Atomic Packing factor) in metals will be: 

  1. 0.65
  2. 0.74
  3. 0.98
  4. 0.84

Answer (Detailed Solution Below)

Option 2 : 0.74

Crystal Structures Question 8 Detailed Solution

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Explanation:

Atomic Packing Factor:

Packing factor is the fraction of the volume of a unit cell that is occupied by "hard sphere" atoms or ions.

It is the sum of the sphere volumes of all atoms within a unit cell (assuming the atomic hard - sphere model) divided by the unit cell volume (total volume).

The atomic packing factor of different crystal structures is given in the table below:

Structure

Atomic packing factor

BCC

0.68

HCP

0.74

FCC

0.74

Diamond cubic

0.34

SC

0.52

The number of atoms per unit cell and the number of slip systems, respectively, for a face- centred cubic (FCC) crystal are

  1. 3, 3
  2. 3, 12
  3. 4, 12
  4. 4, 48

Answer (Detailed Solution Below)

Option 3 : 4, 12

Crystal Structures Question 9 Detailed Solution

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Concept:

In the FCC unit cell effective number of atoms = 8 corner atoms x (1/8) (each atom is shared by 8-unit cells) + 6 face cantered atoms x (1/2) (each shared by two-unit cells) = 4

Unit Cell

Coordination No.

No. of Atoms Per Unit Cell

Atomic packing factor

Simple Unit Cell

6

1

52%

Body-centred Cubic

8

2

68%

Face-centred Cubic

12

4

74%

Hexagonal Closest Packed

12

6

74%

 

Diagram

GATE ME 2009 Images-Q15

GATE ME 2009 Images-Q15.1

GATE ME 2009 Images-Q15.2

Effective no. of

lattice points

\(\Rightarrow \frac{1}{8} \times 8 = 1\)

\(\frac{1}{8} \times 8 + 1 = 2\)

\(\frac{1}{8} \times 8 + \frac{1}{2} \times 6 = 4\)

 

Slip systems: The combination of a slip plane and its direction of slip is known as slip system. Each pattern of atomic arrangements results in different number of slip systems.

  • For BCC crystal structure: 48
  • For FCC crystal structure: 12
  • For Hexagonal close packed structure: 3

Co-ordination number of FCC crystal is

  1. 4
  2. 8
  3. 12
  4. 16

Answer (Detailed Solution Below)

Option 3 : 12

Crystal Structures Question 10 Detailed Solution

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Explanation:

In the FCC unit cell effective number of atoms = 8 corner atoms x (1/8) (each atom is shared by 8-unit cells) + 6 faces cantered atoms x (1/2) (each shared by two-unit cells) = 4

Unit Cell

Coordination No.

No. of Atoms Per Unit Cell

Atomic packing factor

Simple Unit Cell

6

1

52%

Body-centred Cubic

8

2

68%

Face-centred Cubic

12

4

74%

Hexagonal Closest Packed

12

6

74%

 

Diagram

GATE ME 2009 Images-Q15

GATE ME 2009 Images-Q15.1

GATE ME 2009 Images-Q15.2

Effective no. of

lattice points

\(\Rightarrow \frac{1}{8} \times 8 = 1\)

\(\frac{1}{8} \times 8 + 1 = 2\)

\(\frac{1}{8} \times 8 + \frac{1}{2} \times 6 = 4\)

 

Slip systems: The combination of a slip plane and its direction of slip is known as a slip system. Each pattern of atomic arrangements results in a different number of slip systems.

  • For the BCC crystal structure: 48
  • For FCC crystal structure: 12
  • For Hexagonal close packed structure: 3

Additional InformationCo-ordination Number: 

  • The coordination number of an atom is the number of atoms it is touching in a unit cell.

Atomic radius of BCC structure is given by ______.

  1. \(\frac{{a\sqrt 3 }}{4}\)
  2. \(\frac{{4a}}{{\sqrt 3 }}\)
  3. \(\frac{a}{{2\sqrt 2 }}\)
  4. \(a{\rm{ }}/{\rm{ }}2\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{{a\sqrt 3 }}{4}\)

Crystal Structures Question 11 Detailed Solution

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Explanation

BCC crystal structure: BCC stands for Body-Centered Cubic. In one unit cell, there is one atom at center, 1 atom at each corner. The crystal structure is used for Brittle materials only. 

F1 Ashik Madhu 14.08.20 D27

AC = Body diagonal of the unit cell

a = Side of the unit cell

\(a√ 3 = 4r\)

\(r = \frac{{√ 3 a}}{4}\)

26 June 1

characteristics

BCC

FCC

HCP

a to r relation

\(a = \frac{{4r}}{{√ 3 }}\)

 

a=2r√2 

\(a = 2r\)

The average number of atoms

2

4

6

Co-ordination number

8

12

12

APF

0.68

0.74

0.74

Examples

Na, K, V, Mo, Ta, W

Ca, Ni, Cu, Ag, Pt, Au, Pb, Al

Be, Mg, Zn, Cd, Te

Which of the following is an amorphous material?

  1. Mica
  2. Lead
  3. Sodium chloride
  4. Glass
  5. None of the above/More than one of the above.

Answer (Detailed Solution Below)

Option 4 : Glass

Crystal Structures Question 12 Detailed Solution

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The correct answer is Glass.

Key Points

  • The properties of a material depend not only on the bond strength but also on the arrangement of atoms.
  • The two types of solid based on the arrangement of their atoms are discussed in the table below.

 

Crystalline solids

Non-crystalline/ Amorphous solids

The arrangement of atoms is in a periodically repeating manner.

It possesses an entangled chain of atoms without any periodicity.

It presents a sharp diffraction pattern

It does not present any sharp diffraction pattern

It has high density due to its closed packing of atoms in the structure

It has a lower density as the packing of atoms takes place in a random manner

It has a sharp melting point

It melts over a range of temperature

It breaks along a particular point and direction

It breaks suddenly and randomly

Examples are diamonds, metals, salts, etc.

Examples are: Glass, Gels, plastics, various polymers, wax, thin films

Match the crystal structure in Column A with the corresponding packing fractions in Column B of the table

Column A

Column B

1. Simple cubic

P. 0.74

2. Hexagonal close-packed

Q. 068

3. Body-centered cubic

R. 0.52

4. Face-centered cubic

 

  1. 1 - P, 2 - R, 3 - Q, 4- Q
  2. 1 - R, 2 - P, 3 - R, 4- Q
  3. 1 - R, 2 - P, 3 - Q, 4- P
  4. 1 - P, 2 - R, 3 - P, 4- Q

Answer (Detailed Solution Below)

Option 3 : 1 - R, 2 - P, 3 - Q, 4- P

Crystal Structures Question 13 Detailed Solution

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Explanation:

Atomic packing factor

In the crystal structure, the atomic packing factor (APF) or packing efficiency or packing fraction is the fraction of volume in a crystal structure that is occupied by constituent particles. It is a dimensionless quantity and always less than unity.

The atomic packing factor of different crystal structures is given in the table below:

Unit Cell

Coordination No.

No. of Atoms Per Unit Cell

Atomic packing factor

Face-centred Cubic

12

4

0.74

Simple Unit Cell

6

1

0.52

Body-centred Cubic

8

2

0.68

Hexagonal Closest Packed

12

6

0.74

26 June 1

Co-ordination number: The coordination number of an atom is the number of atoms it is touching in a unit cell.

The effective number of lattice points in the unit cell of simple cubic, body centered cubic, and face centered cubic space lattices, respectively, are

  1. 1,2,2
  2. 1,2,4
  3. 2,3,4
  4. 2,4,4

Answer (Detailed Solution Below)

Option 2 : 1,2,4

Crystal Structures Question 14 Detailed Solution

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Concept:

Diagram

GATE ME 2009 Images-Q15

GATE ME 2009 Images-Q15.1

GATE ME 2009 Images-Q15.2

Effective no. of

lattice points

\(\Rightarrow \frac{1}{8} × 8 = 1\)

\(\frac{1}{8} × 8 + 1 = 2\)

\(\frac{1}{8} × 8 + \frac{1}{2} × 6 = 4\)

In the unit cell effective number of atoms = corner atoms × (1/8) + face cantered atoms × (1/2) + 1 (Inner atom)

Unit Cell

Coordination No.

No. of Atoms Per Unit Cell

Atomic packing factor

Simple Unit Cell

6

1

52%

Body-centred Cubic

8

2

68%

Face-centred Cubic

12

4

74%

Hexagonal Closest Packed

12

6

74%

The crystal structure of cementite is _____

  1. FCC
  2. BCC
  3. Tetragonal
  4. Orthorhombic

Answer (Detailed Solution Below)

Option 4 : Orthorhombic

Crystal Structures Question 15 Detailed Solution

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Concept:

  • Cementite is a chemical compound of carbon & Iron. It is denoted by \({F_e}_3C\).
  • Iron carbide is normally classified as a “ceramic”. i.e. it is hard, brittle, and insulator.
  • It has an orthorhombic crystal structure.

Some other phrases & their crystal structure: -

α – Fe; Ferrite ⇒ BCC

γ  – Fe, Austenite ⇒ FCC

\({F_{{e_3}}}C\), cementite ⇒ Orthorhombic

Martensite ⇒ Body-centered tetragonal (BCT)
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