Carriers in Semiconductors MCQ Quiz - Objective Question with Answer for Carriers in Semiconductors - Download Free PDF

Last updated on Apr 5, 2025

Latest Carriers in Semiconductors MCQ Objective Questions

Carriers in Semiconductors Question 1:

If mobility of electron is 𝑢𝑒and mobility of hole is 𝑢 then

  1. 𝑢𝑒 = 𝑢
  2. 𝑢𝑒 > 𝑢
  3. 𝑢𝑒 < 𝑢
  4. 𝑢𝑒 ≤ 𝑢

Answer (Detailed Solution Below)

Option 2 : 𝑢𝑒 > 𝑢

Carriers in Semiconductors Question 1 Detailed Solution

Explanation:

The mobility of a charge carrier in a semiconductor material is a measure of how quickly the carrier can move through the material when subjected to an electric field. It is typically denoted as μ.

Electrons and holes are the two types of charge carriers in a semiconductor. Electrons are negatively charged particles, while holes are the absence of an electron in the semiconductor lattice, effectively acting as positively charged particles.

In most semiconductor materials, the mobility of electrons (μe) is higher than the mobility of holes (μh). This is because electrons, being smaller and lighter particles, can move more easily through the crystal lattice compared to the relatively larger and heavier holes.

Thus, we generally have μe > μh.

∴ The correct answer is option 2.

Carriers in Semiconductors Question 2:

Conductivity of an extrinsic semiconductor is considerably influenced by : 

  1. Majority charge carriers originated from doping
  2. Minority charge carriers originated from thermal agitation 
  3. Majority charge carriers originated from thermal agitation 
  4. Minority charge carriers originated from doping

Answer (Detailed Solution Below)

Option 1 : Majority charge carriers originated from doping

Carriers in Semiconductors Question 2 Detailed Solution

The conductivity of an extrinsic semiconductor is considerably influenced by 1) Majority charge carriers originating from doping.

Explanation:

Extrinsic Semiconductors:

  • These are semiconductors that have been doped with impurities to increase their conductivity.
  • Doping introduces either an excess of electrons (n-type) or an excess of holes (p-type).
  • Majority Carriers:
    • In n-type semiconductors, electrons are the majority carriers.
    • In p-type semiconductors, holes are the majority carriers.
    • The concentration of these majority carriers is significantly higher than the concentration of minority carriers.
  • Conductivity:
    • Conductivity is directly proportional to the concentration of charge carriers.
    • Since doping greatly increases the concentration of majority carriers, they have a much greater influence on conductivity than minority carriers.
  • Minority Carriers:
    • Minority carriers are generated by thermal agitation.
    • Although minority carriers contribute to the current, their number is very small compared to majority carriers.
    • Therefore, they have very little effect on the conductivity of an extrinsic semiconductor.

Therefore, the correct answer is:

    1. Majority charge carriers originated from doping

Carriers in Semiconductors Question 3:

The resistivity of Si at 300K is 3.16 × 103 ohm-m. The mobility of electrons and holes in Si are 0.14 m2/V-sec and 0.06 m2/V-sec respectively. The intrinsic carrier density is:

  1. 0.05 × 1019 / m3
  2. 1.00 × 1016 / m3
  3. 4.01 × 1013 / m3
  4. 6.02 × 1012 / m3

Answer (Detailed Solution Below)

Option 2 : 1.00 × 1016 / m3

Carriers in Semiconductors Question 3 Detailed Solution

Concept:

σ = q × nᵢ × (μₑ + μₕ)

  • Intrinsic carrier density (nᵢ) in a semiconductor is related to resistivity and carrier mobility.
  • Conductivity (σ) is given by: σ = 1 / ρ
  • The relation between conductivity and carrier density is:
  • Here, q = Charge of an electron = 1.6 × 10⁻¹⁹ C

 

Calculation:

Resistivity of Si, ρ = 3.16 × 10³ Ω·m

Electron mobility, μₑ = 0.14 m²/V·s

Hole mobility, μₕ = 0.06 m²/V·s

⇒ Conductivity, σ = 1 / ρ = 1 / (3.16 × 10³)

⇒ σ = 3.16 × 10⁻⁴ S/m

⇒ Using the formula,

nᵢ = σ / (q × (μₑ + μₕ))

⇒ nᵢ = (3.16 × 10⁻⁴) / (1.6 × 10⁻¹⁹ × (0.14 + 0.06))

⇒ nᵢ = (3.16 × 10⁻⁴) / (1.6 × 10⁻¹⁹ × 0.20)

⇒ nᵢ = (3.16 × 10⁻⁴) / (3.2 × 10⁻²⁰)

⇒ nᵢ = 0.987 × 10¹⁶

⇒ nᵢ ≈ 1.00 × 10¹⁶ m⁻³

∴ The intrinsic carrier density of Si is 1.00 × 10¹⁶ m⁻³.

Carriers in Semiconductors Question 4:

What is the velocity of conduction electron of silver having Fermi energy 5.52eV

  1. 1.39 × 106 m/s
  2. 2.39 × 106 m/s
  3. 0.89 × 106 m/s
  4. 0

Answer (Detailed Solution Below)

Option 1 : 1.39 × 106 m/s

Carriers in Semiconductors Question 4 Detailed Solution

Given:

The Fermi energy of silver is \(E_F = 5.52 \, \text{eV}\) . We are asked to find the velocity of the conduction electron in silver.

Concept:

  • The velocity of conduction electrons can be calculated using the relation between kinetic energy and velocity. The kinetic energy of the conduction electron is given by:
  • \( E_F = \frac{1}{2} m v^2 \), where:
    • E_F is the Fermi energy,
    • m is the mass of the electron ( \(m = 9.11 \times 10^{-31} \, \text{kg}\) ),
    • v is the velocity of the electron.

The velocity can be found by rearranging the above equation:

\( v = \sqrt{\frac{2 E_F}{m}} \)

Calculation:

Given\( E_F = 5.52 \, \text{eV}\) and \(1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J}\) , we can convert the Fermi energy into joules:

\(⇒ E_F = 5.52 \times 1.602 \times 10^{-19} \, \text{J} = 8.84 \times 10^{-19} \, \text{J} \).

Now, using the equation for velocity:

\(⇒ v = \sqrt{\frac{2 \times 8.84 \times 10^{-19}}{9.11 \times 10^{-31}}} \\ ⇒ v = \sqrt{1.94 \times 10^{12}} \\ ⇒ v = 1.39 \times 10^6 \, \text{m/s} .\)

∴ The velocity of conduction electrons in silver is \(1.39 \times 10^6 \, \text{m/s}\) .

Carriers in Semiconductors Question 5:

Which of the following is correct in regards with Fermi level in semiconductors at 0 Kelvin?

  1. The Fermi level in intrinsic semiconductors lies in the conduction band, 
  2. The Fermi level in N-type semiconductors lies closer to valence band, 
  3. The Fermi level in intrinsic semiconductors lies between conduction band and valence band,
  4. The Fermi level in P-type semiconductors lies closer to conduction band,

Answer (Detailed Solution Below)

Option 3 : The Fermi level in intrinsic semiconductors lies between conduction band and valence band,

Carriers in Semiconductors Question 5 Detailed Solution

The correct option is 3

Concept

The Fermi level is a crucial concept in semiconductor physics. It represents the energy level at which the probability of finding an electron is 50%. The position of the Fermi level in semiconductors can vary depending on the type of semiconductor and its doping level. 

In an intrinsic semiconductor at 0 Kelvin, the Fermi level lies exactly in the middle of the energy gap between the conduction band and the valence band. This is because there are equal numbers of electrons and holes.

At 0 Kelvin, the distribution of electrons is such that they occupy the lowest possible energy states.

Top Carriers in Semiconductors MCQ Objective Questions

Consider the following statements:

The intrinsic carrier concentration of a semiconductor

1. Depends on doping

2. Increase exponentially with a decrease of the bandgap of the semi-conductor.

3. Increase non-linearly with an increase of temperature

4. Increases linearly with increase of temperature

Which of the above statements are correct?

  1. 1, 2 and 3
  2. 1 and 2 only
  3. 2 and 3 only
  4. 2 and 4 only

Answer (Detailed Solution Below)

Option 3 : 2 and 3 only

Carriers in Semiconductors Question 6 Detailed Solution

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Intrinsic carrier concentration depends on various factors defined by an expression

\(n_i^2 = {N_C}{N_V}{e^{ - \frac{{{E_g}}}{{KT}}}}\)

where K = Boltzmann constant

NC = Effective density of states in the conduction band.

NV = Effective density of states in the valence band

T = Temperature, Eg = Bandgap energy

The above equation increases exponentially with the decrease of the bandgap of the semiconductor and increases non-linearly with an increase of temperature.

The Fermi level in a p-type semiconductor lies close to

  1. top of the valence band
  2. bottom of the valence band
  3. top of the conduction band
  4. bottom of the conduction band

Answer (Detailed Solution Below)

Option 1 : top of the valence band

Carriers in Semiconductors Question 7 Detailed Solution

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The Fermi for a p-type semiconductor lies closer to the valence band as shown:

F16 Shubham 30-11-2020 Swati D4

Similarly, the Fermi level for an n-type lies near the conduction band as shown:

Set 3 D1

  • As the temperature increases above zero degrees, the extrinsic carriers in the conduction band and the valence band increases.
  • Since the intrinsic concentration also depends on temperature, ni also increases. But for small values of temperature, the extrinsic concentration dominates in comparison to the intrinsic concentration.
  • As the temperature continues to increase, the semiconductor starts to lose its extrinsic property and becomes intrinsic, as ni becomes comparable to the extrinsic concentration.

 

The Fermi-level in an intrinsic semiconductor is nearly midway between the conductive and valence band as shown:

​        F1 S.B Madhu 24.04.20 D1

The number of holes in N-type silicon with intrinsic value 1.5 × 1010/cm3 and doping concentration of 1017/cm3, by using mass-action law is

  1. 6.67 × 106/cc
  2. 4.44 × 10-25/cc
  3. 1.5 × 10-24/cc
  4. 2.25 × 103/cc

Answer (Detailed Solution Below)

Option 4 : 2.25 × 103/cc

Carriers in Semiconductors Question 8 Detailed Solution

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Concept: 

Extrinsic n-type semiconductors are formed when a pentavalent impurity is added to a pure semiconductor. Examples of pentavalent impurity are Phosphorus and Arsenic.

Also, the law of mass action is used to determine the minority carriers in a doped semiconductor.

According to law:

n.p = ni2

n = concentration of electrons

p = concentration of holes

Also, if the doping concentration is greater than the intrinsic carrier concentration, the majority carrier concentration will be:

n = Nd

Calculation:

Given: ni = 1.5 × 1010 /cm3

Nd = 1017/cm3

Since Nd >> ni, the majority carrier electron concentration will be:

n = Nd = 1017/cm3

Now, the minority carrier holes concentration will be:

\(p=\frac{n_i^2}{N_d}=\frac{(1.5× 10^{10})^2}{10^{17}}\)

p = 2250 /cm3

p = 2.25 × 103 /cm3

For elements having energy gap more than 5 ev, act as:

  1. Semiconductors
  2. Insulators
  3. Superconductors
  4. Conductors

Answer (Detailed Solution Below)

Option 2 : Insulators

Carriers in Semiconductors Question 9 Detailed Solution

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Concept:

Material  Property  Energy Band diagram 
Conductors: In conductors, the conduction band and the valence band overlap, which indicates that the valence electrons can easily move from the conduction band and are free to conduct F1 P.Y Madhu 13.05.20 D11
Insulators: An insulator, there exists a large bandgap between the conduction band and valence band Eg (Eg > 3 eV), which results in no free electrons in the conduction band, and therefore no electrical conduction is possible. F1 P.Y Madhu 13.05.20 D12
Semiconductors:

In a semiconductor, there exists a finite but small band gap between the conduction band and valence band (Eg < 3 eV).

Because of the small bandgap, at room temperature, some electrons from the valence band can acquire enough energy to cross the energy gap and enter the conduction band.

F1 P.Y Madhu 13.05.20 D13

 

Explanation:

From the above explanation, we can see that, 

  • The energy band gap is measured in eV or electron volt and it is the energy separation between the valence band and conduction band.
  • The valence band lies below the conduction band.
  • An insulator has the highest bandgap which is usually greater than 3 eV because the gap between the valence band and conduction band is large. Hence they cannot conduct electricity that well.
  • The energy band gap of conductors is approximately zero because the valence band and conduction band overlap each other.
  • The energy band gap of conductors is <3 eV, i.e. less than insulators and more than conductors because they lie somewhere in between these two.
  • And the below fig represents the energy gap for all three types of material 
  • F1 U.B Madhu 15.11.19 D 12

 

Which among the following is termed as the drift velocity of the charge carrier per unit electric field?

  1. Resistivity
  2. Current density
  3. Mobility
  4. Relative permittivity

Answer (Detailed Solution Below)

Option 3 : Mobility

Carriers in Semiconductors Question 10 Detailed Solution

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In a semiconductor, the movement of charge carriers under the influence of an electric field is called drift.

Mobility is defined as the value of the drift velocity of the charge carrier per unit of electric field strength. Thus, the faster the particle moves at a given electric field strength, the larger the mobility.

Which of the following are immobile?

  1. Electrons
  2. Holes
  3. Ions
  4. None of these

Answer (Detailed Solution Below)

Option 3 : Ions

Carriers in Semiconductors Question 11 Detailed Solution

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The mobile charge can move in and out of the semiconductor, while the fixed charge does not move at all.

Holes and electrons are movable whereas ions are not movable hence they are immobile.

Current in an Intrinsic semiconductor is equal to 

  1. electron current 
  2. Hole Current
  3. Electron current + Hole Current
  4. Displacement current 

Answer (Detailed Solution Below)

Option 3 : Electron current + Hole Current

Carriers in Semiconductors Question 12 Detailed Solution

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Intrinsic semiconductor:

  • It is a crystal having all atoms of the same nature i.e. extremely pure semiconductor is called an intrinsic semiconductor.

          Ex: pure silicon, germanium.

  • At room temperature (300 Kelvin), the electrons in the valence band are moved to the conduction band. When an electron leaves the valence band it creates a vacancy known as a hole. A hole attracts electrons as it is positively charged.
  • In intrinsic semiconductor number of free electrons is equal to the number of holes. i.e. ne = nh
  • Since there is an equal number of both the electrons and holes in an intrinsic semiconductor, the current contribution will be equal from both the charge carriers.
  • The total current passing through intrinsic semiconductors is given by:

           I = Ie + Ih

          Ie = Electron Current

          Ih = Hole current

This is explained with the help of the following diagram:

F1 S.B Deepak 06.03.2020 D5

26 June 1

For an extrinsic semiconductor the current will be because of majority carriers:

  • For an n-type extrinsic semiconductor, the current will be because of the majority carrier electrons (Ie only)
  • For a p-type extrinsic semiconductor, the current will be because of the majority carrier holes (Ih only)

Which of the following is correctly ordered according to the ascending order of band gap energy?

  1. Silicon, Graphite, Diamond
  2. Graphite, Silicon, Diamond
  3. Silicon, Diamond, Graphite
  4. Diamond, Graphite, Silicon

Answer (Detailed Solution Below)

Option 2 : Graphite, Silicon, Diamond

Carriers in Semiconductors Question 13 Detailed Solution

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CONCEPT:

  • Forbidden energy gap (ΔEg): The energy gap between the conduction band and valence band is known as the forbidden energy gap i.e.,

ΔEg = (C.B)min - (V.B)max

F1 P.Y Madhu 13.05.20 D9

  • No free electron is present in the forbidden energy gap.
  • The width of the forbidden energy gap depends upon the nature of the substance.
  • As the temperature increases, the forbidden energy gap decreases very slightly.

 

F1 P.Y Madhu 13.05.20 D11

  • In a conductor, the conduction band is partially filled and the valanced band is partially empty or when the conduction and valance bands overlap. When there is overlap electrons from the valence band can easily move into the conduction band

F1 P.Y Madhu 13.05.20 D12

  • In an insulator, there exists a large bandgap between the conduction band and valence band Eg (Eg > 3 eV). There are no electrons in the conduction band, and therefore no electrical conduction is possible.

F1 P.Y Madhu 13.05.20 D13

  • In semiconductors, there exists a finite but small band gap between the conduction band and valence band (Eg < 3 eV). Because of the small bandgap, at room temperature, some electrons from the valence band can acquire enough energy to cross the energy gap and enter the conduction band.
  • Therefore, the forbidden energy bandgap in conductors, semiconductors, and insulators are in the relation insulator > semiconductor > conductor.

 

Therefore, the correct order is Graphite, Silicon, Diamond

The majority charge carriers in n-type semiconductors are

  1. Holes
  2. Electrons
  3. Neutrons
  4. Protons

Answer (Detailed Solution Below)

Option 2 : Electrons

Carriers in Semiconductors Question 14 Detailed Solution

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  • Extrinsic conductors are those which have added impurities in them, like p-type and n-type semiconductors.
  • The n-type conductors have electrons as major charge carriers.
  • This is because n-type conductors have pentavalent (5 valence electrons) impurities like phosphorous, etc.
  • Elements of Group 5 have five valence electrons, i.e. 1 extra from the Group 4 elements. 4 out of 5 electrons get bonded with the neighbouring Silicon atoms and 1 electron per atom remains extra with the Group 5 elements.
  • Thus, electrons are the major charge carriers in n-type semiconductors.
  • p-type semiconductors have impurities of elements from Group 3 and holes are majority charge carriers in them.

The concentration of minority carriers in an extrinsic semiconductor under equilibrium is

  1. Directly proportional to the intrinsic concentration
  2. Inversely proportional to the intrinsic concentration
  3. Directly proportional to the doping concentration
  4. Inversely proportional to the doping concentration

Answer (Detailed Solution Below)

Option 4 : Inversely proportional to the doping concentration

Carriers in Semiconductors Question 15 Detailed Solution

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The concentration of minority carriers in an extrinsic semiconductor is given by the law of mass action, according to which:

n.p = ni2

n = concentration of electrons in the conduction band

p = concentration of holes in the valence band

ni = intrinsic carrier concentration

Cases:

In an n-type semiconductor, the minority hole concentration is given by:

\(p = \frac{{n_i^2}}{{{N_D}}}\)

ND = Concentration of Donor impurity

In a p-type semiconductor, the minority electron concentration is given by:

\(n = \frac{{n_i^2}}{{{N_A}}}\)

NA = Concentration of Acceptor impurity

Observations:

Thus the minority carriers concentration is:

1) inversely proportional to the doping concentration

2) directly proportional to the square of intrinsic concentration and not to the intrinsic concentration.

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