Acceleration MCQ Quiz - Objective Question with Answer for Acceleration - Download Free PDF
Last updated on May 21, 2025
Latest Acceleration MCQ Objective Questions
Acceleration Question 1:
In some appropriate units, time (t) and position (x) relation of a moving particle is given by t = x² + x.
The acceleration of the particle is:
Answer (Detailed Solution Below)
Acceleration Question 1 Detailed Solution
Correct option is: (2) −2 / (2x + 1)3
t = x2 + x
We have
dt/dx = 2x + 1
⇒ v = dx/dt = 1 / (2x + 1)
⇒ dv/dx = −2 / (2x + 1)2
⇒ a = v × dv/dx = [1 / (2x + 1)] × [−2 / (2x + 1)2]
= −2 / (2x + 1)3
Acceleration Question 2:
The position vector of a particle changes with time according to the relation
Answer (Detailed Solution Below)
Acceleration Question 2 Detailed Solution
CONCEPT:
Position Vector and Acceleration
- The position vector of a particle provides information about its location in space as a function of time.
- Acceleration is the rate of change of velocity with respect to time.
- To find acceleration, we need to differentiate the position vector twice with respect to time.
EXPLANATION:
- Given position vector: r(t) = 15t2 i + (4 - 20t2) j
- First, we find the velocity by differentiating the position vector with respect to time:
- v(t) = dr(t)/dt = 30t i - 40t j
- Next, we find the acceleration by differentiating the velocity with respect to time:
- a(t) = dv(t)/dt = 30 i - 40 j
- At t = 1, the acceleration vector is:
- a(1) = 30 i - 40 j
- To find the magnitude of the acceleration:
- |a(1)| = √(302 + (-40)2)
- |a(1)| = √(900 + 1600)
- |a(1)| = √2500
- |a(1)| = 50
Therefore, the correct answer is option 4: 50.
Acceleration Question 3:
A particle is moving eastwards with a velocity of
Answer (Detailed Solution Below)
Acceleration Question 3 Detailed Solution
First particle moving towards east Initial velocity of particle
After some time velocity towards North velocity of partially
Change in velocity
Average acceleration =
Average acceleration
making
Acceleration Question 4:
The velocity (v)-time (t) graph for the motion of a body is a straight line making an angle 60° with the time axis. Then the body is moving with an acceleration (in m s-2) of
Answer (Detailed Solution Below)
Acceleration Question 4 Detailed Solution
Concept Used:
The slope of the velocity-time graph gives the acceleration of the body. If the graph is a straight line, the slope is constant and represents the acceleration. In this case, the angle between the line and the time axis is given as 60°.
Formula Used:
Acceleration (a) = slope of the velocity-time graph = tan(θ)
Calculation:
We have:
⇒ Acceleration (a) = tan(60°)
⇒ tan(60°) = √3
∴ The correct answer is: √3
Acceleration Question 5:
A hollow metal pipe is held vertically and bar magnet is dropped through it with its length along the axis of the pipe. The acceleration of the falling magnet is (g = acceleration due to gravity)
Answer (Detailed Solution Below)
Acceleration Question 5 Detailed Solution
Concept:
Magnetic Induction and Eddy Currents in a Metal Pipe:
- When a bar magnet is dropped through a hollow metal pipe, it creates a changing magnetic flux as it falls.
- This changing magnetic flux induces eddy currents in the metal pipe due to electromagnetic induction.
- These eddy currents generate their own magnetic field, which opposes the motion of the magnet (Lenz's Law).
- The opposition to the magnet's motion results in a reduced acceleration compared to free fall under gravity.
- Thus, the acceleration of the falling magnet is less than g (acceleration due to gravity).
Calculation:
When a magnet is dropped through the hollow metal pipe, the induced eddy currents create a force that opposes the motion of the magnet.
This results in a reduced net force and consequently, the acceleration of the magnet is less than the gravitational acceleration g.
∴ The acceleration of the falling magnet is less than g. Option 2) is correct.
Top Acceleration MCQ Objective Questions
The formula for finding acceleration is:
Answer (Detailed Solution Below)
Acceleration Question 6 Detailed Solution
Download Solution PDFThe correct answer is (v-u)/t.
CONCEPT:
- Acceleration: The rate of change in velocity is called acceleration. It is denoted by a.
- The SI unit of acceleration is m/s2.
- Equation of motion: The mathematical equations used to find the final velocity, displacements, time, etc of a moving object without considering force acting on it are called equations of motion.
- V = u + at
- Where, V = final velocity, u = initial velocity, a = acceleration of body under motion, and t = time taken by the body under motion.
EXPLANATION:
From the above equation of motion:
V = u + a t
So a = (V - u)/t
- The formula for finding acceleration is (v-u) / t. So option 4 is correct.
Additional Information
- The product of velocity and time (v x t) represents the displacement of a body which represents the shortest distance between two points.
- The reciprocal of time (1 / t) represents the frequency of oscillations which gives the value of the total number of oscillations in the given time.
- The work per unit time (W / t) represents power which is the measurement of the rate of doing work.
The rate of change of ______ of an object is its acceleration.
Answer (Detailed Solution Below)
Acceleration Question 7 Detailed Solution
Download Solution PDFThe correct answer is velocity.
Key Points
- Acceleration is the rate at which velocity changes with respect to time.
- The ultimate outcome of all forces applied to a body, according to Newton's second law, is its acceleration. Acceleration, a vector quantity, determines the frequency at which a body's velocity varies. The formula can be used to express acceleration.
- The overall movement of an object, regardless of direction, is referred to as distance.
- The term "displacement" refers to a shift in an object's position. It's a vector quantity with a magnitude and a direction.
- The product of a particle's mass and velocity is called momentum. Momentum is a vector quantity in the sense that it has both a magnitude and a direction.
The slope of the velocity – time graph for retarded motion is
Answer (Detailed Solution Below)
Acceleration Question 8 Detailed Solution
Download Solution PDFCONCEPT:
- Velocity: The rate of change of displacement of a body is called the velocity of that body.
- Velocity is a vector quantity that has both magnitudes as well as direction.
- Acceleration: The rate of change of velocity is called the acceleration of the body.
- Acceleration is also a vector quantity.
- The slope of any velocity-time graph gives an acceleration of the body.
- Displacement: The minimum path length between two points is called displacement.
- Distance: The total path length between two points is called distance.
EXPLANATION:
- The slope of any graph is the ratio of the vertical change between two points to the horizontal change between the same points.
- In a velocity-time graph, the velocity (v) is present on the vertical axis while time (t) on the horizontal axis, so the slope of the graph is given by:
- Since the rate of change of velocity is termed as acceleration, the slope of a velocity-time graph gives the acceleration.
- Therefore the slope of the velocity-time graph for retarded motion is negative. Therefore option 3 is correct.
Additional Information
- Similarly, the slope of displacement - time graph gives velocity.
- The area under the velocity-time graph gives displacement and the area under the acceleration - time graph gives the change in velocity.
The slope of an acceleration-time graph gives
Answer (Detailed Solution Below)
Acceleration Question 9 Detailed Solution
Download Solution PDFThe correct answer is option 4) i.e. jerk
CONCEPT:
- Acceleration is defined as the rate of change of velocity.
- The SI unit of acceleration is m/s2.
Acceleration, a =
Where v is the velocity during the time period t.
- Jerk or jolt is defined as the rate of change of acceleration with respect to time.
- It is said to occur when an object experiences a sudden pull/push or irregular movement.
EXPLANATION:
- The slope of an acceleration time graph equals the ratio of change in acceleration for the time interval considered.
Slope =
Additional Information
- Velocity is the rate of change of displacement with time. It is obtained from the slope of the displacement-time graph.
- Impulse is the change in momentum of an object when the object is acted upon by a force for a certain amount of time.
- Force is a push or pull that acts on an object and changes its state of rest/motion or shape or direction.
The motion of a particle along a straight line is described by equation: x = 8 + 12t - t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
Answer (Detailed Solution Below)
Acceleration Question 10 Detailed Solution
Download Solution PDFCONCEPT:
ACCELERATION & DECELEARATION:
- Acceleration is the measure of the rate of change of velocity with respect to time, the value of acceleration can be both positive and negative.
- Deceleration is the negative rate of change of velocity.
CALCULATION:
Given - x = 8 + 12t - t3
- As we know, velocity is defined as the rate of change of displacement.
When V = 0, then
⇒ 12 - 3t2 = 0
⇒ 12 = 3t2
⇒ t = 2 sec
- The retardation is given by
The velocity of a body varies with displacement x as v2 = ax2. The acceleration of the body is-(here a is a constant)
Answer (Detailed Solution Below)
Acceleration Question 11 Detailed Solution
Download Solution PDFCONCEPT:
- Velocity (v): The rate of change of displacement of a body is called the velocity of that body.
- Velocity is a vector quantity that has both magnitudes as well as direction.
- Acceleration (a): The rate of change of velocity is called the acceleration of the body.
- Acceleration is also a vector quantity.
- The slope of any velocity-time graph gives an acceleration of the body
a = dv/dt
Velocity (v) = dx/dt
Where x is displacement and t is time
- Uniform acceleration: When the acceleration is constant then it is called uniform accelerated motion.
- Non-uniform acceleration: When the acceleration is not constant then the motion is non-uniform accelerated motion.
CALCULATION:
Given that:
v2 = ax2
Differential both sides with respect to x,
2v (dv/dx) = 2ax
Since a = dv/dt, and Velocity (v) = dx/dt
Now
Hence acceleration (a) = v(dv/dx) = ax
- Since a is constant so acceleration will be a variable that changes with displacement x and hence non-uniform acceleration.
Acceleration is equal to the rate of change of _________.
Answer (Detailed Solution Below)
Acceleration Question 12 Detailed Solution
Download Solution PDFThe correct answer is velocity.
Key Points
CONCEPT:
- Velocity/ speed: The rate of change of displacement/distance of a body is called the velocity/speed of that body.
- Velocity is a vector quantity that has both magnitudes as well as direction.
- Acceleration: The rate of change of velocity is called the acceleration of the body.
- Acceleration is also a vector quantity.
- The slope of any velocity-time graph gives an acceleration of the body.
- Displacement: The minimum path length between two points is called displacement.
- Distance: The total path length between two points is called distance.
Explanation:
From the above explanation, we can see that,
- Acceleration is the rate of change of velocity
- In other words, it is the ratio of change in velocity and time taken
- It has SI units of m/s2 and is also the derivative of velocity
Additional Information
Name | Description |
Displacement | The shortest distance between two points |
Speed | Distance travelled per unit time |
Jerk | Rate of change of acceleration |
The acceleration-time graph of a moving body is shown in the figure below. The maximum change in-velocity of the body will be:
Answer (Detailed Solution Below)
Acceleration Question 13 Detailed Solution
Download Solution PDFConcept:
Acceleration:
- It is defined as the rate of change of velocity with respect to time.
- Formula, acceleration,
where, dv = change in velocity, dt = change in time - The SI unit of acceleration is m/s2.
- It is a vector quantity because it has both magnitude and direction.
- The area under the acceleration - time graph represents the change in velocity.
Calculation:
We know that,
The area under the acceleration - time graph represents the change in velocity
Hence, the maximum change in velocity is 60m/s.
Additional Information
Velocity:
- It is defined as the rate of change of displacement with respect to time.
- Formula, velocity,
where ds = change in displacement, dt = change in time - The SI unit of velocity is m/s.
- The area enclosed under the velocity-time graph gives Displacement.
When a ball is thrown in vertically upward direction then which of the following remains constant?
Answer (Detailed Solution Below)
Acceleration Question 14 Detailed Solution
Download Solution PDFCONCEPT:
- Velocity (v): The rate of change of position i.e. rate of displacement with time is called velocity.
- It is a vector quantity.
- Speed (v): The rate of change in distance is called speed. It is a scalar quantity.
- Acceleration (a): The rate of change of velocity is called the acceleration of the body.
- Acceleration is also a vector quantity.
- Momentum (p): The product of mass and velocity is called momentum.
- It is a vector quantity.
EXPLANATION:
- Acceleration due to gravity: The earth always attracts the body towards its centre and the acceleration due to this force is called acceleration due to gravity.
- It is denoted by g.
g = 10 m/s2 which is constant.
- When a ball is thrown in the air then this acceleration acts on it. Thus the acceleration of the ball remains constant which is equal to g in a downward direction. So option 3 is correct.
- Due to this acceleration, the speed, velocity and momentum of the ball changes with time as the velocity reduce because of retardation due to gravity.
The slope of a velocity - time graph (v-t) gives-
Answer (Detailed Solution Below)
Acceleration Question 15 Detailed Solution
Download Solution PDFThe correct option is 4.
CONCEPT:
- Velocity (v): The rate of change of position i.e. rate of displacement with time is called velocity.
Where s2 = displacement of the object at t2 and s1 = displacement of the object at t1
- It is a vector quantity.
EXPLANATION:
- The slope of any graph is the ratio of the vertical change between two points to the horizontal change between the same points.
- In a velocity-time graph, the velocity (v) is present on the vertical axis while time (t) on the horizontal axis, so the slope of the graph is given by
- Since the rate of change of velocity is termed as acceleration, the slope of a velocity-time graph gives the acceleration.