555 Timer MCQ Quiz - Objective Question with Answer for 555 Timer - Download Free PDF
Last updated on Jun 10, 2025
Latest 555 Timer MCQ Objective Questions
555 Timer Question 1:
What does the discharge transistor do in the 555 timer circuit?
Answer (Detailed Solution Below)
555 Timer Question 1 Detailed Solution
Explanation:
Function of the Discharge Transistor in a 555 Timer Circuit
Definition: The discharge transistor in a 555 timer circuit is a key component responsible for controlling the timing cycle. It works by discharging the external capacitor connected to the circuit, effectively stopping the timing process and preparing the circuit for the next cycle.
Working Principle: The 555 timer is a versatile IC used for generating time delays or oscillations. Its operation relies heavily on the charging and discharging of an external capacitor connected to the circuit. The discharge transistor plays a crucial role during the discharging phase. When the timer reaches the end of its timing cycle, the discharge transistor provides a low-impedance path for the capacitor to discharge its stored energy to ground. This action resets the timing cycle, ensuring that the timer is ready for the next operation.
Key Role:
- The discharge transistor is connected to pin 7 of the 555 timer IC.
- During the timing cycle, the capacitor charges via an external resistor. Once the cycle ends, the discharge transistor is activated.
- Activation of the discharge transistor allows the capacitor to discharge rapidly to ground, halting the timing process and resetting the circuit.
Advantages:
- Ensures precise timing cycles by resetting the capacitor to its initial state.
- Allows for repetitive operations in oscillatory and timing applications.
- Contributes to the reliability and stability of the 555 timer circuit.
Applications: The discharge transistor is integral to the 555 timer's functionality in applications such as:
- Generating time delays in monostable mode.
- Producing square wave signals in astable mode.
- Pulse width modulation (PWM).
- Frequency generation and signal modulation.
Correct Option Analysis:
The correct option is:
Option 1: Discharge the external capacitor to stop the timing.
This option accurately describes the role of the discharge transistor. Its primary function is to provide a path for the capacitor to discharge to ground, effectively stopping the timing cycle and resetting the circuit for subsequent operations. This functionality is crucial for ensuring the proper operation of the 555 timer in both monostable and astable modes.
Additional Information
To further understand the analysis, let’s evaluate the other options:
Option 2: Charge the external capacitor to stop the timing.
This option is incorrect. The discharge transistor does not charge the capacitor; instead, it discharges it. Charging the capacitor is performed by an external resistor during the timing cycle, and it is unrelated to the operation of the discharge transistor.
Option 3: Discharge the external capacitor to start the timing over again.
This option is partially correct but misleading. While the discharge transistor does allow the external capacitor to discharge, its primary purpose is to stop the timing process rather than directly start it over again. The capacitor discharge resets the circuit, allowing the timer to be ready for the next cycle, but the timing restart depends on external triggers or configurations.
Option 4: Charge the external capacitor to start the timing over again.
This option is incorrect. Charging the external capacitor initiates the timing cycle but is not the function of the discharge transistor. Charging occurs via an external resistor connected to the circuit, whereas the discharge transistor is responsible for halting the timing process by discharging the capacitor.
Conclusion:
The discharge transistor is an essential component of the 555 timer circuit, ensuring precise and repetitive timing operations by discharging the external capacitor to ground. This action halts the timing process and resets the circuit, making it ready for the next operation. Understanding the role of the discharge transistor is crucial for the effective utilization of 555 timer ICs in various applications, such as pulse generation, oscillation, and signal modulation.
555 Timer Question 2:
For Astable-IC555 based multivibrator, TOFF = 0.69CR2. Between which pins of IC 555, R2 is connected :
Answer (Detailed Solution Below)
555 Timer Question 2 Detailed Solution
Concept:
In an astable multivibrator configuration using the IC 555 timer, the output oscillates continuously between high and low states without requiring any external triggering. The timing of the high and low periods is determined by the values of two resistors (R1 and R2) and a capacitor (C).
The time for which the output remains low (TOFF) is given by:
\( T_{OFF} = 0.693 \times R_2 \times C \)
Calculation:
In the astable configuration:
- Resistor R1 is connected between pin 7 (Discharge) and VCC
- Resistor R2 is connected between pin 7 (Discharge) and pin 2/6 (Trigger/Threshold, which are connected together)
- Capacitor C is connected between pin 2/6 and ground
Since TOFF depends only on R2 and C, and the discharge path goes through pin 7, R2 must be connected between pin 7 and the capacitor (which is at pin 2).
Therefore, R2 is connected between pin 7 and pin 2.
555 Timer Question 3:
For an astable multivibrator using IC 555, if the values of R1, R2 and C are 47 kΩ, 100 kΩ, and 10 μF respectively, what is the time period of the output waveform?
Answer (Detailed Solution Below)
555 Timer Question 3 Detailed Solution
Concept
An astable multivibrator using IC 555 is an oscillator circuit that generates a continuous square wave output. The time period
\( T = 0.693 \times (R_1 + 2R_2) \times C \)
where R1 & R2 are the resistances in ohms (Ω)
C is the capacitance in farads (F)
Calculation:
\( T = 0.693 \times (47,000 + 200,000) \times 10 \times 10^{-6} \)
\( T = 0.693 \times 247,000 \times 10 \times 10^{-6} \)
\( T_{s} = 0.693 \times 2.47 \)
\( T_{s} = 1.71 \) sec
Therefore, the time period of the output waveform is 1.71 seconds, which corresponds to option 4.
555 Timer Question 4:
In a monostable multivibrator using IC 555, if the resistance R is 100 kΩ and the capacitance C is 10 μF, what is the pulse width of the output?
Answer (Detailed Solution Below)
555 Timer Question 4 Detailed Solution
Concept
A monostable multivibrator using IC 555 generates a single output pulse in response to a trigger input. The duration of this pulse (also known as pulse width) is determined by the external resistor (R) and capacitor (C) connected to the IC.
The pulse width (T) is given by the formula:
\( T = 1.1 \times R \times C \)
where,
- R is the resistance in ohms (Ω)
- C is the capacitance in farads (F)
Calculation
Given,
- R = 100 kΩ = 100,000 Ω
- C = 10 μF = 10 x 10-6 F
Using the formula:
\( T = 1.1 \times 100,000 \times 10 \times 10^{-6} \) sec
\( T = 1.1 \times 100,000 \times 0.00001 \) sec
\( T = 1.1 \times 1 \) sec
Thus, the pulse width of the output is 1.1 seconds.
The correct answer is option 4.
555 Timer Question 5:
The range of signal generating frequencies for a function generator is ________.
Answer (Detailed Solution Below)
555 Timer Question 5 Detailed Solution
Function generator
- A function generator is an electronic test instrument that produces various types of electrical waveforms over a wide range of frequencies.
- Some of the most common waveforms produced by the function generator are the sine wave, square wave, triangular wave, and sawtooth shapes.
- Although function generators cover both audio and radio frequencies, they are usually not suitable for applications that need low distortion or stable frequency signals. The range of signal-generating frequencies for a function generator is 0.01 Hz to 100 kHz.
- Function generators are essential for various applications, including signal analysis, circuit testing, and research and development in electronics.
- Function generators, like most signal generators, may also contain an attenuator, various means of modulating the output waveform, and often the ability to automatically and repetitively "sweep" the frequency of the output waveform between two operator-determined limits. This capability makes it very easy to evaluate the frequency response of a given electronic circuit.
Top 555 Timer MCQ Objective Questions
Astable multivibrator is
Answer (Detailed Solution Below)
555 Timer Question 6 Detailed Solution
Download Solution PDF- An astable multivibrator is a square wave generator.
- Astable multivibrators generally have an even 50% duty cycle.
- It means 50% of the cycle time the output is “HIGH” and the remaining 50% of the cycle time the output is “OFF”.
- A free-running multivibrator that has no stable states but switches continuously between two states this action produces a train of square wave pulses at a fixed frequency or constant frequency.
Important Points
An astable multivibrator is a free-running oscillator.
Time period of square pulse (T0) = 0.69 (RA + 2RB)C
Clock frequency = 1/T0
= \(\frac{1.45}{(R_A + 2R_B)C}\)
Monostable multivibrator:
- The Monostable Multivibrator circuit has only ONE stable state making it a “one-shot” pulse generator.
- It is used as a pulse stretcher.
- Time period of monostable multivibrator (T) = RC ln3
Bistable multivibrator:
- It operates in a similar fashion to flip-flops producing one of two stable outputs that are the complement of each other.
- It is equivalent to a flip flop.
- It is used as a frequency divider.
A multivibrator is a circuit which generates
Answer (Detailed Solution Below)
555 Timer Question 7 Detailed Solution
Download Solution PDFA multivibrator using a 555 timer:
An astable multivibrator is also called a Square wave generator or Free running oscillator.
It generates a square wave output.
The schematic diagram of the Astable multivibrator using a 555 timer is shown below.
The output waveform:
Hence, The output waveform of a multivibrator is a Square wave.
A stable multivibrator operating at 100 Hz has a discharge time 2 ms. Find the duty cycle of the circuit
Answer (Detailed Solution Below)
555 Timer Question 8 Detailed Solution
Download Solution PDF555 timer A stable Multivibrator pin diagram is shown below:
\(Duty ~Cycle = \frac{T_{on}}{T_{on}+T_{off}}\)
Total time = 1/frequency = 10 ms
Toff = 2 ms
Ton + Toff = Total time
Ton = (10 - 2) = 8 ms
\(Duty ~Cycle = \frac{8}{10} = 80\)%
For trigger voltage less than 1/3 Vcc, the output of IC 555 is:
Answer (Detailed Solution Below)
555 Timer Question 9 Detailed Solution
Download Solution PDF- A low voltage (less than 1/3 the supply voltage) applied for short time to the trigger input that cause output go high.
- The output will remain high until a high voltage is applied to the threshold input.
- In output low state the voltage will be close to 0 V.
Additional Information 555 Timer:
- Pin 5 of 555 Timer is the control pin.
- This makes the oscillator cycle more consistent.
- This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
Which of the following statement is correct for 555 IC timers?
Answer (Detailed Solution Below)
555 Timer Question 10 Detailed Solution
Download Solution PDF555 timer:
The 555 timer IC is an integrated circuit used in a variety of timer, pulse generation, and oscillator applications.
It has three operating modes
Astable mode – In this mode, the 555 IC can be used as an oscillator, pulse generator, logic clocks, etc.
Monostable mode – In this mode, the 555 functions as a ‘one-shot’ pulse generator and finds uses in frequency divider, timers, pulse detection, touch switches.
Bistable mode – In this mode, the 555 IC can be operated as a flip-flop, latches.
555 timer IC with the description of pins is shown below:
The most popular IC used in timing circuit is
Answer (Detailed Solution Below)
555 Timer Question 11 Detailed Solution
Download Solution PDF555 timer:
The 555 timer IC is an integrated circuit used in a variety of timer, pulse generation, and oscillator applications.
It has three operating modes
Astable mode – In this mode, the 555 IC can be used as an oscillator, pulse generator, logic clocks, etc.
Monostable mode – In this mode, the 555 functions as a ‘one-shot’ pulse generator and finds uses in frequency divider, timers, pulse detection, touch switches.
Bistable mode – In this mode, the 555 IC can be operated as a flip-flop, latches.
555 timer IC with the description of pins is shown below:
What is the time period of a monostable 555 multivibrator?
Answer (Detailed Solution Below)
555 Timer Question 12 Detailed Solution
Download Solution PDFThe correct option is 3
Concept:
Monostable multivibrator using 555 timers:
A monostable circuit generates pulse output if the trigger is applied.
It is also called a one-shot multivibrator.
555 timer is needed to produce some time delay in the circuit.
The circuit diagram is shown below.
Formula:
The time period of monostable multivibrator = 1.1 RC in Seconds
The 555 timer can be used in which of the following configurations?
Answer (Detailed Solution Below)
555 Timer Question 13 Detailed Solution
Download Solution PDF555 timer has 2 modes
1. Monostable multivibrator
The applications of monostable multivibrator include:
- Pulse width Modulator
- Linear Ramp generator
- frequency divider
- pulse stretcher
2. Astable multivibrator
- Square Wave Generator
- voltage-controlled oscillator
- FSK generator
- free running oscillator
Additional Information
555 Timer:
- Pin 5 of 555 Timer is the control pin.
- This makes the oscillator cycle more consistent.
- This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
The control terminal (pin5) of 555 timer IC is normally connected to ground through a capacitor (∼ 0.01μF). This is to
Answer (Detailed Solution Below)
555 Timer Question 14 Detailed Solution
Download Solution PDFControl pin of 555 Timer:
- The control pin on the 555 timers is normally connected to the ground through a capacitor (∼ 0.01μF because the noise from the supply line can ride through this simple divider adding small capacitor filters out high-frequency noise that can cause the comparison point to vary slightly
- Pin 5 of 555 Timer is the control pin.
- This makes the oscillator cycle more consistent.
- This pin can also be used to change the internal voltage reference to allow modifying the oscillator frequency or duty cycle.
IC 555 has three operating modes namely:
- Bistable mode or Schmitt Trigger
- Monostable Mode: In this mode, the 555 functions as a pulse generator.
- Astable(Free running) Mode: In this mode, the 555 operates as an oscillator.
Answer (Detailed Solution Below)
555 Timer Question 15 Detailed Solution
Download Solution PDFThe following diagram represents the Schmitt trigger.
Schmitt trigger
The output of the Schmitt trigger is always either VCC or -VEE
The feedback voltage (Vf) can be VUT or VLT
VUT is known as the upper threshold voltage and is given by:
\(V_{UT}=V_{CC}\times{R_2\over R_1+R_2}\)
VLT is known as the lower threshold voltage and is given by:
\(V_{LT}=-V_{EE}\times{R_2\over R_1+R_2}\)
Case 1: When Vf > Vi
Vout = VCC
Vf = VUT
Case 2: When Vf < Vi
Vout = -VEE
Vf = VLT
The output waveform of the Schmitt trigger is: