Question
Download Solution PDFWhen 18 is included in a list of natural numbers, the average of these numbers is increased by 2. When 8 is included in this new list of natural numbers, the average of these numbers in the new list remains the same. If there are N natural numbers in the original list of numbers and their average is X, find the value of N and X, respectively.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
According to the question,
(Nx + 18) = (N + 1) × (x + 2)
⇒ Nx + 18 = Nx + 2N + x + 2
⇒ 2N + x = 16
⇒ (N + x)+ N = 16 … (i)
Again, (Nx + 18 + 8) = (N + 2) × (x + 2)
⇒ Nx + 26 = Nx + 2N + 2x + 4
⇒ 2N + 2x = 22
⇒ N + x = 11, put the value in equation (i) we get,
11 + N = 16
⇒ N = 5 now put the value in equation (i), we get x = 6
∴ The correct answer is 5, 6
Last updated on Jun 11, 2025
-> The UGC NET Exam Schedule 2025 for June has been released on its official website.
-> Check UPSC Prelims Result 2025, UPSC IFS Result 2025, UPSC Prelims Cutoff 2025, UPSC Prelims Result 2025 Name Wise & Rollno. Wise
-> The UGC NET Application Correction Window 2025 is available from 14th May to 15th May 2025.
-> The UGC NET 2025 online application form submission closed on 12th May 2025.
-> The June 2025 Exam will be conducted from 21st June to 30th June 2025
-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.
-> The exam is conducted bi-annually - in June and December cycles.
-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions.
-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.