What will be the ratio of the electric field due to the dipole on its axial and equatorial lines?

CONCEPT:

Electric Field Intensity:

• The electric field intensity at any point is the strength of the electric field at the point.
• It is defined as the force experienced by the unit positive charge placed at that point.

\(\vec E = \frac{{\vec F}}{{{q_o}}}\)

Where F = force and q_o = small test charge

• The magnitude of the electric field is

\(E = \frac{{kq}}{{{r^2}}}\)

Where K = constant called electrostatic force constant, q = sorce charge and r = distance

EXPLANATION:

• The magnitude of the electric field of a short dipole at an axial point at a distance r from its center is

\({E_{axial}} = \frac{{2kp}}{{{r^3}}}\)      ------ (1)

• The magnitude of the electric field of a short dipole at an equatorial point at a distance r from its center is

\({E_{equi}} = \frac{{kp}}{{{r^3}}}\)        ------ (2)

On dividing 1 and 2, we get

\(\frac{{{E_{axial}}}}{{{E_{equi}}}} = \frac{2}{1}\)