What is the equation of the line midway between the lines 3x – 4y + 12 = 0 and 3x – 4y = 6?

  1. 3x – 4y – 9 = 0
  2. 3x – 4y + 9 = 0
  3. 3x – 4y – 3 = 0
  4. 3x – 4y + 3 = 0

Answer (Detailed Solution Below)

Option 4 : 3x – 4y + 3 = 0
Free
NDA 01/2025: English Subject Test
30 Qs. 120 Marks 30 Mins

Detailed Solution

Download Solution PDF

Concept:

Distance between two parallel lines ax + by + c1 = 0 and ax + by + c2 = 0 is 

 

Calculation:

We have, 3x – 4y + 12 = 0 and 3x – 4y = 6⇒ 3x – 4y - 6 = 0

∴ Distance between them = 

= 18/5

 

 

Let, equation of line midway between the given lines 3x - 4y + c = 0

As, it is in the middle, distance from line 3x – 4y + 12 = 0 will be 

Now, 9/5 =

⇒ 12 - c = 9

⇒ c = 3

Hence, option (4) is correct.

Latest NDA Updates

Last updated on Jun 18, 2025

->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Hot Links: teen patti diya teen patti list teen patti joy vip teen patti win teen patti palace