Two infinite plane parallel sheets having surface charge density +σ and –σ are kept parallel to each other at a small separation distance d. The electric field at any point in the region between the plates is

This question was previously asked in
Navik GD Physics 21 March 2021 (All Shifts) Questions
View all Indian Coast Guard Navik GD Papers >
  1. zero

Answer (Detailed Solution Below)

Option 2 :
Free
CRPF Head Constable & ASI Steno (Final Revision): Mini Mock Test
40 Qs. 40 Marks 45 Mins

Detailed Solution

Download Solution PDF

CONCEPT:

Gauss’s Law:

The total electric flux through a closed surface is 1/εo times the charge enclosed in the surface i.e. 

But we know that Electrical flux through a closed surface is 

Where, E = electric field, q = charge enclosed in the surface, and εo = permittivity of free space.

Derivation:

 

The electric field at a point due to an infinite sheet of charge is

Where

σ = surface charge density.

Here,

E1: Electric Field due to sheet having surface charge density +σ

E2: Electric Field due to sheet having surface charge density -σ

The electric field at any point in the region between the plates is

E = E1 + E2

Latest Indian Coast Guard Navik GD Updates

Last updated on Jun 11, 2025

-> The Indian Coast Guard Navik GD is a prestigious exam for those who want to serve the country in Defence Services.

-> A total of 260 vacancies have been released through the Coast Guard Enrolled Personnel Test (CGEPT) for the 01/2026 and 02/2026 batch.

-> Candidates can apply online from 11th to 25th June 2025.

-> Candidates who have completed their 10+2 with Maths and Physics are eligible for this post. 

-> Candidates must go through the Indian Coast Guard Navik GD previous year papers.

More Applications of Gauss’s Law Questions

More Electric Fields and Gauss' Law Questions

Hot Links: teen patti online game teen patti baaz teen patti lotus