Two identical amplifiers each having an upper cut-off frequency fH are cascaded with negligible loading effect. What is the modified fH now?

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KVS TGT WET (Work Experience Teacher) 23 Dec 2018 Official Paper
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  1. \(\frac{f_H}{\sqrt{\sqrt{2}-1}}\)
  2. \({f_H}{\sqrt{\sqrt{2}-1}}\)
  3. \(\frac{f_H}{2}\)
  4. 2fH

Answer (Detailed Solution Below)

Option 2 : \({f_H}{\sqrt{\sqrt{2}-1}}\)
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Detailed Solution

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Concept: Assuming all stages are identical and non-interacting (Proper impedance matching)\(f_{cascaded} = {f_H}{\sqrt{{2^\frac{1}{n}}-1}}\)

where \(f_{cascaded} =\)Higher 3 -dB frequency of the multi-stage amplifier

 \(f_H\) = Higher 3 -dB frequency of all individual stages

 n= Number of stages in the multistage amplifier

 Putting n =2 we get,

 \(f_{cascaded}={f_H}{\sqrt{\sqrt{2}-1}}\)

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