Two blocks with masses M and m are in contact with each other and are resting on a horizontal frictionless floor. When horizontal force is applied to the heavier, the blocks accelerate to the right. The force between the two blocks is

subject test 1 som&em images Q21

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ISRO Scientist ME 2011 Paper
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  1. (M + m) F/m
  2. MF/m
  3. mF/M
  4. mF/(M + m)

Answer (Detailed Solution Below)

Option 4 : mF/(M + m)
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Detailed Solution

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Concept:

From the free body diagram:

subject test 1 som&em images Q21a

F – N = Ma     … (i)

And N = ma    … (ii)

Therefore, \(a = \frac{{F}}{{\left( {m + M} \right)}}\)

From equation (ii), we get

\(N = \frac{{mF}}{{\left( {m + M} \right)}}\)

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