Question
Download Solution PDFThe resistance of a wire is R. If the length of the wire is doubled and the radius gets halved by stretching, then the new resistance will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- Resistance: The obstruction offered to the flow of current is known as the resistance.
- Mathematically it can be written as
\(R = \frac{{\rho l}}{A}\)
Where R = resistance, l = length, A = area of cross-section and ρ = resistivity
EXPLANATION:
Given – length of wire before stretching = l and radius of wire before stretching = r, length of wire after stretching (l1) = 2l and radius of wire after stretching (r1) = r/2
- The resistance of wire before stretching is
\(R = \frac{{\rho l}}{A} = \frac{{\rho l}}{{\pi {r^2}}}\)
- The resistance of wire after stretching is
\({R_1} = \frac{{\rho \left( {2l} \right)}}{{\pi {{\left( {\frac{r}{2}} \right)}^2}}} = \frac{{8\rho l}}{{\pi {r^2}}} = 8R{\rm{\;}}\left[ {As,\;R = \frac{{\rho l}}{{\pi {r^2}}}} \right]\)
- The resistance of wire after stretching will be eight times that of resistance of wire before stretching.
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