The radius of the largest sphere which fits properly at the edge of a body centered cubic unit cell is (Edge length is represented by ‘a’)

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JEE Mains Previous Paper 1 (Held On: 11 Jan 2019 Shift 2)
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  1. 0.134 a
  2. 0.027 a
  3. 0.047a
  4. 0.067 a

Answer (Detailed Solution Below)

Option 4 : 0.067 a
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JEE Main 04 April 2024 Shift 1
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90 Questions 300 Marks 180 Mins

Detailed Solution

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Concept:

  • The body-centered cubic unit cell has atoms at each of the eight corners of a cube plus one atom in the center of the cube.
  • Each of the corner atoms is the corner of another cube so the corner atoms are shared among eight unit cells.

Calculation:

For body-centered cubic bcc structure,

Radius, (R) = (a×√3)/4    or a×√3 = 4×R  --- (1)

Where, a = edge length.

According to the question, the structure of a cubic unit cell can be shown as follows:

∴ a = 2(R + r)

On substituting the value of R from Eq. (1) and Eq (2), we get

\(\frac{a}{2}=\frac{√{3}}{4}a+r\)

\(r=\frac{a}{2}=\frac{√{3}}{4}a=2a-\frac{√{3a}}{4}\)

\(r=\frac{a\left( 2-√{3} \right)}{4}\)

r = 0.067 a.
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