The present age of A is twice the age of B. 15 years ago, the age of A was thrice the age of B. Then 25 years ago, the age of A was:

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  1. 7 times the age of B
  2. 6 times the age of B
  3. 5 times the age of B
  4. 4 times the age of B

Answer (Detailed Solution Below)

Option 1 : 7 times the age of B
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CT 1: Indian Polity (Making of the Constitution రాజ్యాంగాన్ని రూపొందించడం) Part 1
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Detailed Solution

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Given:

The present age of A is twice the age of B.

15 years ago, the age of A was thrice the age of B.

Formula used:

Let the present age of B = x years.

Then, the present age of A = 2x years.

15 years ago: A's age = (2x - 15), B's age = (x - 15).

Calculations:

Given, 15 years ago A's age was thrice B's age:

2x - 15 = 3(x - 15)

⇒ 2x - 3x = -45 + 15

⇒ x = 30

Present age of B = x = 30 years.

Present age of A = 2x = 60 years.

25 years ago:

A's age = 60 - 25 = 35 years.

B's age = 30 - 25 = 5 years.

⇒ 25 years ago, A's age was 35 = 7 × 5 (7 times the age of B).

∴ The correct answer is option (1).

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