Question
Download Solution PDFThe population of a city in the first three continuous years is given as 6000, 8000 and 10000 respectively. What is the population of the city in the fourth continuous year, according to the geometric increase method?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For geometric increase method,
Pn = P × (1+r)n
Where
Pn = Future Population, P = Latest known population and n = numbers of years
|
Years |
Population |
Increment |
Geometric Increase |
|
1 |
6000 |
|
|
|
2 |
8000 |
2000 |
2000/6000 = 0.333 |
|
3 |
10000 |
2000 |
2000 / 8000 = 0.25 |
\(\text{r}=\sqrt{{{\text{r}}_{1}}\times {{\text{r}}_{2}}}\)
\(=\sqrt{0.33\times 0.25}=0.2885\)
P4 = 10000 × (1 + 0.2885)1 = 12885
∴ The population of the city in the fourth continuous year will be 12885.
Last updated on May 28, 2025
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