The mean of a, b, c, d and e is 28. The mean of a, c, e is 24. The mean of b and d is

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This question was previously asked in

Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)

Answer 1

Calculations:

The mean of a, b, c, d, and e is 28, and the mean of a, c, and e is 24, we can find the mean of b and d.

The mean of a, b, c, d, and e is (a + b + c + d + e) / 5 = 28.

The mean of a, c, and e is (a + c + e) / 3 = 24.

Now, let's subtract the mean of a, c, and e from the mean of all five to find the mean of b and d:

(a + b + c + d + e) = 28 × 5 = 140 [(a + c + e) = 24 × 3 = 72

140 - 72 = 68 = (b + d)

68/2 = 34 = (b + d)/2

So, the mean of b and d is 34.

Hence, The Correct Answer 34.

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