Question
Download Solution PDFThe maximum permissible limit of total hardness present in drinking water in the absence of alternate source of water, as per IS 10500 - 2012 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
As per IS 10500: 2012, the following are the various permissible limits for different parameters:
|
Parameters |
Acceptable Limit |
Permissible limit in absence of alternate source. |
|
Total suspended solids |
500 |
2000 |
|
Turbidity (NTU) |
1 |
5 |
|
Colour (TCU) |
5 |
15 |
|
Taste & odour (TON) |
1 |
3 |
|
Total dissolved solids (mg) |
500 |
2000 |
|
Alkalinity |
200 |
600 |
|
pH |
7 – 8.5 |
< 6.5 & > 9.2 |
|
Hardness (mg/L) |
200 |
600 |
|
Chloride content (mg/L) |
250 |
1000 |
|
Free ammonia (mg/L) |
0.15 |
0.15 |
|
Nitrate (mg/L) |
45 |
No relaxation |
|
Fluoride content (mg/L) |
1 |
1.5 |
|
lron as Fe (mg/L), max |
0.3 |
No relaxation |
|
Sulphate (mg/L) |
200 |
400 |
|
Calcium (mg/L) |
75 |
200 |
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