The marked price of a water bottle is Rs.950. A man bought the same for Rs.740, after getting two successive discounts. If the first discount is 12%, then what is the second discount?

Given:

Marked Price (MP) = ₹950

Selling Price (SP) = ₹740

First discount (D₁) = 12%

Second discount (D₂) = ?

Formula Used:

Price after first discount = MP - (D₁% of MP)

SP = Price after first discount - (D₂% of Price after first discount)

Calculation:

Price after the first discount = 950 - (12% of 950)

Price after the first discount = 950 - (0.12 × 950)

Price after the first discount = 950 - 114

Price after the first discount = ₹836

Now, the second discount is applied on this price to get the selling price of ₹740.

Let the second discount be x%.

740 = 836 - (x% of 836)

740 = 836 - \(\frac{x}{100} \times 836\)

836 × \(\frac{x}{100}\) = 836 - 740

836 × \(\frac{x}{100}\) = 96

x = \(\frac{96 \times 100}{836}\)

x = \(\frac{9600}{836}\)

x = 11.48325...

Rounding off to two decimal places, the second discount is 11.48%.

The second discount is 11.48%.