Question
Download Solution PDFThe junction capacitance of a p-n junction depends on
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFA diode can have two different capacitances namely Junction capacitance and diffusion capacitance.
Junction Capacitance:
It is dominant when the diode is reverse biased and is the result of the charge stored in the Depletion layer.
The junction capacitance is given by the formula:
\({C_j} = \frac{{A\epsilon}}{W}\) ---(1)
W = Width of the depletion region calculated as:
\(W= \sqrt {\frac{{2\epsilon_s(V_{bi}-V_a)(N_a+N_d)}}{N_aN_d}} \) ---(2)
Va = Applied Voltage
Na and Nd are the acceptor and donor doping concentrations respectively.
Substituting the above in Equation (1), we get:
\(C=\frac{A\epsilon}{ \sqrt {\frac{{2\epsilon_s(V_{bi}-V_a)(N_a+N_d)}}{N_aN_d}} }\)
\(C=\sqrt {\frac{{{A^2\epsilon_s}{N_A}{N_D}}}{{2\left( {{V_{bi}} - {V_a}} \right)\left( {{N_A} + {N_D}} \right)}}} \)
∴ The junction capacitance of a p-n junction depends on both the doping concentration and the applied voltage.
Diffusion Capacitance:
It is dominant when the diode is forward and is the result of storage charges when forward biased.
The diffusion capacitance is given by the formula:
\({C_d} = \frac{{{I_{DQ}}\times\tau }}{{η {V_T}}}\)
IDQ = Quiescent current of the diode.
τ = Minority carrier lifetime
VT = Thermal voltage
η = Constant = 2 for silicon and 1 for germanium
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