The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is:

Question

Question

Answer 1

Concept:

The amount of electrical energy transferred to an appliance depends on its power and the duration of time it is used.

Electrical energy is measured in kilowatt-hours, kWh. One unit is 1 kWh.

Electrical energy transferred is given as,

E = P × t

Where, P is the power in kilowatts (kW), T is the time in hours (h)

Calculation:

Given,

Power, P = 100 kW

Time, t = 1 hour

∴ E = P × t = 100 × 1 = 100 kWh

E = 100 × 3.6 × 10⁶ J = 36 × 10^{7 J (∵ 1 kWh = 3.6 × 10⁶ J)}

Hence, option (2) is the correct answer.