The direction ratios of a line are (1, -3, 2). Its direction cosines will be:

  1. (1, -3, 2)
  2. (-1, 3, -2)
  3. \(\displaystyle \rm\left({1\over\sqrt{14}},{-3\over\sqrt{14}},{2\over\sqrt{14}}\right)\)
  4. \(\displaystyle\rm\left({-1\over\sqrt{14}},{3\over\sqrt{14}},{-2\over\sqrt{14}}\right)\)

Answer (Detailed Solution Below)

Option 3 : \(\displaystyle \rm\left({1\over\sqrt{14}},{-3\over\sqrt{14}},{2\over\sqrt{14}}\right)\)
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Detailed Solution

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Concept:

If the direction ratios of a line are (l, m, n), then its direction cosines are

 \(\rm\displaystyle\left({l\over\sqrt{l^2+m^2+n^2}},{m\over\sqrt{l^2+m^2+n^2}},{n\over\sqrt{l^2+m^2+n^2}}\right)\).

Calculation:

Using the formula for direction cosines from direction ratios, the required direction cosines are:

\(\displaystyle\rm\left({1\over\sqrt{1^2+(-3)^2+2^2}},{-3\over\sqrt{1^2+(-3)^2+2^2}},{2\over\sqrt{1^2+(-3)^2+2^2}}\right)\)

\(\displaystyle\rm\left({1\over\sqrt{14}},{-3\over\sqrt{14}},{2\over\sqrt{14}}\right)\).

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