The compensator required to improve the steady state response of a system is

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  1. Lag 
  2. Lead
  3. Lag-lead
  4. Zero

Answer (Detailed Solution Below)

Option 1 : Lag 
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Lag compensator:

Transfer function:

If it is in the form of \(\frac{{1 + aTs}}{{1 + Ts}}\), then a < 1

If it is in the form of \(\frac{{s + a}}{{s + b}}\), then a > b

Maximum phase lag frequency:

\({\omega _m} = \frac{1}{{T\sqrt a }}\)

Maximum phase lag::

\({\phi _m} = {\sin ^{ - 1}}\left( {\frac{{a - 1}}{{a + 1}}} \right)\)

ϕis negative

Pole zero plot:

F1 U.B Madhu 2.12.19 D1

The pole is nearer to the origin.

Filter: It is a low pass filter (LPF)

Effect on the system:

  • Rise time and settling time increases and Bandwidth decreases
  • The transient response becomes slower
  • The steady-state response is improved
  • Stability decreases

26 June 1

Lead compensator:

Transfer function:

If it is in the form of \(\frac{{1 + aTs}}{{1 + Ts}}\), then a > 1

If it is in the form of \(\frac{{s + a}}{{s + b}}\), then a < b

Maximum phase lead frequency:

\({\omega _m} = \frac{1}{{T\sqrt a }}\)

Maximum phase lead:

\({\phi _m} = {\sin ^{ - 1}}\left( {\frac{{a - 1}}{{a + 1}}} \right)\)

ϕis positive

Pole zero plot:

F1 U.B Madhu 2.12.19 D16

The zero is nearer to the origin.

Filter: It is a high pass filter (HPF)

Effect on the system:

  • Rise time and settling time decreases and Bandwidth increases
  • The transient response becomes faster
  • The steady-state response is not affected
  • Improves the stability
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