The area of a rhombus shaped field is 5544 m2 and the length of one of its diagonals is 72 m. What will be the perimeter of the field (in m)?

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  1. 380
  2. 300
  3. 340
  4. 320

Answer (Detailed Solution Below)

Option 3 : 340
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Detailed Solution

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Given : 

Area of Rhombus = 5544 m2

One of its diagonal = 72 m

Formula Used : 

Area of Rhombus = 1/2 × D1 × D2

Calculation : 

According to question,

⇒ 5544 = 1/2 × 72 × D2

⇒ D2 = 154

Now,  D2/2 = 77, D1/2 = 36

Now by using Pythagoras theorem,
F2 Vinanti Engineering 13.09.23 D2

⇒ AD2 = 772 + 362 = 1296 + 5929 = 7225

⇒ AD = √7225 = 85 m 

Perimeter = 4 × 85 = 340 m

∴ The correct answer is 340 m.

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