Question
Download Solution PDFTension in the tight side of a belt drive is 100 N and that in the slack side 60 N. If the belt breadth is 10 cm and thickness 4 cm, what is the maximum stress induced in the belt?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Maximum stress will be on tight side of belt.
\(\sigma _{max}=\frac{T_{max}}{Cross-section ~area~of~belt}=\frac{T_{tight~side}}{Cross-section~area ~of~belt}\)
Calculation:
Given:
Ttight side = 100 N, Breadth (w) = 10 cm, Thickness (t) = 4 cm
\(\sigma _{max}=\frac{T_{max}}{Cross-section ~area~of~belt}=\frac{T_{tight~side}}{Cross-section~area ~of~belt}\)
\(\sigma_{max}=\frac{100}{10\times 4}=2.5 \frac{N}{cm^2}\)
Last updated on Aug 1, 2024
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