Question
Download Solution PDFSooraj is three times as old as his son Arjun. After 8 years, he would be two and a half times of Arjun’s age. After another 8 years, he would be _____ times Arjun’s age.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFLet the age of Sooraj be x years and of Arjun be y years.
⇒ x = 3y ----(1)
After 8 years,
⇒ x + 8 = (5/2) (y + 8)
⇒ 2x + 16 = 5y + 40
putting the value of x from eq (1)
⇒ 2 × 3y + 16 = 5y + 40
⇒ 6y + 16 = 5y + 40
⇒ y = 24 ----(2)
Solving Equation (1) and (2), we get:
⇒ x = 72 and y = 24
After another 8 years, the age of Sooraj = (72 + 8 + 8) = 88 years
The age of Arjun = (24 + 8 + 8) = 40 years
As per question,
Suraj age / Arjun age = 88/40
⇒ 2 × 8/40
⇒ \(2\frac{1}{5}\)
∴ After another 8 years, Sooraj would be \(2\frac{1}{5}\) times Arjun’s age.
Confusion Points Here in question it is given after 8 years ,that means first from current age we need to add 8 years and after that 8 years from then is added, so total 16 years.
Last updated on Jun 2, 2025
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