Simplify the expression (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22).

This question was previously asked in
SSC Selection Post 2024 (Graduate Level) Official Paper (Held On: 20 Jun, 2024 Shift 3)
View all SSC Selection Post Papers >
  1. 0.035
  2. 0.027
  3. 0.019
  4. 0.053

Answer (Detailed Solution Below)

Option 3 : 0.019
Free
English Language (Matric Level) Sectional Test - 01
11.9 K Users
25 Questions 50 Marks 12 Mins

Detailed Solution

Download Solution PDF

Given:

Simplify the expression (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22).

Formula Used:

Use basic arithmetic operations and algebraic identities:

(a - b)(a2 + ab + b2) = a3 - b3

Calculation:

Given expression: (0.3 - 0.2) (0.32 + 0.3 × 0.2 + 0.22)

First, simplify the inner expression:

0.32 + 0.3 × 0.2 + 0.22

0.09 + 0.06 + 0.04

0.19

Now, simplify the outer expression:

(0.3 - 0.2) × 0.19

0.1 × 0.19

⇒ 0.019

The correct answer is option 3.

Latest SSC Selection Post Updates

Last updated on Jun 3, 2025

-> The Staff Selection Commission has officially released the SSC Selection Post Phase 13 Notification 2025 on its official website at ssc.gov.in.

-> A total number of 2423 Vacancies have been announced for various selection posts under Government of India.

-> The Computer Based Exam is scheduled from 24th July to 4th August, 2025. Candidates will be able to apply online from 2nd June 2025 to 23rd June 2025.

->  The SSC Selection Post Phase 13 exam is conducted for recruitment to posts of Matriculation, Higher Secondary, and Graduate Levels.

-> The selection process includes a CBT and Document Verification.

-> Some of the posts offered through this exam include Laboratory Assistant, Deputy Ranger, Upper Division Clerk (UDC), and more. 

-> Enhance your exam preparation with the SSC Selection Post Previous Year Papers & SSC Selection Post Mock Tests for practice & revision.

Get Free Access Now
Hot Links: teen patti - 3patti cards game downloadable content teen patti gold download apk teen patti master list teen patti flush