Question
Download Solution PDFदिलेल्या आकृतीमध्ये, ABCD हा समांतरभुज चौकोन आहे ज्यामध्ये ∠DCB = 85° आणि ∠ADB = 55° तर, ∠ABD = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
∠DCB = 85°
∠ADB = 55°
वापरलेली संकल्पना:
समांतरभुज चौकोनामध्ये, विरुद्ध कोन समान असतात आणि विरुद्ध बाजू समांतर असतात
त्रिकोणाच्या सर्व कोनांची बेरीज 180° आहे
गणना:
समांतरभुज चौकोनाचे विरुद्ध कोन
⇒ ∠DCB = ∠DAB
⇒ ∠DAB = 85°
त्रिकोणाच्या कोनांची बेरीज = ∠ABD + ∠ADB + ∠DAB
⇒ ∠ABD + 55° + 85° = 180°
⇒ ∠ABD = 180° - 140°
⇒ ∠ABD = 40°
∴ ABD चे मूल्य 40° आहे
Last updated on Apr 30, 2025
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