Question
Download Solution PDFजर पहिली टर्म 125 असेल आणि सामान्य गुणोत्तर 2/5 असेल, तर GP ची चौथी टर्म किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
जर a, ar, ar 2 , ar 3 ,.....,ar n-1 GP मध्ये असतील तर GP ची nवी टर्म द्वारे दिली जाते
T n = ar n-1
दिले:
प्रथम पद a = 125
सामान्य प्रमाण r = 2/5
टर्म n = 4 व्या
गणना:
⇒ T n = ar n-1
⇒ T 4 = 125 x (2/5) 4-1
⇒ T 4 = 125 x (२/५) ३
⇒ T 4 = 125 x (८/१२५)
⇒ T 4 = 8
त्यामुळे G चा 4 था पद "8" आहे.
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