समद्विभुज त्रिकोणाचे क्षेत्रफळ शोधा ज्याचा पाया 54 सेमी लांब आहे आणि प्रत्येक समान बाजू 45 सेमी लांब किती आहे?

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RRB NTPC CBT 2 Level -4 Official paper (Held On: 10 May 2022 Shift 1)
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  1. 1944 चौरस सेमी
  2. 1215 चौरस सेमी
  3. 972 चौरस सेमी
  4. 1620 चौरस सेमी

Answer (Detailed Solution Below)

Option 3 : 972 चौरस सेमी
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Detailed Solution

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दिलेले आहे:

समद्विभुज त्रिकोणाचे क्षेत्रफळ ज्याचा पाया 54 सेमी लांब आहे आणि प्रत्येक समान बाजू 45 सेमी लांब आहे.

वापरलेला सूत्र:

समद्विभुज त्रिकोणाचे क्षेत्रफळ = 1/2 × b × √a2 – (b/2)2

गणना:

समद्विभुज त्रिकोणाच्या समान बाजू अनुक्रमे a सेमी आणि पाया b सेमी आहे असे समजा

प्रश्नानुसार

समद्विभुज त्रिकोणाचे क्षेत्रफळ = 1/2 × b × √[a2 – (b/2)2]

⇒ 1/2 × 54 × √[452 – (54/2)2]

⇒ 27 × √2025 – (27)2

⇒ 27 × √(2025 – 729)

⇒ 27 × √1296

⇒ (27 × 36) सेमी2

⇒ 972 सेमी2

आवश्यक क्षेत्र 972 चौरस सेमी आहे

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